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[Core 4] 3D Coordinate Geometry

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Zacken
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Original post by old_engineer

AB⃗=(6+3u6−4u−1)−(66−1)=(3u4u−1)\vec{AB}=\begin{pmatrix} 6+3u\\6-4u\\-1\end{pmatrix}-\begin{pmatrix} 6\\6\\-1\end{pmatrix}=\begin{pmatrix} 3u\\4u\\-1\end{pmatrix}



Slight error at the end. :smile:
Original post by Zacken
Slight error at the end. :smile:


Yep, spotted that myself but couldn't correct it at the time as the Edit button had gone awol. Now corrected (I think). Thank you for the alert.

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