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1. (Original post by betapro)
Yes for 2 i got 6) so L=1 and not a clue how to do 4
Just by looking at Q4 I'd say I would test a base case of before evaluating what happens as as see if the inequality still holds, examining closely the denominators if two things tend to the same thing. Just a thought though.
2. For problem 4 i got my ansdwer as (a) is correct
3. (Original post by betapro)
Found values for which absolute values vanish and split into three intervals and then tested each one
I got a different result when x is less than -1/2.
4. (Original post by betapro)
For problem 4 i got my ansdwer as (a) is correct
What was wrong with (e)?
5. (Original post by EricPiphany)
What was wrong with (e)?
For e i agree with first step but i dont get how u get that to 1
6. (Original post by EricPiphany)
I got a different result when x is less than -1/2.
Could you send screenshot of working to see where i went wrong? ty <3
7. (Original post by betapro)
For e i agree with first step but i dont get how u get that to 1
You can always use a little cheeky algebra
8. (Original post by betapro)
Could you send screenshot of working to see where i went wrong? ty <3
For , both , so LHS is ...
Unless I've done something really dumb somewhere...
9. (Original post by EricPiphany)
For , both , so LHS is ...
Unless I've done something really dumb somewhere...
Right yea ur right so if you would say that the answer is 6?
10. (Original post by EricPiphany)
You can always use a little cheeky algebra
Can u show me this hidden magic of algebra xD
11. (Original post by betapro)
Right yea ur right so if you would say that the answer is 6?
I'll let you decide on that one...
12. (Original post by EricPiphany)
I'll let you decide on that one...
Well for most right interval u get -2 less than equal to 2 so u take that to be right, and from previous working we know that -infinity to -0.5 is right and also the interval between -0.5 and half is also right then yes? A confirmation would be great
13. (Original post by betapro)
Can u show me this hidden magic of algebra xD
consider ...
or simply multiply by the denominator...
14. (Original post by betapro)
Well for most right interval u get -2 less than equal to 2 so u take that to be right, and from previous working we know that -infinity to -0.5 is right and also the interval between -0.5 and half is also right then yes? A confirmation would be great
https://www.desmos.com/calculator/7scpx7ack1
15. Graph doesnt break or anything so i see why its -infitinty to positive infinity thanks. Still requiring some further assistance with that question 4 with the getting to one situation xD
16. (Original post by betapro)
Graph doesnt break or anything so i see why its -infitinty to positive infinity thanks. Still requiring some further assistance with that question 4 with the getting to one situation xD
(Original post by EricPiphany)
consider ...
or simply multiply by the denominator...
is clearly less than 1, so ...
17. (Original post by EricPiphany)
is clearly less than 1, so ...
Yea see what u mean but surely it could never be 1, or is that just the notation you are meant to use?
18. (Original post by betapro)
Yea see what u mean but surely it could never be 1, or is that just the notation you are meant to use?
means less than or equal to.
It is true if or or both.

so if then
19. (Original post by EricPiphany)
means less than or equal to.
It is true if or or both.

so if then
Derp yea...

q1-3
q2-6
q3-4
q4-2
q5-2
q6-6

Also is there a way i can give u rating? <3
20. (Original post by betapro)
Derp yea...

q1-3
q2-6
q3-4
q4-2
q5-2
q6-6

Also is there a way i can give u rating? <3
i can't confirm them

and not really, but you can click the green thumbs up under a post by me

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