thanks for all the help guys, hopefully I'll understand it more when we cover orbitals in class?? aha(Original post by CheeseIsVeg)
You are along the right lines.
So Aluminium has 13 electrons
These lie in the 1s2 2s2 2p6 3s2 3p1 sub shells
the question ends in 3s1
I have bolded where 3s1 is in aluminium's full electronic configuration
How many ionisations is this?Well 3p1 = 1, to get to 3s1 we then knock off another electron, therefore it would be 2nd ionisation (2 electrons lost )
Should I still go?