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    I hate C4!
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    (Original post by bbadonde2)
    I hate C4!
    I hate s1 even more...its so ****ing tedious! :mad:

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    (Original post by Gilo98)
    I hate s1 even more...its so ****ing tedious! :mad:

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    Oh I did it last year and understand your frustrations! I think I only properly got it like 2 weeks before the exams, just hammer the past papers
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    (Original post by bbadonde2)
    Oh I did it last year and understand your frustrations! I think I only properly got it like 2 weeks before the exams, just hammer the past papers
    That's my plan....I'm way too disinterested to actually understand what I'm doing when I answer questions - just going to chug through the formulas and learn answers :ahee:
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    Tbh i loved s1 just because it was so easy

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    Attachment 394933Attachment 394935


    For question C, why does the limits switch round?



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    (Original post by lam12)
    Attachment 394933Attachment 394935


    For question C, why does the limits switch round?



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    If you have a negative integral, you can switch the limits around to get rid of the minus sign
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    I've just done the june 14 paper and did pretty well apart from the last part of the vector question. I've done past papers chronologically and seem to have noticed that the vector questions are getting more obscure. Like I think have decent undrestanding of vectors but seem to trip up on more obscure questions. Anyone know a resource with difficult/obscure vector Qs to practice. Or even any tips on better understanding vectors. I also seem to muck up my diagrams maybe that's because I have messy working.
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    (Original post by H0PEL3SS)
    If you have a negative integral, you can switch the limits around to get rid of the minus sign
    You learn something new every day haha, Thanks :-)


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    Hi, can someone please help me do question (d). I've tried it multiple times but can't get to the answer shown in the book.
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    (Original post by Kira Yagami)
    Hi, can someone please help me do question (d). I've tried it multiple times but can't get to the answer shown in the book.
    I've just completed it, may I ask how far you got, because I think I may know where you went wrong.
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    (Original post by randlemcmurphy)
    I've just completed it, may I ask how far you got, because I think I may know where you went wrong.
    Is the answer u-1/4u^2+c

    I just done that in 2 mins, is that right ?

    been practicing integration all day hope it is
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    [QUOTE=randlemcmurphy;55630055]I've just completed it, may I ask how far you got, because I think I may know where you went wrong



    Hi, thanks for the reply. This is the answer. I managed to get the ln term but not the root x^2 +4 part. I don't know where I went wrong.



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    (Original post by ThePrestigeUK)
    Is the answer u-1/4u^2+c

    I just done that in 2 mins, is that right ?

    been practicing integration all day hope it is
    Hi, just posted the answer. The answer substitutes back in for u. i don't think the your answer is correct.

    I've been practicing all day too. Just can't seem to get this answer!
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    Just did the above and I think people are going wrong by not being able to rearrange for the desired result.
    Not that integrals in the form 1/x^2-a^2 are in the formula book. Using this does the question in a couple of minutes.


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    (Original post by Kira Yagami)
    Hi, just posted the answer. The answer substitutes back in for u. i don't think the your answer is correct.

    I've been practicing all day too. Just can't seem to get this answer!
    (Original post by ThePrestigeUK)
    Is the answer u-1/4u^2+c

    I just done that in 2 mins, is that right ?

    been practicing integration all day hope it is
    I will post my solution with working out in a little bit. On the other hand you could check out the worked solution in the Ch6 Solution Bank here. (solution on page 42)
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    Name:  ImageUploadedByStudent Room1431292125.109219.jpg
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    Can someone help me with part e and also label on the t values on the graph????


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    (Original post by Medicjug)
    Name:  ImageUploadedByStudent Room1431292125.109219.jpg
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    Can someone help me with part e and also label on the t values on the graph????


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    y=sin2t=2sintcost
    Then if x=cost use an identity to find sin


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    (Original post by physicsmaths)
    y=sin2t=2sintcost
    Then if x=cost use an identity to find sin


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    Yup did that to get the Cartesian form but really confused on part e


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    (Original post by Medicjug)
    Yup did that to get the Cartesian form but really confused on part e


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    You can take a positive or negative square root. :ahee:

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