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    (Original post by Khoinet)
    73.3 is right but 10.44 is wrong
    is 10.4 right ? are you talking about the value being wrong or sig figs
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    (Original post by Squishy•)
    Do errors get carried forward? Like I used 0.x instead of X for a calculation and it changed all my answers up
    Yes you will probably get the method marks.
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    (Original post by linaxq)
    so 73.3 and 10.44 no marks?
    73.3 was right -- that's 3sf.

    Which question was 10.44? You may only lose 1 mark if it involved g
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    (Original post by linaxq)
    is 10.4 right ? are you talking about the value being wrong or sig figs
    10.4 is right but 10.44 is wrong if you leave it at 4 s.f
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    How do you find lambda?
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    (Original post by SHJBHB)
    For Q4a) I got the 0.8299 but managed to round it to 0.823 so will I just lose the 1 accuracy mark or will they see the 0.8299 and not look past it as it's the correct answer
    I'm not entirely sure, I'd guess -1A though.
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    (Original post by Khoinet)
    10.4 is right but 10.44 is wrong if you leave it at 4 s.f
    cant remember if i did 10.44 or 10.4 i might of left it has square root of 109
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    for question 1b how many marks would be lost for integrating with limits 0 and 3.
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    (Original post by Rgrewall)
    Didnt it say "in the third second" hence implying the integral had limits 4,3
    No, third second implies between t=2 and t=3
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    (Original post by Lilylollydove7)
    Did anyone else get 1.22 as their distance for the centre of mass?
    Wasn't it from O, as you're removing the triangle, it'd be larger than 3sqrt(2)/2
    because it shifts closer to the shape you have left.
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    (Original post by linaxq)
    cant remember if i did 10.44 or 10.4 i might of left it has square root of 109
    Well it really depend on the examiner and ms. If you lucky its still correct so, only 1 mark gone its fine
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    (Original post by Jakester11)
    How do you find lambda?
    suvat

    horizontal: s=lambda
    vertixcal: s=-lamda

    Fill in the other knowns, find t in terms of lambda using the horizontal (t=1/3 lambda) and then solve substituting this into s=ut+1/2 at^2 with the vertical values
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    (Original post by Jakester11)
    How do you find lambda?
    Equal the x distance to the negative of the y distance, solver for T, sub T back in to one of them.
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    (Original post by cjlh)
    73.3 was right -- that's 3sf.

    Which question was 10.44? You may only lose 1 mark if it involved g
    The calculation was square root of (10^2 + 3^2) to get square root 109 which iwas 10.44 and so on.

    To get 10 i had to use g but to find 10.44 was a matter of pythagoras
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    (Original post by kingaaran)
    Yeah I got this too - you're right
    I did that too but it's actually wrong... 3rd second is from 2 to 3
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    (Original post by Khoinet)
    Well it really depend on the examiner and ms. If you lucky its still correct so, only 1 mark gone its fine
    When using gravity, they always penalise for 4SF or more.
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    (Original post by Major-fury)
    for question 1b how many marks would be lost for integrating with limits 0 and 3.
    i want to know this too
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    (Original post by linaxq)
    The calculation was square root of (10^2 + 3^2) to get square root 109 which iwas 10.44 and so on.

    To get 10 i had to use g but to find 10.44 was a matter of pythagoras
    Ohh yeah I see. That could go either way to be honest. Bit better than me, I forgot to square root 109 hahaha
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    (Original post by Nesquickforce)
    No, third second implies between t=2 and t=3
    How many marks do you think I'd get for putting in the wrong limits? 3 and 4 (it was 5 marks)
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    (Original post by Major-fury)
    for question 1b how many marks would be lost for integrating with limits 0 and 3.
    The question was 6 mars so I 'd say you got 3 and lost 3.
 
 
 
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