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# M1 OCR (Not MEI) Exam - 9/06/2015 watch

1. (Original post by olliecass1)
questions 5 im pretty sure is wrong as it can also accelerate upwards
But the weight of the particle was far more than 1.2N, so there would never be any upward acceleration
2. yeh that's what I got . How is it 9.74?
3. That paper was amazing

28
6.38
0.598
6
0.2
5
7
50
9.74, 35.4 deg
?
?
1.04
1.06
0
0
68
78
132
7
Proof done with calculator
1.26
-3.15
0.525
0.735
5. (Original post by olliecass1)
im pretty sure your q 5s are wrong as it can also accelerate upwards
The maximum upward force was 1.2N, and the weight was 0.4g = 3.92, so weight is always greater and so it never accelerates upwards.
6. (Original post by olliecass1)
im pretty sure your q 5s are wrong as it can also accelerate upwards
I dont think so cause the resultant force was towards the surface
7. (Original post by wat a wizard)
I did that too, did you get 13.3 ish?
Yeah
Than I used tan = O/A for the angle??
8. I got k as 96 and for 6i) I got 32. Anyone agree?
9. (Original post by mechanicsonejune)

28
6.38
0.598
6
0.2
5
7
50
9.74, 35.4 deg
?
?
1.04
1.06
0
0
68
78
132
7
Proof done with calculator
1.26
-3.15
0.525
0.735
I got different answers for question 7 iirc. Think T was 1.2 for me? (Instead of 0.525)
10. A lot of m friends are saying that the 1.2 force was pushing down onto the block. I thought it was pulling
11. (Original post by mechanicsonejune)

28
6.38
0.598
6
0.2
5
7
50
9.74, 35.4 deg
?
?
1.04
1.06
0
0
68
78
132
7
Proof done with calculator
1.26
-3.15
0.525
0.735
Agree with you there. The ones that stumped you got me too
12. (Original post by Mattniemier)
I dont think so cause the resultant force was towards the surface
I got an upwards acceleration of 1.2/mass because the weight and reaction cancelled out and then there was 1.2 left??
13. (Original post by olliecass1)
im pretty sure your q 5s are wrong as it can also accelerate upwards
What everyone else said about the weight is correct, it wouldn't accelerate up.
14. (Original post by smoothER)
Yeah
Than I used tan = O/A for the angle??
I think iused the sine rule to get 36 or 37
15. Why would the acceleration = 0 for questions 5iii and 5iv??
16. (Original post by xsanda)
Xsanda's solutions:

Falling question
1i) v=28 [2]
1ii) s=6.384 [2]
1iii) t=0.598 [3]

Collision question
2i) u=6 [4]
2ii) m=0.2 [4]

Cycling question
3i) 20km, 5hrs [3]
3ii) 7 hrs [3]
3iii) 50km [2]

110° tick
4i) 9.74N, 35.4° [6]
4ii) 10.3N [1]
4iii) 54.6° [2]

θ force
5i) 1.04 [3]
5ii) 1.06 [3]
5iii) a=0 [3]
5iv) a=0 [2]

Coalescing
6i) v=68 [4]
6ii) s=78 [4]
6iii) k=132 [1]
6iv) v=7 [5]

Prism
7i) a=0.7 (show that), T=1.68 [5]
7ii) v=1.26 [2]
7iii) -a = 0.9 [2]
7iva) T=1.2 [3]
7ivb) Fr = 1.12 [3]
Got all of them apart from 5)iii and 5)iv). How come they were both 0 :/
17. (Original post by mechanicsonejune)

28
6.38
0.598
6
0.2
5
7
50
9.74, 35.4 deg
?
?
1.04
1.06
0
0
68
78
132
7
Proof done with calculator
1.26
-3.15
0.525
0.735
I disagree on the question 7, here are my solutions:

(Original post by xsanda)
Xsanda's solutions:
Falling question
1i) v=28 [2]
1ii) s=6.384 [2]
1iii) t=0.598 [3]

Collision question
2i) u=6 [4]
2ii) m=0.2 [4]

Cycling question
3i) 20km, 5hrs [3]
3ii) 7 hrs [3]
3iii) 50km [2]

110° tick
4i) 9.74N, 35.4° [6]
4ii) 10.3N [1]
4iii) 54.6° [2]

θ force
5i) 1.04 [3]
5ii) 1.06 [3]
5iii) a=0 [3]
5iv) a=0 [2]

Coalescing
6i) v=68 [4]
6ii) s=78 [4]
6iii) k=132 [1]
6iv) v=7 [5]

Prism
7i) a=0.7 (show that), T=1.68 [5]
7ii) v=1.26 [2]
7iii) -a = 0.9 [2]
7iva) T=1.2 [3]
7ivb) Fr = 1.12 [3]
18. S un
U 1.26
V 0
A
T 0.4

v = u+at
v/t - u/t = a
a = -3.15

everyone seems to have gotten a different answer and i've got a feeling that i used the wrong value for time
19. (Original post by xsanda)
I disagree on the question 7, here are my solutions:
I agree on 7
20. (Original post by aliah4666)
Why would the acceleration = 0 for questions 5iii and 5iv??
^^^

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