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    (Original post by josephpryor)
    Can someone please confirm the LQ UQ?
    Uq 7.68
    Lq 3.68
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    the s1 paper today crushed my soul
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    (Original post by bob6969)
    YOUR BOI BOB6969 (hopefully correct) answers

    1i) IQR = 4 (or 4.15 depending on method) Median = 29
    ii) No outliers

    2i) 0.512
    ii) 0.16
    iii) 0.66 i think

    3i) 120
    ii) 1/60
    iii) 1/60
    iv) 0.1

    4i) 50k = 60 so k is 1.2
    ii) E(X) = 2.74 Var(X) = 1.232

    5i) 0.21
    ii) venn diagram
    iii) 0.241

    6i) mean = 70.19 s.d. = 36.90
    ii) 15.7%
    iii) histogram drawing
    iv) positive skew
    v) 20.2%
    vi) men shoes had smaller mean and lower spread

    7ai) 0.1423
    B) 0.2108
    C) 1.6
    ii) p=0.1 h1, p<0.1
    iii) Not writing it out
    iv) don't reject as 5.3% > 5% so insufficient evidence
    I got exactly the same answers for every question lol. Does it matter if I said women had higher average price and men had greater variation than women or do I need to use the word spread?
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    Don't think that's right, i got one in 30's one in late 20's
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    (Original post by Crozzer24)
    I got exactly the same answers for every question lol. Does it matter if I said women had higher average price and men had greater variation than women or do I need to use the word spread?
    Normally you would say the prices of the womens shoes were more consitent - there was more variation in the prices of mens shoes.
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    (Original post by josephpryor)
    Can someone please confirm the LQ UQ?
    Seems that IQR questions are very inconsistent but I ended up with IQR=4 LQ=27.8 UQ=31.8 after crossing out 4.15
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    That's the probability the team lost all three games, which is different than a team not winning all three games
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    (Original post by Crozzer24)
    Did anyone find 2i fairly long winded for 1 mark or have I done something wrong? I think I got 64/125 I can't quite remember
    Think I got this (0.512) but there were a few ways to do it... was it not just 0.8^3?
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    imgur. com/a/4iRS3
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    (Original post by Massoom)
    Think I got this (0.512) but there were a few ways to do it... was it not just 0.8^3?
    That's what I did
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    (Original post by Massoom)
    Think I got this (0.512) but there were a few ways to do it... was it not just 0.8^3?
    Lol yes that's why I got but I've gone about it a very long winded way
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    Low or high grade boundaries?
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    (Original post by Hiba.A)
    I got 0.66 for 2 (iii)
    SAME!
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    (Original post by Crozzer24)
    Lol yes that's why I got but I've gone about it a very long winded way

    Didnt it say the probability of not losing? doesnt that mean he can draw or win so wouldnt it be 1-(0.2^3) which was like 0.9 something
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    (Original post by reoshinwho)
    Low or high grade boundaries?
    I thought it was a challenging paper, the wordings were???
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    (Original post by meimaths123)
    Didnt it say the probability of not losing? doesnt that mean he can draw or win so wouldnt it be 1-(0.2^3) which was like 0.9 something
    No, since your method only works out the probability that they don't lose all 3 matches. You missed out the chance they could lose 1 or 2 matches
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    So when people did the quartile a for q1 what did you get, everyone seems to have a different answer?
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    (Original post by bob6969)
    YOUR BOI BOB6969 (hopefully correct) answers

    1i) IQR = 4 (or 4.15 depending on method) Median = 29
    ii) No outliers

    2i) 0.512
    ii) 0.16
    iii) 0.66 i think

    3i) 120
    ii) 1/60
    iii) 1/60
    iv) 0.1

    4i) 50k = 60 so k is 1.2
    ii) E(X) = 2.74 Var(X) = 1.232

    5i) 0.21
    ii) venn diagram
    iii) 0.241

    6i) mean = 70.19 s.d. = 36.90
    ii) 15.7%
    iii) histogram drawing
    iv) positive skew
    v) 20.2%
    vi) men shoes had smaller mean and lower spread

    7ai) 0.1423
    B) 0.2108
    C) 1.6
    ii) p=0.1 h1, p<0.1
    iii) Not writing it out
    iv) don't reject as 5.3% > 5% so insufficient evidence
    Isn't 7c)iv) significant because it's less than 10%?
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    (Original post by meimaths123)
    Didnt it say the probability of not losing? doesnt that mean he can draw or win so wouldnt it be 1-(0.2^3) which was like 0.9 something
    That's the probability of him losing all 3 games, you needed to minus the probability of losing just one game and two games and the various combinations
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    (Original post by robnaldom9)
    Isn't 7c)iv) significant because it's less than 10%?
    I think the significance level was 5%
 
 
 
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