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    (Original post by SamKeene)
    (assuming this isn't sarcasm)

    If the interval is [a,b], just calculate f(a) and f(b) and if there is a sign change, then there is a root in that interval.

    Easy few marks, just remember that
    LOL
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    (Original post by EnglishMuon)
    lol thanks, was sarcasm though did c3 last year. Just my version of humour
    Thought it might have been (see my edit).

    Good luck with whatever exams though
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    (Original post by IrrationalRoot)
    Seriously though they'd better make the C3 exam harder this year. Otherwise I'm protesting lol, literally same Qs different numbers every year. Well different numbers if you're lucky.
    nope. I believe the exams officer at my school is still the chief examiner for c3 (or c4 cant remember). I believe he is 50% potato 50% sick coloured wall paper and 100% chump so I wouldnt get ur hopes up.
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    (Original post by SamKeene)
    Thought it might have been (see my edit).

    Good luck with whatever exams though
    oh ok haha, thanks . Mainly step nowadays though
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    (Original post by EnglishMuon)
    nope. I believe the exams officer at my school is still the chief examiner for c3 (or c4 cant remember). I believe he is 50% potato 50% sick coloured wall paper and 100% chump so I wouldnt get ur hopes up.
    Damn haha, guess I'll have to memorise an interesting STEP Q beforehand and do that when I'm bored lol.
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    (Original post by IrrationalRoot)
    Damn haha, guess I'll have to memorise an interesting STEP Q beforehand and do that when I'm bored lol.
    Yea it actually kills time, I did that in c1 last year. probably spent more time on that q than on the actual paper
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    (Original post by EnglishMuon)
    Yea it actually kills time, I did that in c1 last year. probably spent more time on that q than on the actual paper
    You were doing STEP Qs last year too? Lol when I first sat C1 I didn't understand half the topics, half of my answers were just application of algorithms. Didn't even understand how completing the square worked XD.
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    (Original post by IrrationalRoot)
    You were doing STEP Qs last year too? Lol when I first sat C1 I didn't understand half the topics, half of my answers were just application of algorithms. Didn't even understand how completing the square worked XD.
    lol yea but it was only step I and i was pretty slow. probably wouldve only got a lowish 2 if id taken it last year.
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    done two mocks today can siklos claim me as sacrifice yet?
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    Is Grade 2 easy to achieve? I'm so nervous about the STEP II on the 16th ......panicking ...
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    Is S,S easy to achieve
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    (Original post by Number Nine)
    done two mocks today can siklos claim me as sacrifice yet?
    Nah he only sacrifices goats.

    That is if they've been tied to the side of a square barn of side length 2a.


    Posted from TSR Mobile
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    (Original post by Krollo)
    Nah he only sacrifices goats.

    That is if they've been tied to the side of a square barn of side length 2a.


    Posted from TSR Mobile
    feels like years since i did that question but it was only 4 months ago crikey
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    (Original post by betterthanbarbs)
    Is Grade 2 easy to achieve? I'm so nervous about the STEP II on the 16th ......panicking ...
    yes if you relax now you will not be as tense for the real exam

    (Original post by gasfxekl)
    Is S,S easy to achieve
    yes got it last week compelted it
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    Doing STEP II 2015 tomorrow, hope it goes well
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    Slightly regretting not applying to Trinity, who apparently only require a 1 in STEP I for CompSci with Maths. My life would be so chill without the horrors of STEP III (OTOH I'd then die from the maths tripos if I got in).
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    (Original post by Number Nine)
    yes got it last week compelted it
    lolwut

    (Original post by sweeneyrod)
    Slightly regretting not applying to Trinity, who apparently only require a 1 in STEP I for CompSci with Maths. My life would be so chill without the horrors of STEP III (OTOH I'd then die from the maths tripos if I got in).
    yeah and Trinity's crap soooo why would you want to apply there anyway?

    Spoiler:
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    get at me Trin-mos
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    Hello, could you please have a look since you are the only one i know who has done 2015 step 1, thank you
    Spoiler:
    Show
    For question 8,
    can i say as
    S=(n-(n-1))k +(n-(n-2))k+...+(n-1)k+(n-0)k
    so S+( (n-1)k+(n-2)k+...+1k+0k ) is divisible by n as proved at the start
    and ( (n-1)k+(n-2)k+...+1k+0k ) is S-nk
    therefore, 2S-nk is divisible by n
    so 2S is divisible by n

    and if n is odd, S has to be divisible by n because 2 is not a factor of n
    and if n is even, S then would be divisible by n/2

    I asked because I don't really understand what the markscheme is talking about :P
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    (Original post by charlielao)
    Hello, could you please have a look since you are the only one i know who has done 2015 step 1, thank you
    Spoiler:
    Show
    For question 8,
    can i say as
    S=(n-(n-1))k +(n-(n-2))k+...+(n-1)k+(n-0)k
    so S+( (n-1)k+(n-2)k+...+1k+0k ) is divisible by n as proved at the start
    and ( (n-1)k+(n-2)k+...+1k+0k ) is S-nk
    therefore, 2S-nk is divisible by n
    so 2S is divisible by n

    and if n is odd, S has to be divisible by n because 2 is not a factor of n
    and if n is even, S then would be divisible by n/2

    I asked because I don't really understand what the markscheme is talking about :P
    Zacken Renzhi10122 Krollo physicsmaths also have
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    (Original post by charlielao)
    Hello, could you please have a look since you are the only one i know who has done 2015 step 1, thank you
    Spoiler:
    Show
    For question 8,
    can i say as
    S=(n-(n-1))k +(n-(n-2))k+...+(n-1)k+(n-0)k
    so S+( (n-1)k+(n-2)k+...+1k+0k ) is divisible by n as proved at the start
    and ( (n-1)k+(n-2)k+...+1k+0k ) is S-nk
    therefore, 2S-nk is divisible by n
    so 2S is divisible by n

    and if n is odd, S has to be divisible by n because 2 is not a factor of n
    and if n is even, S then would be divisible by n/2

    I asked because I don't really understand what the markscheme is talking about :P
    This line requires parity considerations I believe.
    Reason being is you can't just arbitrarily pair off terms and use the proven result (ii). You need to consider how the terms pair off in the middle.
    That's why the ms approach was a bit more complicated.
 
 
 
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