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    (Original post by eggfriedrice)
    I got t=1 and two stationary points ._.
    As did I. All these conflicting answers! :confused:
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    (Original post by Dizzy in my Head)
    As did I. All these conflicting answers! :confused:
    Yeah, I plotted the graph and there are 2 stationary points. But why?
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    (Original post by Dizzy in my Head)
    As did I. All these conflicting answers! :confused:
    Let's be honest, no one knows what the ****'s happening or what they're talking about.
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    Can someone please answer this question.... when you had to integrate x^8 ln3x... i put ln3x as u and when you differentiate it, it simplifies to 1/x, but when 1/x is integrated you get lnx not ln3x why is that?
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    (Original post by eggfriedrice)
    I got t=1 and two stationary points ._.
    Same. So so worried now.
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    For t it was a cubic so I think it was just one stationary point...
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    (Original post by ihatepeople37)
    Can someone please answer this question.... when you had to integrate x^8 ln3x... i put ln3x as u and when you differentiate it, it simplifies to 1/x, but when 1/x is integrated you get lnx not ln3x why is that?
    It's because when you integrate, there's a constant. That constant will be ln(3).
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    Mr M, where art thou?

    Posted from TSR Mobile
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    Forgot to substitute u back in.... Same mistake every time
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    There are 3 stationary points because you cancelled cosx's and to do that you have to find the solution to cosx=0 i.e. x=pi/2
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    3) Skew
    4) (pi/2 ,1), (pi/6 , 3/2)
    5ii) 1/2 ln (root 13)
    cant remember the question: (0,3)

    Some of the answers i remember...
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    (Original post by Emmalacrosse)
    There are 3 stationary points because you cancelled cosx's and to do that you have to find the solution to cosx=0 i.e. x=pi/2
    Yeah see this is what I thought, but I plotted the graph on an online plotter and there's only two. Why is this?
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    (Original post by Vip3rgt9)
    It's because when you integrate, there's a constant. That constant will be ln(3).
    ok... still not 100% sure but there's nothing I can do now...could have done with 15 more mins
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    (Original post by ihatepeople37)
    Can someone please answer this question.... when you had to integrate x^8 ln3x... i put ln3x as u and when you differentiate it, it simplifies to 1/x, but when 1/x is integrated you get lnx not ln3x why is that?
    ln(3x)= ln3 + ln x. ln 3 is a constant and so differentiates to zero while lnx gives 1/x
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    (Original post by ihatepeople37)
    ok... still not 100% sure but there's nothing I can do now...could have done with 15 more mins
    It's ok though. You are right in thinking that it differentiated to 1/x.
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    How do you do the integral of tan2x question?
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    (Original post by Croydon'Stepper)
    Dont worry, so did I and most of my year. Just realised marks here and there missed too
    (Original post by Dizzy in my Head)
    No. I agree. I thought is was dreadful. :mad: I'm so angry with myself! I can't wait for someone to post an unofficial mark scheme.
    Phew.
    I'm so angry with myself too. I let myself down so much, I messed up just about every question in some way ... I'm just in a shocked state of horror atm
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    (Original post by SJ12345)
    ln(3x)= ln3 + ln x. ln 3 is a constant and so differentiates to zero while lnx gives 1/x
    oh okay.... i am such a nob
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    (Original post by SJ12345)
    How do you do the integral of tan2x question?
    Oh yeah, I messed up that question. Had a total mindblank.

    Somebody enlighten us?
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    Anyone got a rough idea on grade boundaries?
 
 
 
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