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    will these modules be continued next year?
    When will they introduce new syllabus??
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    (Original post by Ilovemaths96)
    Haha, differentiate is easy, use product rule,

    PsIf you wanted to integrate use parts so that 'u' = x from parts formula
    thank you
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    (Original post by SarahLund)
    thank you
    I just put the answer in your other thread
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    (Original post by TeeEm)
    I just put the answer in your other thread
    Hey TeeEm can you answer the question i asked about eigenvectors



    (Original post by chughes17)
    You can't use any other value for y and z, you can only do that when you have 3 comparative variables. When solving your 3 simultaneous equations,

    x+2z=x

    z can only be 0 when you solve by cancelling x's

    if you had x=2z and z=2y

    then you can set one to whatever you like and figure the other 2 out, but y and z can only take the value 0 in this case

    Posted from TSR MobileSo I have to look at the 3 simultaneous and decide what values i can use.

    The three equations given were :
    x + 2z = x
    4y + z = y
    5y = z

    But if it were like this: [situation 1]

    2z = 3x
    4y + z = y
    5y = z

    I could then use any value for x?

    What if it were like this : [situation 2]

    3x = 0
    4y + z + x = y
    5y = z

    Thanks for Help, this has confuse me for a long time
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    (Original post by ninjasinpjs)
    Hey TeeEm can you answer the question i asked about eigenvectors
    just woke up...
    for the next hour or so I am only capable of doing question involving the times tables.
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    (Original post by SarahLund)
    thank you
    no problem
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    (Original post by TeeEm)
    just woke up...
    for the next hour or so I am only capable of doing question involving the times tables.
    Hahaha, 😎 rough night? My brother is still sleep😙


    Posted from TSR Mobile
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    (Original post by ninjasinpjs)
    Hahaha, 😎 rough night? My brother is still sleep😙


    Posted from TSR Mobile
    night?

    I start work at 7 a.m. on Saturdays and finish at 14.00
    Then I sleep...
    Attached Images
     
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    (Original post by TeeEm)
    just woke up...
    for the next hour or so I am only capable of doing question involving the times tables.
    Ok I will edit my post, take a look at it when you are feeling better, its a 2 marker but i don"t get the concept again


    Posted from TSR Mobile
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    Hey TeeEm can you answer the question i asked about eigenvectors (2 C)

    (Original post by ninjasinpjs)
    Hey bro i had a bit of difficulty finding the eigenvector (1) because if any other value was used of y,z instead of x first you get a completely different vector, can you explain why?

    (Original post by chughes17)You can't use any other value for y and z, you can only do that when you have 3 comparative variables. When solving your 3 simultaneous equations,x+2z=xz can only be 0 when you solve by cancelling x'sif you had x=2z and z=2ythen you can set one to whatever you like and figure the other 2 out, but y and z can only take the value 0 in this case

    Posted from TSR Mobile

    So I have to look at the 3 simultaneous and decide what values i can use.

    The three equations given were :
    x + 2z = x
    4y + z = y
    5y = z

    But if it were like this: [situation 1]
    2z = 3x
    4y + z = y
    5y = z
    I could then use any value for x?

    What if it were like this : [situation 2]
    3x = 0
    4y + z + x = y
    5y = z

    Thanks for Help
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    Part C, after a bit of thought, i assumed that I can come up with 3 equation of planes.

    Where A , B , C would be the known point in each of the 3 equations with their respective direction vectors.

    So i wanted to ask if these vectors were on the same plane (co-planer), would it mean that there would only be 1 equation of the plane if i were find the equation of the plane for each of the 3 points for this new situation?

    Sorry if i'm posting a lot
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    the reduction questions are so weird, in june 2014 r, you can technically solve it without splitting it up/factorsing but you don't get the form they want, ugh so annoying you realise so late and waste so much time
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    when you have two plane equations (cartesian) and you have to find an intersecting point, do you always put x/y/z as zero? whenever i put then as 1 i always get the wrong answer, the markscheme always seems to show where one coordinate is zero, is this the way you do it all the time in you have 3 unknowns?
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    (Original post by mmms95)
    when you have two plane equations (cartesian) and you have to find an intersecting point, do you always put x/y/z as zero? whenever i put then as 1 i always get the wrong answer, the markscheme always seems to show where one coordinate is zero, is this the way you do it all the time in you have 3 unknowns?
    sorry bro, i don't understand what you are saying, can you show me example
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    (Original post by mmms95)
    when you have two plane equations (cartesian) and you have to find an intersecting point, do you always put x/y/z as zero? whenever i put then as 1 i always get the wrong answer, the markscheme always seems to show where one coordinate is zero, is this the way you do it all the time in you have 3 unknowns?
    you set any one of the three coordinates to any sensible number (zero is good).

    two planes cannot possibly intersect at one point, but along a line so the answer is not unique
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    (Original post by TeeEm)
    you set any one of the three coordinates to any sensible number (zero is good).

    two planes cannot possibly intersect at one point, but along a line so the answer is not unique
    (Original post by ninjasinpjs)
    sorry bro, i don't understand what you are saying, can you show me example
    sorry i meant interesting line, and then point for the line

    ahh okay, cause sometimes we have to use that answer in another part, i think i'll just use zero, thanks
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    (Original post by mmms95)
    sorry i meant interesting line, and then point for the line

    ahh okay, cause sometimes we have to use that answer in another part, i think i'll just use zero, thanks
    sure
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    (Original post by ninjasinpjs)
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    Part C, after a bit of thought, i assumed that I can come up with 3 equation of planes.

    Where A , B , C would be the known point in each of the 3 equations with their respective direction vectors.

    So i wanted to ask if these vectors were on the same plane (co-planer), would it mean that there would only be 1 equation of the plane if i were find the equation of the plane for each of the 3 points for this new situation?

    Sorry if i'm posting a lot
    if i understand what you mean, then i think the answer to your question is yes, if you use different point you still get the same equation of the plane, i.e. there is only one. try visualising it and you'll see there can only be one plane.
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    6D so the equation of the locus is y = 0

    As we vary theta the denominator(theta), the largest and smallest values we can have is x = +a or x = -a ; so shouldn't the inequality be -a </= x </= a.

    I know I'm wrong but, why did they use their inequality?
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    (Original post by ninjasinpjs)
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    6D so the equation of the locus is y = 0

    As we vary theta the denominator(theta), the largest and smallest values we can have is x = +a or x = -a ; so shouldn't the inequality be -a </= x </= a.

    I know I'm wrong but, why did they use their inequality?
    As the denominator gets smaller x gets larger; thus the largest denominator (in terms of magnitude) gives the smallest magnitude x values, hence |x| >/= a rather than the other way round
 
 
 
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