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# Edexcel A2 C4 Mathematics June 2015 - Official Thread watch

1. have any of you ever seen questions involving arc sin etc. in papers?
2. (Original post by knoxy.22)
have any of you ever seen questions involving arc sin etc. in papers?
I seen a question in a class test saying show that arcsinx+arccosx= something find the something

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3. (Original post by physicsmaths)
I seen a question in a class test saying show that arcsinx+arccosx= something find the something

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I never actually seen a question on it but guess ill just revise it in case , thanks anyway
4. (Original post by physicsmaths)
I seen a question in a class test saying show that arcsinx+arccosx= something find the something

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Jan 2007 Q8

http://www.mathsgeeks.co.uk/allpaper...celJan07QP.pdf

Basically, I thought cos y = sin (y+pi/2)

But when I use this, I get an incorrect answer

And also in review exercise of c3 book there is a question:

y= arcsin x

a) Express arccos x in terms of y
5. (Original post by Efemena15)

Jan 2007 Q8

http://www.mathsgeeks.co.uk/allpaper...celJan07QP.pdf

Basically, I thought cos y = sin (y+pi/2)

But when I use this, I get an incorrect answer

And also in review exercise of c3 book there is a question:

y= arcsin x

a) Express arccos x in terms of y
shouldnt it be cosy=sin(pi/2-y)
6. (Original post by Efemena15)

Jan 2007 Q8

http://www.mathsgeeks.co.uk/allpaper...celJan07QP.pdf

Basically, I thought cos y = sin (y+pi/2)

But when I use this, I get an incorrect answer

And also in review exercise of c3 book there is a question:

y= arcsin x

a) Express arccos x in terms of y
The ExamSolutions guy explains it really well.

http://www.examsolutions.net/a-level...uary/paper.php

EDIT: Alternatively here are the youtube links, as ExamSolutions is running slow.

7. (Original post by Efemena15)

Jan 2007 Q8

http://www.mathsgeeks.co.uk/allpaper...celJan07QP.pdf

Basically, I thought cos y = sin (y+pi/2)

But when I use this, I get an incorrect answer

And also in review exercise of c3 book there is a question:

y= arcsin x

a) Express arccos x in terms of y
here is the solution (ignore the bottom line)
Attached Images

8. Thank you for both replies but and I understand both of your formulae, but I thought that mine should still work. Is it incorrect?
9. (Original post by Efemena15)
Thank you for both replies but and I understand both of your formulae, but I thought that mine should still work. Is it incorrect?
i believe it gives you the negative angle so you would the have to find the corresponding acute angle by multiplying by -1 which is effectively what the formulae i used is.
10. Since this is the last year before A-level's format changes I think the examiners will probably want to go out with a big boom. I'm guessing this years paper will be really hard!
11. (Original post by sagar448)
Since this is the last year before A-level's format changes I think the examiners will probably want to go out with a big boom. I'm guessing this years paper will be really hard!
Remember though the last paper will be next year as the people in Year 12 are still on the same spec as us.
12. (Original post by randlemcmurphy)
Remember though the last paper will be next year as the people in Year 12 are still on the same spec as us.
OH yes! Banter. I feel better now.
13. Hi everyone, hope you're all well. To say I am s***ting myself for this exam is a a total understatement. I am literally just learning integration for C4 and am struggling with what seems the easiest type :[[[[

I'm using exam solutions, looking at integration of (ax+b)^n, can anyone explain this concept to me?

Much thanks!
14. (Original post by sagar448)
Since this is the last year before A-level's format changes I think the examiners will probably want to go out with a big boom. I'm guessing this years paper will be really hard!
(Original post by randlemcmurphy)
Remember though the last paper will be next year as the people in Year 12 are still on the same spec as us.
Edexcel Maths reform is not until 2017 as far as i'm aware...

http://qualifications.pearson.com/en...s/reforms.html
15. (Original post by pearl_rose)
Hi everyone, hope you're all well. To say I am s***ting myself for this exam is a a total understatement. I am literally just learning integration for C4 and am struggling with what seems the easiest type :[[[[

I'm using exam solutions, looking at integration of (ax+b)^n, can anyone explain this concept to me?

Much thanks!
When integrating (ax+b)^n the power n needs to be more than -1 or less than -1. If the power n is minus one then you cannot use this integration and you will need to use the natural log integration.

Integrating (ax+b)^n example:

Integrate (2x+3)^-4

First step would be to add 1 to the power.

(2x+3)^-3 then, instead of multiplying like in differentiation, you divide by the new power...

((2x+3)^-3)/-3) This is not all, now if you remember in differentiation you differentiated the inside of the bracket and multiplied it to the original. But in integration you differentiate the inside of the bracket and divide.

((2x+3)^-3)/(-3 x 2)

Simplifying gives you...
((2x+3)^-3)/(-6)

Good luck.
16. (Original post by Kill3er)
Edexcel Maths reform is not until 2017 as far as i'm aware...

http://qualifications.pearson.com/en...s/reforms.html
Oh right, I'm way off then. That helps a lot, but pretty sure exam is still going to be hard
17. (Original post by sagar448)
Oh right, I'm way off then. That helps a lot, but pretty sure exam is still going to be hard
Yup. I'm expecting very very difficult papers. Cant even get high marks on the easy ones atm :P
18. (Original post by Kill3er)
Yup. I'm expecting very very difficult papers. Cant even get high marks on the easy ones atm :P
I know right, if you want a real challenge try the R papers. Especially the June 2014 and June 2013 R papers. They are quite tough. :C
19. (Original post by sagar448)
When integrating (ax+b)^n the power n needs to be more than -1 or less than -1. If the power n is minus one then you cannot use this integration and you will need to use the natural log integration.

Integrating (ax+b)^n example:

Integrate (2x+3)^-4

First step would be to add 1 to the power.

(2x+3)^-3 then, instead of multiplying like in differentiation, you divide by the new power...

((2x+3)^-3)/-3) This is not all, now if you remember in differentiation you differentiated the inside of the bracket and multiplied it to the original. But in integration you differentiate the inside of the bracket and divide.

((2x+3)^-3)/(-3 x 2)

Simplifying gives you...
((2x+3)^-3)/(-6)

Good luck.
Thank you very much. :]
20. Is / does anyone use pencil for their exams? Not sure whether it's a good idea

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