You are Here: Home >< Maths

# M1 OCR (Not MEI) Exam - 9/06/2015 watch

1. how the **** did i get k=24 and v=14 :/
what do you think 65/72 will be UMS?
2. (Original post by jt663)
I got different answers for question 7 iirc. Think T was 1.2 for me? (Instead of 0.525)
same, and 1.12 for the final answer for me
3. Ideas as to what 66/72 will be in UMS this year?
4. (Original post by newy181818)
something like 9.74N and 35.6 degrees
Yes - same!
5. iit must be 13.3 for the resultant force
6. (Original post by aliah4666)
Why would the acceleration = 0 for questions 5iii and 5iv??
For iv, there was no sideways movement, and the force up (1.2) was less than gravity (0.4g)

For iii, there was sideways movement, but it was less than friction, so no movement.
7. (Original post by xsanda)
Xsanda's solutions:

Falling question
1i) v=28 [2]
1ii) s=6.384 [2]
1iii) t=0.598 [3]

Collision question
2i) u=6 [4]
2ii) m=0.2 [4]

Cycling question
3i) 20km, 5hrs [3]
3ii) 7 hrs [3]
3iii) 50km [2]

110° tick
4i) 9.74N, 35.4° [6]
4ii) 10.3N [1]
4iii) 54.6° [2]

θ force
5i) 1.04 [3]
5ii) 1.06 [3]
5iii) a=0 [3]
5iv) a=0 [2]

Coalescing
6i) v=68 [4]
6ii) s=78 [4]
6iii) k=132 [1]
6iv) v=7 [5]

Prism
7i) a=0.7 (show that), T=1.68 [5]
7ii) v=1.26 [2]
7iii) -a = 0.9 [2]
7iva) T=1.2 [3]
7ivb) Fr = 1.12 [3]
For q5. The force was applied so those answers are wrong... that's what I think anyway.

Posted from TSR Mobile
8. 7)iv)b 0.3gsin30 -fr = 0.3*-0.9

fr = 1.47 + 0.27 = 1.74?
9. (Original post by lolkik)
iit must be 13.3 for the resultant force
13.3 was the wrong diagonal: the diagonal from the ends of both of the vectors, rather than the diagonal from the start to the end tip-to-tail. You needed to move one vector to the end of the other.
10. Was q5 pulling?
11. T=7 hours
K=132

Is deffo correct
12. (Original post by seizetoday)
T=7 hours
K=132

Is deffo correct
how did you get k to be 132? so i can see where i went wrong
13. (Original post by wat a wizard)
7)iv)b 0.3gsin30 -fr = 0.3*-0.9

fr = 1.47 + 0.27 = 1.74?
You've missed out the tension I think
14. What the **** was that paper? Questions 1-3 and 6-7 were fine but 4 and 5 were abysmal! I will be lucky to have picked up 5 of those 20 marks. Urgh.

I think 56/72 will be an A. Question 3 was a bit hard, but I got 7 hours BY GUESSING.

I guess overall the difficulty balances to medium, as all questions were easy apart from 4 and 5.
16. (Original post by ChoccyPhilly)
A lot of m friends are saying that the 1.2 force was pushing down onto the block. I thought it was pulling
This was the strangest question in terms of wording. 'A 1.2N force is applied to P' there was never any indication for pushing or pulling so it required an assumption to be made. I assumed push, but loads assumed pull. Some are saying that it can't have been push because the angle would have to be below the horizontal. But that's a load of rubbish, since when was that a law? However, I know I got the last two parts wrong because I did a silly mistake, which I'm kicking myself for now. Just hoping that's all I got wrong, which I think it is, in which case this stupid question doesn't matter to me, I can afford to lose it.
17. i second that motion...i got k as 96 i think. how did you get 132?
18. (Original post by Sid1234)
how did you get k to be 132? so i can see where i went wrong
They gave you are formula which was displacement of Q= k-2t^3 I think
Cant remember exactly, but you plug in t=3
So you get k-54 but you equal this to what you get in your previous answer which was the displacement OP (OP=OQ at t=3)

So K-54=78
K=132

Hope this helps.
19. (Original post by Sid1234)
how the **** did i get k=24 and v=14 :/
what do you think 65/72 will be UMS?
i also got 14
20. (Original post by seizetoday)
They gave you are formula which was displacement of Q= k-2t^3 I think
Cant remember exactly, but you plug in t=3
So you get k-54 but you equal this to what you get in your previous answer which was the displacement OP (OP=OQ at t=3)

So K-54=78
K=132

Hope this helps.
AHHH i did 78-24 FUUUUUUU

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: March 7, 2016
Today on TSR

### AQA Mechanics Unofficial Markscheme

Find out how you've done here

### 3,179

students online now

Exam discussions

### Find your exam discussion here

Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE