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    (Original post by supercrazyxo)
    I keep on getting high Bs in every unit 5 paper. How do i get an A. The thing thats usually trips me up are constructing equations.
    BTW How do i get an A* in chem like ums wise??
    Read over the textbook, read chemguide, keep at it until you get it.

    270/300 (90% average) across A2 units and 80% average across all A2 and AS units

    You may find this useful http://www.ocr.org.uk/i-want-to/conv...-marks-to-ums/
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    Tfw you still get grade Cs in unit 5
    Ligands and calcuating buffer pH does my head in ngl
    And i am not specific enough for some questions
    But unit 4 i have that A in the bag provided the NMR is not like the june 15 one
    Drawing the final product is hard as hell for me
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    (Original post by Serine Soul)
    Read over the textbook, read chemguide, keep at it until you get it.270/300 (90% average) across A2 units and 80% average across all A2 and AS unitsYou may find this useful http://www.ocr.org.uk/i-want-to/conv...-marks-to-ums/
    Right now am using this :https://chemrevise.org/ocr-revision-guides/

    I dont like the layout of chemguide and stuff
    What did you get at AS if you dont mind??
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    (Original post by toonervoustotalk)
    Tfw you still get grade Cs in unit 5
    Ligands and calcuating buffer pH does my head in ngl
    And i am not specific enough for some questions
    But unit 4 i have that A in the bag provided the NMR is not like the june 15 one
    Drawing the final product is hard as hell for me
    I printed out all of the NMR questions from OCR A and B for practice
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    (Original post by supercrazyxo)
    I printed out all of the NMR questions from OCR A and B for practice
    Ahh nice!!! Will start doing that
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    (Original post by supercrazyxo)
    Right now am using this :https://chemrevise.org/ocr-revision-guides/

    I dont like the layout of chemguide and stuff
    What did you get at AS if you dont mind??
    That looks fine! If you want help remember to post in this thread!

    A (286/300) Need to repeat that this year if I want to go to my firm uni :cry:
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    (Original post by Serine Soul)
    That looks fine! If you want help remember to post in this thread!

    A (286/300) Need to repeat that this year if I want to go to my firm uni :cry:
    yh will do so and Dam wish i was that smart -_-
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    (Original post by toonervoustotalk)
    Tfw you still get grade Cs in unit 5
    Ligands and calcuating buffer pH does my head in ngl
    And i am not specific enough for some questions
    But unit 4 i have that A in the bag provided the NMR is not like the june 15 one
    Drawing the final product is hard as hell for me
    Tbh drawing the structure was only 3 marks. I was a few ums off an A* in that exam, and I didn't even get the structure and missed out one or two questions.

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    (Original post by UnknownAnon)
    Tbh drawing the structure was only 3 marks. I was a few ums off an A* in that exam, and I didn't even get the structure and missed out one or two questions.

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    Ahh nice!!!
    But tbf i did crap in the practical unit
    26/40
    So i have to boost my grades up by unit 4 and 5!!
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    (Original post by toonervoustotalk)
    Ahh nice!!!
    But tbf i did crap in the practical unit
    26/40
    So i have to boost my grades up by unit 4 and 5!!
    Can't you try again?? Don't you get 3 tries with ISA??


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    (Original post by supercrazyxo)
    I printed out all of the NMR questions from OCR A and B for practice
    Do you have files of these?

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    (Original post by supercrazyxo)
    Can't you try again?? Don't you get 3 tries with ISA??


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    I did but i didnt do well in it
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    (Original post by Hunnybeebee)
    Do you have files of these?

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    sry i dont have it on my computer. I just went to the ocr site and printed the NMR questions and it will take too long to scan it onto laptop
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    Hi everyone,

    Hows everyone revision going?

    I just wanted to ask does anybody know how to do Question 4c)ii) in the OCR June 2014 paper It is a really straightforward question but it seems so tricky to get the initial rate of reaction. For e.g. Experiment 3 the initial rate is 614. How on earth do they get that?
    Heres the link:
    http://www.ocr.org.uk/Images/243458-...d-elements.pdf
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    (Original post by omarali1212)
    Hi everyone,

    Hows everyone revision going?

    I just wanted to ask does anybody know how to do Question 4c)ii) in the OCR June 2014 paper It is a really straightforward question but it seems so tricky to get the initial rate of reaction. For e.g. Experiment 3 the initial rate is 614. How on earth do they get that?
    Heres the link:
    http://www.ocr.org.uk/Images/243458-...d-elements.pdf
    They give you the rate question at the beginning of the question. Use that!!

    In this question your comparing experiments.
    So to find out the initial rate of experiment 3, you compare experiment 1 and 3.

    Starting from [I-]
    To get from 0.015 to 0.060 you x by 4
    We know from the rate equation the [I-] is second order so we square the 4. times 4 squared by 0.60 (initial rate)
    And you get X value

    [IO3-]

    To get from 0.010 to 0.040 to x by 4
    We know from the rate equation that
    [IO3-] is first order so it 4 to the power of 1 which is 4. 4 times X value to get Y value

    [H+]

    To get from 0.020 to 0.080 you times by 4. [H+] is second order so thats 4 squared. Y value times 4 squared is Z value which is the I initial rate for experiment 3.

    You should get 614.4 and to the 3 SF it's 614.

    Don't know of this makes sense.










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    (Original post by supercrazyxo)
    They give you the rate question at the beginning of the question. Use that!!

    In this question your comparing experiments.
    So to find out the initial rate of experiment 3, you compare experiment 1 and 3.

    Starting from [I-]

    To get from 0.015 to 0.060 you x by 4
    We know from the rate equation the [I-] is second order so we square the 4. times 4 squared by 0.60 (initial rate)
    And you get X value

    [IO3-]

    To get from 0.010 to 0.040 to x by 4
    We know from the rate equation that
    [IO3-] is first order so it 4 to the power of 1 which is 4. 4 times X value to get Y value

    [H+]

    To get from 0.020 to 0.080 you times by 4. [H+] is second order so thats 4 squared. Y value times 4 squared is Z value which is the I initial rate for experiment 3.

    You should get 614.4 and to the 3 SF it's 614.

    Don't know of this makes sense.










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    (Original post by supercrazyxo)
    They give you the rate question at the beginning of the question. Use that!!

    In this question your comparing experiments.
    So to find out the initial rate of experiment 3, you compare experiment 1 and 3.

    Starting from [I-]
    To get from 0.015 to 0.060 you x by 4
    We know from the rate equation the [I-] is second order so we square the 4. times 4 squared by 0.60 (initial rate)
    And you get X value

    [IO3-]

    To get from 0.010 to 0.040 to x by 4
    We know from the rate equation that
    [IO3-] is first order so it 4 to the power of 1 which is 4. 4 times X value to get Y value

    [H+]

    To get from 0.020 to 0.080 you times by 4. [H+] is second order so thats 4 squared. Y value times 4 squared is Z value which is the I initial rate for experiment 3.

    You should get 614.4 and to the 3 SF it's 614.

    Don't know if this makes sense.










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    (Original post by supercrazyxo)
    They give you the rate question at the beginning of the question. Use that!!

    In this question your comparing experiments.
    So to find out the initial rate of experiment 3, you compare experiment 1 and 3.

    Starting from [I-]
    To get from 0.015 to 0.060 you times by 4.We know from the rate equation the
    [I-] is second order so we square the 4. times 4 squared by 0.60 (initial rate)
    And you get X value

    [IO3-]

    To get from 0.010 to 0.040 you times by 4.We know from the rate equation that
    [IO3-] is first order so it 4 to the power of 1 which is 4. 4 times X value to get Y value

    [H+]

    To get from 0.020 to 0.080 you times by 4. [H+] is second order so thats 4 squared. Y value times 4 squared is Z value which is the I initial rate for experiment 3.

    You should get 614.4 and to the 3 SF it's 614.

    Don't know of this makes sense.










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    How comes your up so early?

    I kind of get it

    Thanks for the reply.
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    On question 3)b)ii) on F324 January 2010 (MS here http://www.ocr.org.uk/Images/63346-m...me-january.pdf) says "Ignore bond linkage for all groups" does this mean how you drew the bonds do not matter??
 
 
 
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