Turn on thread page Beta
    Offline

    15
    ReputationRep:
    (Original post by ombtom)
    Someone already posted this:

    1a) 8
    b) 5
    2a) 6
    b) 4
    3) 6
    4a) 5
    b) 4
    5a) 8
    b) 4
    6a) 6
    b) 7
    7a) 7
    b) 3
    c) 2
    Thanks.
    Offline

    11
    ReputationRep:
    How many marks was the question where you had to find d=? (the one with the non uniform rod)?
    Offline

    10
    ReputationRep:
    **** m2
    Offline

    0
    (Original post by HarshaPeed)
    Personally I think the paper looked weird af but was alright if you applied your mechanics. I can never do centre of mass questions anyways so I probably got that wrong (oh well). Other than that the paper was super non-standard with a lot of weird questions. Also anyone who did FP2 will understand that p,q and r and no longer part of my alphabet as they are disgusting letters and should be killed with fire.
    You just made my day! Lol yeah I did FP2 exam too If you still remember question 4 on that paper.. lol I totally understand what you mean
    Offline

    2
    ReputationRep:
    (Original post by ThatPerson2)
    I would think that you would probably lose one or two A1 marks for it, assuming your method was correct (I would think it might be M1A1 for getting the correct integral, M1 for subbing in values and solving).
    Hopefully! Thanks!
    Offline

    2
    ReputationRep:
    (Original post by ombtom)
    Someone already posted this:

    1a) 8
    b) 5
    2a) 6
    b) 4
    3) 6
    4a) 5
    b) 4
    5a) 8
    b) 4
    6a) 6
    b) 7
    7a) 7
    b) 3
    c) 2
    Lol theres nothing wrong with posting again, not everyone will go back to that page and find it ygm
    Offline

    2
    ReputationRep:
    (Original post by TheMoon)
    How many marks was the question where you had to find d=? (the one with the non uniform rod)?
    4 marks
    Offline

    2
    ReputationRep:
    (Original post by RThornton)
    My answers:
    1).
    a). q=-8, p=2, r=11
    b). 11/3m


    2).
    P=4900w
    R=784N
    b). d=53.1m


    3).
    c=10/3


    4).
    x=0.83m below
    angle= 114 degrees


    5).
    d= 2.56m


    6). lambda= 30/7 (4.29)
    speed= 10.4m
    angle= 73.6 degrees to the vector i (horizontal)


    7). A= 3u/20 (left)
    B= 21u/10 (right)
    e=1/14
    no collision as B after wall moves at the same speed as A, hence never meet
    Question 1 had 3 parts, part b) was to find the acceleration of the particle when t=3 wasnt it?

    Other than that I got all the exact same answers as you ^^ hopefully 90+ UMS
    Offline

    11
    ReputationRep:
    (Original post by ombtom)
    Someone already posted this:

    1a) 8
    b) 5
    2a) 6
    b) 4
    3) 6
    4a) 5
    b) 4
    5a) 8
    b) 4
    6a) 6
    b) 7
    7a) 7
    b) 3
    c) 2
    which was the one with the non uniform rod?
    Offline

    10
    ReputationRep:
    ....
    Offline

    16
    ReputationRep:
    (Original post by linaxq)
    Lol theres nothing wrong with posting again, not everyone will go back to that page and find it ygm
    Exactly; I posted it again to complete edothero's list. They match up so it's all good.
    Offline

    2
    ReputationRep:
    (Original post by ombtom)
    Someone already posted this:

    1a) 8
    b) 5
    2a) 6
    b) 4
    3) 6
    4a) 5
    b) 4
    5a) 8
    b) 4
    6a) 6
    b) 7
    7a) 7
    b) 3
    c) 2
    Using that I probably got somewhere between 50 and 55. Which isn't too bad.
    Ah well.
    Offline

    2
    ReputationRep:
    (Original post by cjlh)
    Very true, could be either depending on how anal they are. Probably would be fine though actually



    No problem dude
    Ahh was the position vector lambda(i+j) or lambda (i-j)
    Offline

    0
    ReputationRep:
    for q5 did you have to do it using work energy principle?
    Offline

    2
    ReputationRep:
    (Original post by zandneger)
    Question 1 had 3 parts, part b) was to find the acceleration of the particle when t=3 wasnt it?

    Other than that I got all the exact same answers as you ^^ hopefully 90+ UMS
    part a was to find acceleration at t=3 and you could only do it by finding p q and r

    b was to find distance covered in the third second
    Offline

    2
    ReputationRep:
    (Original post by ombtom)
    Exactly; I posted it again to complete edothero's list. They match up so it's all good.
    ah nice
    Offline

    15
    ReputationRep:
    Grade boundaries:
    I reckon

    66 - 90 UMS
    58 - 80 UMS
    51 - 70 UMS
    Offline

    0
    ReputationRep:
    For question 1b) it said in the THIRD second therefore would the boundaries for the integral not be t=2 and t=3 meaning you would get 34/3 or 11.66 as the distance
    Offline

    2
    ReputationRep:
    (Original post by Jakester11)
    Ahh was the position vector lambda(i+j) or lambda (i-j)
    Began at 0, projected with velocity (3i-4j) and ended up at A which had position vector lambda(i-j)
    Offline

    2
    ReputationRep:
    Looking through the mark schemes, it looks like they all want the answer to 3sf OR BETTER, meaning you can't have rounded 10.44 any less than 3, rather than any more than 3
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: August 18, 2016

University open days

  • Heriot-Watt University
    School of Textiles and Design Undergraduate
    Fri, 16 Nov '18
  • University of Roehampton
    All departments Undergraduate
    Sat, 17 Nov '18
  • Edge Hill University
    Faculty of Health and Social Care Undergraduate
    Sat, 17 Nov '18
Poll
Black Friday: Yay or Nay?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.