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# Edexcel AS/A2 Mathematics M2 - 17th June 2016 - Official Thread watch

1. (Original post by ombtom)

1a) 8
b) 5
2a) 6
b) 4
3) 6
4a) 5
b) 4
5a) 8
b) 4
6a) 6
b) 7
7a) 7
b) 3
c) 2
Thanks.
2. How many marks was the question where you had to find d=? (the one with the non uniform rod)?
3. **** m2
4. (Original post by HarshaPeed)
Personally I think the paper looked weird af but was alright if you applied your mechanics. I can never do centre of mass questions anyways so I probably got that wrong (oh well). Other than that the paper was super non-standard with a lot of weird questions. Also anyone who did FP2 will understand that p,q and r and no longer part of my alphabet as they are disgusting letters and should be killed with fire.
You just made my day! Lol yeah I did FP2 exam too If you still remember question 4 on that paper.. lol I totally understand what you mean
5. (Original post by ThatPerson2)
I would think that you would probably lose one or two A1 marks for it, assuming your method was correct (I would think it might be M1A1 for getting the correct integral, M1 for subbing in values and solving).
Hopefully! Thanks!
6. (Original post by ombtom)

1a) 8
b) 5
2a) 6
b) 4
3) 6
4a) 5
b) 4
5a) 8
b) 4
6a) 6
b) 7
7a) 7
b) 3
c) 2
Lol theres nothing wrong with posting again, not everyone will go back to that page and find it ygm
7. (Original post by TheMoon)
How many marks was the question where you had to find d=? (the one with the non uniform rod)?
4 marks
8. (Original post by RThornton)
1).
a). q=-8, p=2, r=11
b). 11/3m

2).
P=4900w
R=784N
b). d=53.1m

3).
c=10/3

4).
x=0.83m below
angle= 114 degrees

5).
d= 2.56m

6). lambda= 30/7 (4.29)
speed= 10.4m
angle= 73.6 degrees to the vector i (horizontal)

7). A= 3u/20 (left)
B= 21u/10 (right)
e=1/14
no collision as B after wall moves at the same speed as A, hence never meet
Question 1 had 3 parts, part b) was to find the acceleration of the particle when t=3 wasnt it?

Other than that I got all the exact same answers as you ^^ hopefully 90+ UMS
9. (Original post by ombtom)

1a) 8
b) 5
2a) 6
b) 4
3) 6
4a) 5
b) 4
5a) 8
b) 4
6a) 6
b) 7
7a) 7
b) 3
c) 2
which was the one with the non uniform rod?
10. ....
11. (Original post by linaxq)
Lol theres nothing wrong with posting again, not everyone will go back to that page and find it ygm
Exactly; I posted it again to complete edothero's list. They match up so it's all good.
12. (Original post by ombtom)

1a) 8
b) 5
2a) 6
b) 4
3) 6
4a) 5
b) 4
5a) 8
b) 4
6a) 6
b) 7
7a) 7
b) 3
c) 2
Using that I probably got somewhere between 50 and 55. Which isn't too bad.
Ah well.
13. (Original post by cjlh)
Very true, could be either depending on how anal they are. Probably would be fine though actually

No problem dude
Ahh was the position vector lambda(i+j) or lambda (i-j)
14. for q5 did you have to do it using work energy principle?
15. (Original post by zandneger)
Question 1 had 3 parts, part b) was to find the acceleration of the particle when t=3 wasnt it?

Other than that I got all the exact same answers as you ^^ hopefully 90+ UMS
part a was to find acceleration at t=3 and you could only do it by finding p q and r

b was to find distance covered in the third second
16. (Original post by ombtom)
Exactly; I posted it again to complete edothero's list. They match up so it's all good.
ah nice
I reckon

66 - 90 UMS
58 - 80 UMS
51 - 70 UMS
18. For question 1b) it said in the THIRD second therefore would the boundaries for the integral not be t=2 and t=3 meaning you would get 34/3 or 11.66 as the distance
19. (Original post by Jakester11)
Ahh was the position vector lambda(i+j) or lambda (i-j)
Began at 0, projected with velocity (3i-4j) and ended up at A which had position vector lambda(i-j)
20. Looking through the mark schemes, it looks like they all want the answer to 3sf OR BETTER, meaning you can't have rounded 10.44 any less than 3, rather than any more than 3

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