Edexcel AS/A2 Mathematics M2 - 17th June 2016 - Official Thread

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Four things that unis think matter more than league tables 08-12-2016
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    I still don't understand how to do question 6 got completely wrong the lambda question
    Since the exam ended I don't really care how to solve it (good bye m2 Let's never meet again ) but then again I want to know how many marks I can pick up hopefully few method marks
    Can anybody please explain me how to do that question?
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    I think i put wrong fprces for the the moments question what were the right forces
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    (Original post by TKA1998)
    For question 1b) it said in the THIRD second therefore would the boundaries for the integral not be t=2 and t=3 meaning you would get 34/3 or 11.66 as the distance
    The distance was 11/3 though.
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    (Original post by Mattematics)
    My answers:
    Q1) Acceleration: 4 ms^-2 (p = 2, q = -8)
    Distance = 11/3 m

    Q2) R = 784
    P = 4900
    d = 58.1 m

    Q3) c = 10/3

    Q4) Distance below AD = 0.830
    Couldn't work out the angle

    Q5) R = 5g - something cos^2theta
    F = something * dg*costheta*sintheta

    d = ~1.94

    Q6) lambda = 30/7
    v = 10.4 ms^-1
    73.3 degrees below horizontal

    Q7) e = 1/14
    No collision because they're moving the same speed in the same direction
    How did you got e in q7
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    (Original post by TKA1998)
    For question 1b) it said in the THIRD second therefore would the boundaries for the integral not be t=2 and t=3 meaning you would get 34/3 or 11.66 as the distance
    The first part of what you've said is true but the answer was 11/3 not 34/3
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    (Original post by cjlh)
    Began at 0, projected with velocity (3i-4j) and ended up at A which had position vector lambda(i-j)
    Gutted, thought it said i+j, that's why. Oh well, cheers
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    (Original post by TKA1998)
    For question 1b) it said in the THIRD second therefore would the boundaries for the integral not be t=2 and t=3 meaning you would get 34/3 or 11.66 as the distance
    Integrating 2t^2 - 8t + 11 and then using the limits 2 and 3 gives you 11/3m (This is what I did in the exam).
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    I also was baffled on the lambda question
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    (Original post by edothero)
    Grade boundaries:
    I reckon

    66 - 90 UMS
    58 - 80 UMS
    51 - 70 UMS
    those are pretty low no??
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    (Original post by angelitajin)
    I still don't understand how to do question 6 got completely wrong the lambda question
    Since the exam ended I don't really care how to solve it (good bye m2 Let's never meet again ) but then again I want to know how many marks I can pick up hopefully few method marks
    Can anybody please explain me how to do that question?
    I said a few pages back:

    (Original post by cjlh)
    suvat

    horizontal: s=lambda
    vertixcal: s=-lamda

    Fill in the other knowns, find t in terms of lambda using the horizontal (t=1/3 lambda) and then solve substituting this into s=ut+1/2 at^2 with the vertical values
    If you need it cleared up I can go into more detail

    (Original post by Jakester11)
    Gutted, thought it said i+j, that's why. Oh well, cheers
    No problem, sucks but hopefully you'll score the Ms.
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    (Original post by Jakester11)
    Ahh was the position vector lambda(i+j) or lambda (i-j)
    Lambda(I-J)
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    how many marks lost if I integrated between 3 and 0 instead of 3 and 2?
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    does anyone know how many marks i would lose if for the question with 3i+4j i used 3 for vertical and 4 for horizontal but all my working out was right? out of all the 12 marks?
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    (Original post by zandneger)
    Looking through the mark schemes, it looks like they all want the answer to 3sf OR BETTER, meaning you can't have rounded 10.44 any less than 3, rather than any more than 3
    great ty for that
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    (Original post by Cong)
    How did you got e in q7
    Particle B is going towards the wall with speed 21u/10

    Impulse received was 27mu/4

    Using I = mv - mu

    Which you get v = 3u/20

    e = v/u

    therefore e = (3u/20)/(21u/10) = 1/14

    And for part c, both A and B are moving at the same speed, V_a = V_b therefore no further collisions will occur
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    (Original post by TKA1998)
    For question 7 I made an arithmetic error and subsequently got the wrong value for the speed of B meaning I used the wrong value in part b and c, how many marks would i likely loose for this.
    Anyone?
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    (Original post by zandneger)
    Looking through the mark schemes, it looks like they all want the answer to 3sf OR BETTER, meaning you can't have rounded 10.44 any less than 3, rather than any more than 3
    Has to be 3sf in mechanics doesn't it, or can you get away with 4sf or greater for all questions?
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    If A* is approx 68/69, would 100 UMS be any lower than 75/75?
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    (Original post by linaxq)
    those are pretty low no??
    They are, but looking at June 2012, the questions are quite similar. That year was 57 for 80 UMS. :eek:
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    (Original post by angelitajin)
    I still don't understand how to do question 6 got completely wrong the lambda question
    Since the exam ended I don't really care how to solve it (good bye m2 Let's never meet again ) but then again I want to know how many marks I can pick up hopefully few method marks
    Can anybody please explain me how to do that question?
    lambda(i-j) = (lambda)i+(-lambda)j
    Since you know horizontal speed is constant, using speed = distance/time you get
    distance(horizontal) = 3t
    Hence, lambda = 3t and -lamba = -3t
    So you want the value for t when displacement(vertical) = -3t
    s=-3t u=4 v=/ a=-9.8 t=t
    s=ut+1/2at^2
    -3t=4t-4.9t^2
    7t-4.9t^2=0
    t(7-4.9t)=0
    s=-3t when t=0 or when t=7/4.9
    7/4.9 = 10/7
    hence lambda = 3t = 30/7
 
 
 
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