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Edexcel IGCSE Mathematics A - Paper 3H - 2016 - Unofficial Mark Scheme Watch

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    For the circle theorem (63) i wrote the working for 48 and 15 but didn't add them together and just put 15 what would i get out of (4 marks)?
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    Can anyone finish the mark scheme would really apreciate it
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    (Original post by BOBQ)
    For the circle theorem (63) i wrote the working for 48 and 15 but didn't add them together and just put 15 what would i get out of (4 marks)?
    3 probably.

    Just missed out one stage if the numbers 48 and 15 are visible but you haven't added them then you have only missed out one step.
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    (Original post by igggy)
    Can anyone finish the mark scheme would really apreciate it
    If you tell me the questions you would like, I can give you the answers.
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    No I think he's right. See, when you scale a side of a square by two, it's area increases by 4,because it's squared. If you were to go from cm^2 to cm^3, you would need to do ^3/2
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    (Original post by Ryzoz)
    No I think he's right. See, when you scale a side of a square by two, it's area increases by 4,because it's squared. If you were to go from cm^2 to cm^3, you would need to do ^3/2
    For that question, here is the proof.
    ASF = 750/120=6.25
    LSF = square root of ASF = square root of 6.25 = 2.5
    VSF = LSF cubed, = 2.5^3=15.625

    Therefore 1600/15.625 = 102.4 cm^3
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    If anyone needs

    5 mark gradient question was 4Y - 3X = - 19

    Trapezium X value ( question 17) was 8 (not - 7.5)
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    Thank you Ryzoz, someone understands my logic. You can't compare values of different units.
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    (Original post by Martins1)
    For that question, here is the proof.
    ASF = 750/120=6.25
    LSF = square root of ASF = square root of 6.25 = 2.5
    VSF = LSF cubed, = 2.5^3=15.625

    Therefore 1600/15.625 = 102.4 cm^3
    Yes Area factor = (scale factor)^2

    Volume factor = (scale factor)^3
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    (Original post by sgsb0y)
    For the pentagon I just divided it into 3 triangles. Used 1/2absinC for the area of the two outer triangles. Used cosine rule to get the length of one of the sides of the middle triangle. Then split the middle triangle in half to get a right angled triangle and halved the 13 cm into 6.5cm. Used Pythagoras to get the height of the overall middle triangle. 1/2 times base (13cm) times height (I worked out the height using Pythagoras theorem earlier). Then added the areas of the 3 triangles together and got the total area of the pentagon: 188cm which I presume is right because the majority of people are saying it is.


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    THIS IS HOW I ANSWERED QUESTION 22. I'm sure there are other methods but this seemed most simple to me at the time. IGCSETANK or whoever you are, I'm pretty certain that 188 is the answer, stop acting like your school is Hogwarts so that people believe that you are right. And just a healthy tip, you don't have to constantly curse to prove a point...


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    Topic List for 4H
    Angle rules (corresponding angles, interior angles etc.)
    Alternate Segment Theorem
    Indices
    Transformations
    A hard algebraic simplification question
    Surds
    Quadratic Formula
    Inequalities – inequality lines and graphs(shade in the correct section)
    Vectors – Proof of straight line
    Function notation – inverse function, domain,range
    Median, mean, mode, range
    Compound interest and percentages
    Proportionality
    Bearings
    Line Bisectors and angle bisectors
    Construction of shapes
    Histograms
    Interior angles, exterior angles, number ofsides
    Standard Form
    Recurring Decimals
    Prime Factors
    Venn Diagrams
    Chords and Sectors
    Sin rule trig
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    (Original post by Martins1)
    Topic List for 4H
    Angle rules(corresponding angles, interior angles etc.)
    AlternateSegment Theorem
    Cyclic Quadrilateral circle theorem
    Indices
    Transformations
    A hard algebraic simplification question
    Surds
    Quadratic Formula
    Inequalities – inequality lines and graphs(shade in the correct section)
    Vectors – Proof of straight line
    Function notation – inverse function, domain,range
    Median, mean, mode, range
    Compound interest and percentages
    Proportionality
    Bearings
    Line Bisectors and angle bisectors
    Construction of shapes
    Histograms
    Interior angles, exterior angles, number ofsides
    Standard Form
    Recurring Decimals
    Prime Factors
    Venn Diagrams
    I think cyclic quadrilateral theorem was in 3H? on the circle theorem
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    (Original post by BOBQ)
    I think cyclic quadrilateral theorem was in 3H? on the circle theorem
    Of course, sorry.
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    (Original post by Martins1)
    Of course, sorry.
    Sound like easier topics though which is good
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    (Original post by Martins1)
    Yes. Set A shares no members with Set B and vice versa.
    i just saied that there is not letter in commen is that full mark ?
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    (Original post by WhiteX)
    i just saied that there is not letter in commen is that full mark ?
    Yes its the same thing
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    On the straight line graph that had to be drawn, did you have to stop at X=3
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    (Original post by Martins1)
    If you tell me the questions you would like, I can give you the answers.
    All of the ones missing lol i was getting 90s in past papers and i just ****ed up so badly idek why. Gonna have to do sick in the second paper
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    Differentiation velocity question I think was question 15 and the answer was:

    (a). 12t-24
    (b). 2
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    (Original post by joebarnes123)
    Differentiation velocity question I think was question 15 and the answer was:

    (a). 12t-24
    (b). 2
    The first part a) was ds/dt to find the velocity which = 6t^2 -24t + 7

    and b) was 2
 
 
 
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