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# AQA A2 Mathematics Pure Core 4 MPC4 - 17th June 2016 Watch

1. (Original post by -jordan-)
You loose the same percentage in the same time period.
Not of the original value. That would mean an element would only ever have 2 half lives..
2. Can anyone remember how many marks q3 was and q8?
3. (Original post by df97)
partial fractions and binomial expansion, i think answers are as follows:
A=-5/2 B=9/2
-1+7x-22/3x^2
not sure on limit, think some people have something like mod x < 4/3
wasnt there a smaller range mod x< 1/2
4. (Original post by C0balt)
What he said
So what form was the answer to the last question?
5. (Original post by df97)
partial fractions and binomial expansion, i think answers are as follows:
A=-5/2 B=9/2
-1+7x-22/3x^2
not sure on limit, think some people have something like mod x < 4/3
mod x <1/2 i believe , since the range of 1/2 falls within the range of 3/4
6. (Original post by ihsanulhaq101)
13/35 for me also.
SAME
Can we please verify if 1/5 or 13/35?
7. How did everyone find it? I thought it was alright, couldnt do last vectors or last page though
8. (Original post by Pingu7)
So what form was the answer to the last question?
3sin3y - 3cos3y =1/6 tan^-1(3x/2)+pi
Or sth
9. (Original post by 1/2(p^2-p))
wasnt there a smaller range mod x< 1/2
yes thats right
10. (Original post by tanyapotter)
does anyone remember the two parametric equations that you had to find dy/dx for?
x = (4-4e^2-6t)4 y=e^3t/33t
11. (Original post by m00ngrk)
Can anyone remember how many marks q3 was and q8?
last one was 10 marks
3 was the 5 marker i think? Trig quadratic
12. Whoops, did anyone get lamda=3 and mu=2?
13. (Original post by mickel_w)
Not of the original value. That would mean an element would only ever have 2 half lives..
After 100 days you have k^100 lots of the original value left. After 200 days you have (k^100)^2 of the original value. So therefore you loose (0.8)^3 over 300 days, given that k^100 is approximately 0.8 because you had roughly 8=(k^100)*10
14. (Original post by hi-zen-berg)
SAME
Can we please verify if 1/5 or 13/35?
I got 13/35
15. (Original post by jtebbbs)
Yeah sounds right. Just made me realise I put |x|<1/4 cause I was looking at (3-4x) and not (1-4/3x), there goes a mark lol

Edit: think the right answer would be |x|<3/4, as the |x| in |x|<1 is replaced by |4/3x|, so |4/3x|<1, so |x|<3/4
I got -1/2<x<1/2
16. What did everyone do for p(5-5^0.5)?
17. (Original post by Jm098)
x = (4-4e^2-6t)4 y=e^3t/33t
what was the gradient when you use these to find dy/dx
18. (Original post by AQslAyy)
I got -1/2<x<1/2
Me too, as this was the narrowest of the two ranges
19. (Original post by tanyapotter)
does anyone remember the two parametric equations that you had to find dy/dx for?
Attachment 551854551856
Attached Images

20. (Original post by AQslAyy)
I got -1/2<x<1/2
Yeah don't listen to me mate, you're right, didn't even consider the (1+2x) part until just now, oh well it's only one mark

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