I agree with you here I don't understand why its 5v across the 18ohm resistor and not 1... anyone care to explain why its 5v not 1v!!
also anyone know of an unofficial mark scheme anywhere?
6.0V was your emf. When current flows through the circuit, volts are lost inside the battery due to the internal resistance. The oscilloscope acts much like a voltmeter, and when both switches were closed the oscilloscope measured the terminal pd (which obviously does not account for the volts lost inside the battery). The resistance of the external resistor was 18 ohms, and the pd across it was 5.0V (i.e. the terminal pd), hence current is worked out using V=RI so I=V/R =5/18 =0.277777... A and so on
For the conservation to find particle X I put photon, it doesn't have a charge, lepton number = 0, baryon number = 0, doesn't violate anything so would I by any chance get the mark?
But a photon isn't a particle! And it said X was a particle I'm sure
I thought the power question was asking for the total power and not the mean power supplied so wouldn't it be 8800W? Also, are the wires in parallel or series? I was running out of time and assumed parallel so will I lose all 4 marks?