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    (Original post by Lawliettt)
    How would you get 4040? It was literally (230^2)/12=4400. And even if it was 4040, you would be wrong because you had to use 2 significant figures
    Read first line, Correct add etc. That was my typing mistake
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    For the emf question I put 6 without the unit, do you reckon I will lose the mark as it only asked for the value not the units...? 🤕


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    (Original post by txnilxnur)
    I agree with you here I don't understand why its 5v across the 18ohm resistor and not 1... anyone care to explain why its 5v not 1v!!

    also anyone know of an unofficial mark scheme anywhere?
    6.0V was your emf. When current flows through the circuit, volts are lost inside the battery due to the internal resistance. The oscilloscope acts much like a voltmeter, and when both switches were closed the oscilloscope measured the terminal pd (which obviously does not account for the volts lost inside the battery). The resistance of the external resistor was 18 ohms, and the pd across it was 5.0V (i.e. the terminal pd), hence current is worked out using V=RI so I=V/R =5/18 =0.277777... A and so on
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    (Original post by matty9)
    For the conservation to find particle X I put photon, it doesn't have a charge, lepton number = 0, baryon number = 0, doesn't violate anything so would I by any chance get the mark?
    But a photon isn't a particle! And it said X was a particle I'm sure
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    Guys do you think I will get any marks for working out on the power question I got 8800W
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    (Original post by dont leave blank)
    For the emf question I put 6 without the unit, do you reckon I will lose the mark as it only asked for the value not the units...? 🤕


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    It was one mark so i imagine you will get the mark for simply stating the magnitude without the unit
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    what did everyone draw for the circuit for the 6 market question??
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    (Original post by Imtheish)
    Guys do you think I will get any marks for working out on the power question I got 8800W
    Maybe one mark for writing down the equation: P=V^2/R
    But no other marks
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    So did I because I thought it asked for total power but everyone else has calculated average power so are we wrong?
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    (Original post by tort 779)
    Maybe one mark for writing down the equation: P=V^2/R
    But no other marks
    Okay thanks do you remember if there was another question after that one before the 228V
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    (Original post by tort 779)
    Maybe one mark for writing down the equation: P=V^2/R
    But no other marks
    I thought that particular question had marks for using an appropriate sfs..?


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    (Original post by tort 779)
    It was one mark so i imagine you will get the mark for simply stating the magnitude without the unit
    Yh..hopefully


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    (Original post by ShenanigansTVLV)
    So did I because I thought it asked for total power but everyone else has calculated average power so are we wrong?
    Apparently we are
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    (Original post by txnilxnur)
    what did everyone draw for the circuit for the 6 market question??
    Name:  ImageUploadedByStudent Room1464119133.125621.jpg
Views: 246
Size:  18.4 KB

    I think they'd expect something like this..but forgot to do the data logger..


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    I got 651V for my peak to peak as I didn't round when calculating Vtotal? Will I still get the mark?
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    (Original post by txnilxnur)
    But a photon isn't a particle! And it said X was a particle I'm sure
    First line of wikipedia: "A photon is an elementary particle" so your point is invalid xD
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    In question 6 bi I thought it asked for total power and not average power so would it not be wrong to use V rms instead of the peak voltage ??


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    (Original post by Imtheish)
    Apparently we are
    I thought the power question was asking for the total power and not the mean power supplied so wouldn't it be 8800W? Also, are the wires in parallel or series? I was running out of time and assumed parallel so will I lose all 4 marks?
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    (Original post by Lawliettt)
    For 6 I got 650V, then 4400W, then 228V (that one was a disgusting question) and for the last one i just wrote down BS
    I got 651V and 4480W and then 228.2V so pretty close, fingers crossed its right.
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    (Original post by Imtheish)
    Okay thanks do you remember if there was another question after that one before the 228V
    Calculating peak to peak voltage, which i believe was 650V
 
 
 
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