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Edexcel IGCSE Mathematics A - Paper 3H - 2016 - Unofficial Mark Scheme Watch

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    (Original post by BOBQ)
    On the straight line graph that had to be drawn, did you have to stop at X=3
    yes x=3 y=4
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    angle of 105 degrees and sides of 8cm and 12cm
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    (Original post by WhiteX)
    yes x=3 y=4
    Thanks!
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    (Original post by igggy)
    Didnt he already have like 1000 or something
    you are right
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    (Original post by _Xenon_)
    Please help us get together an unofficial mark scheme for the Edexcel IGCSE Mathematics A HIGHER TIER exam today. If you can remember any questions/answers (preferably with question numbers) please post below. Please note that the questions which are currently empty are labelled 'not done' and will be filled in ASAP. Many thanks.

    Question 1
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    1. Ingredients question.
    (a) 750
    (b) 30 muffins
    Question 2
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    2. t is the total number of pens.
    x is a small box.
    y is a big box.
    There are 4 pens in the small boxes and 10 pens in the big ones. I believe the answer was: t = 4x+10y (3 marks)
    Question 3
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    3. 38
    Question 4 (not done)
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    4.
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    5.
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    6.
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    8.
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    9.
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    10. 10.7 degrees (?)
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    14.
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    15.
    Question 16
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    16. Volume of the vase was 102 cm3.
    Working out:
    ASF = -
    LSF = -
    VSF = -
    = --- (3 s.f.)
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    17.
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    18.
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    19.
    Question 20
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    20. x=7, y=-3
    Question 21
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    21. 25/84
    Question 22
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    22. 188cm2
    [Circle theorems was 63 degrees. Cube and sphere one was 1637 (?)]

    If you remember the question numbers please let me know, thanks.
    Cube and sphere one was 850?!
    Differentiation velocity one was:
    (a). 12t-24
    (b). 2
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    (Original post by BOBQ)
    The first part a) was ds/dt to find the velocity which = 6t^2 -24t + 7

    and b) was 2

    Yeah but for the first part I think you had to differentiate again because it's dv/ds
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    Question 22 Proof that answer is 188.
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    Does anyone remember the shaded rectangle with circle in the middle question?
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    (Original post by joebarnes123)
    Cube and sphere one was 850?!
    Differentiation velocity one was:
    (a). 12t-24
    (b). 2
    Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
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    (Original post by Martins1)
    Question 22 Proof that answer is 188.
    Haha I messed that one up so bad
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    (Original post by joebarnes123)
    Cube and sphere one was 850?!
    Differentiation velocity one was:
    (a). 12t-24
    (b). 2

    Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
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    (Original post by sgsb0y)
    Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
    yeah I think part a was 12t^2-24t+7
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    (Original post by sgsb0y)
    Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
    I'm not entirely sure but I'm fairly confident you had to differentiate the first one a second time because you are finding velocity not speed... And yeah the second part was definitely 2
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    (Original post by sgsb0y)
    Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
    The first part a) said to find VELOCITY which is speed / time or ds/dt

    so you differentiated the equation s = 2t^3 + 12t^2 + 7t

    which = 6t^2 + 24t + 7

    b) was to find ACCELERATION which = dv/dt when velocity = 0

    which =2
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    (Original post by sgsb0y)
    Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
    no! I don't agree with you, for velocity you only differentiate once, then for acceleration you do again!
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    (Original post by sgsb0y)
    Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
    No, 12t-24=0 was part of the working for part b.

    Part a asked you to differentiate to get 6t^2 - 24t + 7
    Part b asked you to find the time when acceleration was equal to 0.
    Therefore, acceleration= 6t^2 - 24t + 7 differentiated to get 12t-24=a
    when a = 0, 12t-24=0
    12t=24
    t=2
    therefore the time was 2 seconds.
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    (Original post by robellie77)
    yeah! I agree with you, for velocity you only differentiate once, then for acceleration you do again!
    Yeah because velocity is speed in a given direction, it won't require a double differentiation. Acceleration requires another differentiation. 👍



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    (Original post by Martins1)
    No, 12t-24=0 was part of the working for part b.

    Part a asked you to differentiate to get 6t^2 - 24t + 7
    Part b asked you to find the time when acceleration was equal to 0.
    Therefore, acceleration= 6t^2 - 24t + 7 differentiated to get 12t-24=a
    when a = 0, 12t-24=0
    12t=24
    t=2
    therefore the time was 2 seconds.
    You quoted the wrong person, I'm agreeing with you.


    Posted from TSR Mobile
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    [QUOTE=sgsb0y;65220281]Yeah because velocity is speed in a given direction, it won't require a double differentiation. Acceleration requires another differentiation. 👍




    yesss )
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    [QUOTE=sgsb0y;65220281]Yeah because velocity is speed in a given direction, it won't require a double differentiation. Acceleration requires another differentiation. 👍

    Yeah part A wouldn't be 2 marks if it was that complicated
 
 
 
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