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# Edexcel IGCSE Mathematics A - Paper 3H - 2016 - Unofficial Mark Scheme Watch

1. (Original post by BOBQ)
On the straight line graph that had to be drawn, did you have to stop at X=3
yes x=3 y=4
2. angle of 105 degrees and sides of 8cm and 12cm
3. (Original post by WhiteX)
yes x=3 y=4
Thanks!
4. (Original post by igggy)
Didnt he already have like 1000 or something
you are right
5. (Original post by _Xenon_)
Please help us get together an unofficial mark scheme for the Edexcel IGCSE Mathematics A HIGHER TIER exam today. If you can remember any questions/answers (preferably with question numbers) please post below. Please note that the questions which are currently empty are labelled 'not done' and will be filled in ASAP. Many thanks.

Question 1
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1. Ingredients question.
(a) 750
(b) 30 muffins
Question 2
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2. t is the total number of pens.
x is a small box.
y is a big box.
There are 4 pens in the small boxes and 10 pens in the big ones. I believe the answer was: t = 4x+10y (3 marks)
Question 3
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3. 38
Question 4 (not done)
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4.
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5.
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Question 7 (not done)
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Question 8 (not done)
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8.
Question 9 (not done)
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9.
Question 10
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10. 10.7 degrees (?)
Question 11 (not done)
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11.
Question 12 (not done)
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12.
Question 13 (not done)
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Question 14 (not done)
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14.
Question 15 (not done)
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15.
Question 16
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16. Volume of the vase was 102 cm3.
Working out:
ASF = -
LSF = -
VSF = -
= --- (3 s.f.)
Question 17 (not done)
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17.
Question 18 (not done)
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18.
Question 19 (not done)
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19.
Question 20
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20. x=7, y=-3
Question 21
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21. 25/84
Question 22
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22. 188cm2
[Circle theorems was 63 degrees. Cube and sphere one was 1637 (?)]

If you remember the question numbers please let me know, thanks.
Cube and sphere one was 850?!
Differentiation velocity one was:
(a). 12t-24
(b). 2
6. (Original post by BOBQ)
The first part a) was ds/dt to find the velocity which = 6t^2 -24t + 7

and b) was 2

Yeah but for the first part I think you had to differentiate again because it's dv/ds
7. Question 22 Proof that answer is 188.
8. Does anyone remember the shaded rectangle with circle in the middle question?
9. (Original post by joebarnes123)
Cube and sphere one was 850?!
Differentiation velocity one was:
(a). 12t-24
(b). 2
Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
10. (Original post by Martins1)
Question 22 Proof that answer is 188.
Haha I messed that one up so bad
11. (Original post by joebarnes123)
Cube and sphere one was 850?!
Differentiation velocity one was:
(a). 12t-24
(b). 2

Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
12. (Original post by sgsb0y)
Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
yeah I think part a was 12t^2-24t+7
13. (Original post by sgsb0y)
Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
I'm not entirely sure but I'm fairly confident you had to differentiate the first one a second time because you are finding velocity not speed... And yeah the second part was definitely 2
14. (Original post by sgsb0y)
Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
The first part a) said to find VELOCITY which is speed / time or ds/dt

so you differentiated the equation s = 2t^3 + 12t^2 + 7t

which = 6t^2 + 24t + 7

b) was to find ACCELERATION which = dv/dt when velocity = 0

which =2
15. (Original post by sgsb0y)
Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
no! I don't agree with you, for velocity you only differentiate once, then for acceleration you do again!
16. (Original post by sgsb0y)
Are you sure a was that was the answer to a? I differentiated the given equation once to get a quadratic-looking equation and for part b I differentiated again to get 12t-24=0 and then I solved it to get t=2.
No, 12t-24=0 was part of the working for part b.

Part a asked you to differentiate to get 6t^2 - 24t + 7
Part b asked you to find the time when acceleration was equal to 0.
Therefore, acceleration= 6t^2 - 24t + 7 differentiated to get 12t-24=a
when a = 0, 12t-24=0
12t=24
t=2
therefore the time was 2 seconds.
17. (Original post by robellie77)
yeah! I agree with you, for velocity you only differentiate once, then for acceleration you do again!
Yeah because velocity is speed in a given direction, it won't require a double differentiation. Acceleration requires another differentiation. 👍

Posted from TSR Mobile
18. (Original post by Martins1)
No, 12t-24=0 was part of the working for part b.

Part a asked you to differentiate to get 6t^2 - 24t + 7
Part b asked you to find the time when acceleration was equal to 0.
Therefore, acceleration= 6t^2 - 24t + 7 differentiated to get 12t-24=a
when a = 0, 12t-24=0
12t=24
t=2
therefore the time was 2 seconds.
You quoted the wrong person, I'm agreeing with you.

Posted from TSR Mobile
19. [QUOTE=sgsb0y;65220281]Yeah because velocity is speed in a given direction, it won't require a double differentiation. Acceleration requires another differentiation. 👍

yesss )
20. [QUOTE=sgsb0y;65220281]Yeah because velocity is speed in a given direction, it won't require a double differentiation. Acceleration requires another differentiation. 👍

Yeah part A wouldn't be 2 marks if it was that complicated

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