Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    1
    ReputationRep:
    64/5 for 90 UMS, anyone agree??
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by lucabrasi98)
    I don't understand why it isn't just your smallest value from the previous question?
    Look at the fraction; it has an additional sin(theta) on the bottom. You can recalculate R and alpha, or just change it to be Rcos(theta-alpha) instead of plus.
    Offline

    2
    ReputationRep:
    (Original post by sandybeach1996)
    guys am I counting this right? somebody please help me we need 480 ums for an A, I has 251 from AS , that means I need 229 across C3 C4 M1 ? I think I got 55 marks in M1 , same in C3 , does that mean I need 89 ums in C4 to still get an A??? how many marks approximately is 89 ums? can I still get the A? PLEASE help
    am reposting until somebody helps me
    That's correct - 89 UMS tends to vary a bit, it has been around 65 (2014), and 69 (2015 for 90 UMS, 89 didn't exist). I'd suggest 68 + in C4 should do it
    Offline

    4
    ReputationRep:
    (Original post by ShatnersBassoon)
    Wait. Your first post made it sound as if you differentiated the original fraction (and subbed in 3) with your calculator but didn't write any working out down.

    If you differentiated the original fraction manually (quotient rule with a quartic - nasty but possible), full marks in part (b) for definite.
    If you differentiated the quadratic but with A and B in place of the values 3 and 4, probably but not necessarily full marks for part (b). If you differentiate, A goes away but B does not, and you can't just retroactively work out its value from your calculator and get full credit. You might lose up to 3 marks.
    If you differentiated the quadratic with 3 and 4 (regardless of where you obtained the numbers), or later replaced A and B with 3 and 4 and differentiated again, probably full marks in part (b).
    No, i think your original understanding of what I did was right- but for the first line of my working for part b, I wrote f(x)= x^2 +3 +4/(x+2) (or whatever it was) - then i differentiated this manually and did the rest of the question as you normally would.
    I know I didn't work out the values of A and B properly, but surely this part is only being assessed in part a? Since I did get the values (using a sly method, but again, this only relates to part a really), and then differentiated with numerical values of a and b, surely i'll get full? i'm hoping so anyway..
    Offline

    3
    ReputationRep:
    (Original post by lucabrasi98)
    How the should we know? Grade boundaries haven't been released yet. Go and look at past papers of similar difficulties to this one then look at the raw mark to ums convertor on EDEXCELs website.


    Or look at a random guess someone has made for grade boundaries

    Or draw your own conclusions from the C3 exam poll. The physics one had a nice bell curve but for C3 a significant amount found it hard or very hard

    I don't understand why it isn't just your smallest value from the previous question?
    WOW! idiota ! i asked for help not a lecture, i didn't say u were psychic , i asked for help, if you cnt help then don't reply , BLEH BLEH BLEH
    Offline

    3
    ReputationRep:
    (Original post by yellownectarine)
    89 UMS is around 67 ish for C4 maybe? (rough estimate)
    Hi ,
    thanks , i doubt that's possible to only lose 8 marks but still going to try . Thanks for your help
    Offline

    3
    ReputationRep:
    (Original post by callum9977)
    That's correct - 89 UMS tends to vary a bit, it has been around 65 (2014), and 69 (2015 for 90 UMS, 89 didn't exist). I'd suggest 68 + in C4 should do it
    Thanks , 68+ is barely possible for me , I have no choice tho
    Offline

    14
    ReputationRep:
    (Original post by sandybeach1996)
    WOW! idiota ! i asked for help not a lecture, i didn't say u were psychic , i asked for help, if you cnt help then don't reply , BLEH BLEH BLEH
    lol says the one that can't spell
    Offline

    2
    ReputationRep:
    It can't be because no value of E will ever be 0, so it has to be the turning point of the other bit

    Posted from TSR Mobile
    Offline

    4
    ReputationRep:
    (Original post by Patrick Gekko)
    No, i think your original understanding of what I did was right- but for the first line of my working for part b, I wrote f(x)= x^2 +3 +4/(x+2) (or whatever it was) - then i differentiated this manually and did the rest of the question as you normally would.
    I know I didn't work out the values of A and B properly, but surely this part is only being assessed in part a? Since I did get the values (using a sly method, but again, this only relates to part a really), and then differentiated with numerical values of a and b, surely i'll get full? i'm hoping so anyway..
    Okay. Then I think we're agreed that you should get full marks in part (b). But correct answer is not full marks. In fact, it's not guaranteed to get you any marks. If you didn't show a valid method (long division or factorisation by sight) in part (a), you might not have got anything. If you did show that in one of your several attempts at getting the right answer, then you've definitely got a method mark or two and depending on exactly what you wrote down you could get full marks.
    Offline

    21
    ReputationRep:
    (Original post by sandybeach1996)
    guys am I counting this right? somebody please help me we need 480 ums for an A, I has 251 from AS , that means I need 229 across C3 C4 M1 ? I think I got 55 marks in M1 , same in C3 , does that mean I need 89 ums in C4 to still get an A??? how many marks approximately is 89 ums? can I still get the A? PLEASE help
    am reposting until somebody helps me
    Woah, firstly chill. Panicking is literally the worst thing you can do right now.

    Yes, you need 229 UMS across C3,C4 and M1 for the A.

    55/75 in M1 is approximately 75 UMS - its usually 50/51 for a B and around 59/60 for an A (however given how tricky M1 was this year, it could be lower - so you could have 77/78 us)

    I haven't seen the paper yet (this one) but based off the worked solutions PDF, and how people have responded to the paper (and whatever questions my sibling told me) I would predict around 59/60 for an A, and 51/52 for a B, so 55/75 on C3 will probably net you around 73-75 UMS.

    Basically for C3 and M1 you should assume an average of 75 UMS on each paper, it may be give or take a few UMS when the boundaries come out. That puts you on 150 UMS. Since its only 229 UMS you need for an A, you need 79 UMS on C4 to get an A.

    Remember this is just an estimate though, your UMS will depend on the grade boundaries. So aim for as high a mark as possible on C4. So basically you need to getting 59/75 and up to realistically be hitting your C4 target.
    Offline

    2
    ReputationRep:
    (Original post by sandybeach1996)
    Thanks , 68+ is barely possible for me , I have no choice tho
    Never say never, still a few days - just do as many past papers as possible, Good Luck!
    Offline

    3
    ReputationRep:
    I think 55 marks for C3 and 55 marks for M1 , from last year those should be 76 ums each roughly so i figured i d need 89 ums in C4 , that's crazy high
    Offline

    3
    ReputationRep:
    (Original post by Fas)
    Woah, firstly chill. Panicking is literally the worst thing you can do right now.

    Yes, you need 229 UMS across C3,C4 and M1 for the A.

    55/75 in M1 is approximately 75 UMS - its usually 50/51 for a B and around 59/60 for an A (however given how tricky M1 was this year, it could be lower - so you could have 77/78 us)

    I haven't seen the paper yet (this one) but based off the worked solutions PDF, and how people have responded to the paper (and whatever questions my sibling told me) I would predict around 59/60 for an A, and 51/52 for a B, so 55/75 on C3 will probably net you around 73-75 UMS.

    Basically for C3 and M1 you should assume an average of 75 UMS on each paper, it may be give or take a few UMS when the boundaries come out. That puts you on 150 UMS. Since its only 229 UMS you need for an A, you need 79 UMS on C4 to get an A.

    Remember this is just an estimate though, your UMS will depend on the grade boundaries. So aim for as high a mark as possible on C4. So basically you need to getting 59/75 and up to realistically be hitting your C4 target.

    59/75 ? not 68? some people are saying 68 marks ?
    Offline

    0
    ReputationRep:
    Do you think grade boundaries will be 64-A* 58-A 52-B?
    Or will be a bit higher/lower?
    Offline

    21
    ReputationRep:
    (Original post by sandybeach1996)
    59/75 ? not 68? some people are saying 68 marks ?
    You got 251/300 in AS correct?

    Because of that 11-mark buffer you got in AS, you will need approximately 59-60/75 on C4 to get 79/100 UMS.
    Online

    19
    ReputationRep:
    Having just done some solutions (no calculator so not done a lot of specifics and I see others have uploaded anyway so no point posting), certainly a relatively time consuming paper. Actual questions fairly standard though.
    Offline

    2
    ReputationRep:
    So how many marks do we reckon a B/A/A* will be then?
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by 13 1 20 8 42)
    Having just done some solutions (no calculator so not done a lot of specifics and I see others have uploaded anyway so no point posting), certainly a relatively time consuming paper. Actual questions fairly standard though.
    That's what I thought, questions were obscure but pretty average. Fortunately I had time to check, and store my answers in calculator memory
    Offline

    3
    ReputationRep:
    (Original post by Fas)
    You got 251/300 in AS correct?

    Because of that 11-mark buffer you got in AS, you will need approximately 59-60/75 on C4 to get 79/100 UMS.
    thanks , i really thought i needed 89 ums and that was just impossible no i have hope
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Brexit voters: Do you stand by your vote?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Write a reply...
    Reply
    Hide
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.