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AQA A2 MFP3 Further Pure 3 – 18th May 2016 [Exam Discussion Thread]

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Original post by JahJah
That exam was quite ridiculous compared to all the past papers. I thought that some of the maths was quite fun like (cosa+sina)^2= 1+root3/2
But some was just ridiculously hard. Like I don't think I did very well on that polar coordinates question that converted it into Cartesian. For that question did anyone get the transformation as 4 in positive X axis ?


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Yes, that is the answer my whole group got.
Original post by Adam_98
54 enough for a B?


54 for FKiNG 100
Reply 482
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JahJah
2
Ah okay thank you. I know in the form the question have it it made it look like the curve was an ellipse, when in fact the value I got for d was negative, making it a hyperbola. I think my value of d was -25/4. I'm pretty sure I was incorrect on this though as it seemed quite unlikely the Question would mislead you on that. What did you get for d ?


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Original post by JahJah
Ah okay thank you. I know in the form the question have it it made it look like the curve was an ellipse, when in fact the value I got for d was negative, making it a hyperbola. I think my value of d was -25/4. I'm pretty sure I was incorrect on this though as it seemed quite unlikely the Question would mislead you on that. What did you get for d ?


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One was 20 and one was 36. No negatives. Do you remember what the polar equation was?
(edited 7 years ago)
Worst exam of my life :frown:
Does anyone have the paper or remember the 'impossible integral'?
Original post by SherlockHolmes
Does anyone have the paper or remember the 'impossible integral'?


What you on about? The x^-7lnx?

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Original post by SherlockHolmes
Does anyone have the paper or remember the 'impossible integral'?


Let p= 1/a

Lim(Ln(p)/p) as p approaches infinity

So a approaches 0

Replacing p with 1/a and using log laws you get one of the quoted limits in the spec
Original post by SherlockHolmes
Does anyone have the paper or remember the 'impossible integral'?


It was lnx/x^7 with limits infinity and 1 I believe.
How many marks was the Maclaurin expansion 2.080 thing

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ninya98
Original post by C0balt
Well I got something like 2.0779 and rounded to 2.078 or something like that for the Maclaurin I have no idea what I did wrong


I got that as well :/
Original post by Barbecuetime123
Let p= 1/a
Yea
Lim(Ln(p)/p) as p approaches infinity

So a approaches 0

Replacing p with 1/a and using log laws you get one of the quoted limits in the spec

Is the value of it just 0?
Well, gap year it is...

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Well, suicide it is...
Original post by CoIIins
Is the value of it just 0?


Yes, then you had to use that limit because you got something in that form from the integration by parts. Final answer 1/36
Pretty funny, https://www.youtube.com/watch?v=FDhGCsrwSzw
Original post by CoIIins
Is the value of it just 0?


I think so.

What did people get for the Euler and maclaurin, I got 2.081 and 2.080
(edited 7 years ago)
Can't wait for FP2 now.....

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Original post by Barbecuetime123
I think so.

What did people get for the Euler and maclaurin, I got 2.085 and 2.080


Do you remember how many marks was Maclaurin

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Original post by Adam_98
Can't wait for FP2 now.....

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Said no one, ever

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