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    (Original post by its_samuel)
    How did you guys manage to find x in the perimeter question?!

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    find the first differential and make it equal to zero and solve for x.
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    how long will it approx. take for an unofficial mark scheme to come out?
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    Peole have been saying we had to substitute the x value back in to find the value of the perimeter (which gives P=120ish) but I don't remember the question requiring this. I remember it saying onky find x to the nearest m. What does everyone reckon? Did we need to sub x back in to find Perimeter?
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    (Original post by DW4)
    I got -2.19. Anyone else??
    yh I got that too
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    (Original post by Skylarkman)
    Peole have been saying we had to substitute the x value back in to find the value of the perimeter (which gives P=120ish) but I don't remember the question requiring this. I remember it saying onky find x to the nearest m. What does everyone reckon? Did we need to sub x back in to find Perimeter?
    It said find minimum value for P.
    Therefore you had to sub x= back in
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    (Original post by Skylarkman)
    Peole have been saying we had to substitute the x value back in to find the value of the perimeter (which gives P=120ish) but I don't remember the question requiring this. I remember it saying onky find x to the nearest m. What does everyone reckon? Did we need to sub x back in to find Perimeter?
    NO the question stated find the minimum value of P. to do this you had to find x then sub it into P to get 120
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    (Original post by DW4)
    There was no question 10!
    Yeh the one about proving the sum of a series is ....
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    (Original post by Skylarkman)
    Peole have been saying we had to substitute the x value back in to find the value of the perimeter (which gives P=120ish) but I don't remember the question requiring this. I remember it saying onky find x to the nearest m. What does everyone reckon? Did we need to sub x back in to find Perimeter?
    yes as the question asked for the minimum value of P.
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    in general how did youse find the exam? and do you think the grade boundaries will be high or low?
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    (Original post by unifiedfield)
    Pretty sure B was one thousand and something
    I got -1584 for B, 16 for A and k as 7/2
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    After realising the silly errors that I made in that paper. I regret the fact that I didn't complete it quicker as that would allow me to carefully look through my answers and make corrections if necessary does anyone remember question 6. A involves trig equation looks similar to this 1-2(pi/4+sinx)=0?
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    Anyone have a copy of the paper and/or questions and/or anwers. With the questions I can do a mark scheme.
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    (Original post by jack potato)
    I got the same but I left my answers to 1 decimal place...(x=16.6 and p=120.something) did the question ask to leave the answers as integers? would I still get full marks for that question?
    I prefer to work with more decimal places to make sure my answer is accurate. I think the question said "give your answer to the nearest meter" so I left it as P = 120
    You'll probably still get the marks because the mark schemes usually accept answers that round to the correct answer
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    (Original post by HeenaChowdry)
    how many marks would i lose for the first trig questions, if I only found 1 correct value
    probably just one
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    (Original post by unifiedfield)
    Pretty sure B was one thousand and something
    I think it was:

    -288k + 1944 = B
    but k=7/2
    -288(7/2) + 1944 = B
    -1008 + 1944 = B
    therefore B = 936
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    (Original post by Skylarkman)
    Peole have been saying we had to substitute the x value back in to find the value of the perimeter (which gives P=120ish) but I don't remember the question requiring this. I remember it saying onky find x to the nearest m. What does everyone reckon? Did we need to sub x back in to find Perimeter?
    They didn't ask us to find x, they asked for the perimeter which we can only work out once we've found x, so yes we needed to substitute x into P.
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    This C2 exam went really well for me

    k= 7/2 and B was like 936.
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    (Original post by AlonsoAMG)
    Yeh the one about proving the sum of a series is ....
    ??
    You talking about question 1?
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    (Original post by mani119)
    It said find minimum value for P.
    Therefore you had to sub x= back in
    you must sub in the value of x into the 2nd order derivative so d^2p/dx^2 that will give you what your looking for if it is >0 then it is a minimum <0 it is a maximum.
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    (Original post by DW4)
    ??
    You talking about question 1?
    He's trying to troll by saying there was a question 10 when there wasn't
 
 
 
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