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# Edexcel FP3 June 2015 - Official Thread watch

1. (Original post by chemlover12)
Oh nice!
Thanks, hey, im done with what i intended to do, gonna head to bed.

The mods will probably delete our posts [ sorry mods] , nice chatting to you, see yah around for sure ^^
2. (Original post by ninjasinpjs)
Thanks, hey, im done with what i intended to do, gonna head to bed.

The mods will probably delete our posts [ sorry mods] , nice chatting to you, see yah around for sure ^^
Night night!

Lol. It was nice talking to you too Yea XD
3. hey guys.. anyone who tried june 2014 question 7, why multiply the surface by 2 when they say its rotated through pi radians?
and part c, i cant figure out why its pi/2 without any working. its just 1 mark
4. HELP! I learnt Vectors yesterday and I'm learning the second half of Matrices today. Does anyone know a way where I can find good practice questions that will prepare me for tomorrow other than past papers? 80-85 UMS will suffice. Who knows the best way to prepare for the exam? I'm in dire need of some sort of adequate preparation.
5. For 2013R question 3, my equation was already in the required circle form at the end of part b. But this is not given in the mark scheme, even though I did it algebraically (not assuming it was a circle or anything like that) and the question just says "find a Cartesian equation". This seems a bit stupid, and what am I supposed to say in part c; "this is the equation of a circle so it's a circle"?
6. (Original post by A*desperate!)
hey guys.. anyone who tried june 2014 question 7, why multiply the surface by 2 when they say its rotated through pi radians?
and part c, i cant figure out why its pi/2 without any working. its just 1 mark
b) general area of circle = 2pi(r)^2 so in this case area of circle 2pi x integral by given formula.
edit: oops sorry. ignore this ^

c) general formula: y= squrt(r^2 - x^2) in part c they gave y=squrt(1-x^2) so the radius is one. If you draw a circle with the radius 1. You can clearly see the angle between when x=0 and x=1 is pi/2.
7. (Original post by Abel Demoz)
HELP! I learnt Vectors yesterday and I'm learning the second half of Matrices today. Does anyone know a way where I can find good practice questions that will prepare me for tomorrow other than past papers? 80-85 UMS will suffice. Who knows the best way to prepare for the exam? I'm in dire need of some sort of adequate preparation.
Some people on this thread have been looking at the questions in the Review exercise of the FP3 textbook so maybe you could have a look at them.
8. (Original post by chemlover12)
b) general area of circle = 2pi(r)^2 so in this case area of circle 2pi x integral by given formula.

c) general formula: y= squrt(r^2 - x^2) in part c they gave y=squrt(1-x^2) so the radius is one. If you draw a circle with the radius 1. You can clearly see the angle between when x=0 and x=1 is pi/2.
Someone's never heard the Circle Song...
9. (Original post by Elcor)
Someone's never heard the Circle Song...
lol oops -.-'
10. (Original post by chemlover12)
b) general area of circle = 2pi(r)^2 so in this case area of circle 2pi x integral by given formula.
edit: oops sorry. ignore this ^

c) general formula: y= squrt(r^2 - x^2) in part c they gave y=squrt(1-x^2) so the radius is one. If you draw a circle with the radius 1. You can clearly see the angle between when x=0 and x=1 is pi/2.
oh I'll go through that again now, thank you! !
11. (Original post by A*desperate!)
hey guys.. anyone who tried june 2014 question 7, why multiply the surface by 2 when they say its rotated through pi radians?
and part c, i cant figure out why its pi/2 without any working. its just 1 mark
Because in question you should rotate full circle around x-axis for pi radians (which would give you a sphere), not just the part that is above x-axis (which gives you half-sphere). However, you are allowed to use integral formula for surface only for function. Therefore you use symmetry and multiply by 2.
12. Does anyone have the examiners report for June 2014?

Posted from TSR Mobile
13. (Original post by BP_Tranquility)
Does anyone have the examiners report for June 2014?

Posted from TSR Mobile
http://qualifications.pearson.com/co...-June-2014.pdf

it says FP1 but it's actually FP3
14. (Original post by TeeEm)
no worries ... I get more pleasure when people use my stuff.
in your reduction formula booklet, question 17, it says in the question sqt(1+x^2)
but in the solution it solves it with sqt(1-x^2).
in question 18, the position of In and I(n+1) in the question is different. (doesn't match solution)
15. (Original post by 13 1 20 8 42)
For 2013R question 3, my equation was already in the required circle form at the end of part b. But this is not given in the mark scheme, even though I did it algebraically (not assuming it was a circle or anything like that) and the question just says "find a Cartesian equation". This seems a bit stupid, and what am I supposed to say in part c; "this is the equation of a circle so it's a circle"?
As long as your final answer is in the form (x-a)^2 + (y-b)^2 = c then yes lol just say its in the form of an equation of a circle and that should get you the marks, though it seems you did parts of (c) in (b)
16. (Original post by 13 1 20 8 42)
For 2013R question 3, my equation was already in the required circle form at the end of part b. But this is not given in the mark scheme, even though I did it algebraically (not assuming it was a circle or anything like that) and the question just says "find a Cartesian equation". This seems a bit stupid, and what am I supposed to say in part c; "this is the equation of a circle so it's a circle"?
Yeah it's a silly question because you're meant to stop in (b) as soon as you get an equation, but the primal mathematician instinct in all of us wants to simplify it there and then...
17. (Original post by 13 1 20 8 42)
For 2013R question 3, my equation was already in the required circle form at the end of part b. But this is not given in the mark scheme, even though I did it algebraically (not assuming it was a circle or anything like that) and the question just says "find a Cartesian equation". This seems a bit stupid, and what am I supposed to say in part c; "this is the equation of a circle so it's a circle"?
would be nice to see some working
18. (Original post by rachu)
in your reduction formula booklet, question 17, it says in the question sqt(1+x^2)
but in the solution it solves it with sqt(1-x^2).
in question 18, the position of In and I(n+1) in the question is different. (doesn't match solution)

thank you

I will try to look at them tonight
19. (Original post by ninjasinpjs)
would be nice to see some working
20. (Original post by TeeEm)
thank you

I will try to look at them tonight
thank you for the questions .. they were fun to solve and look at your method of solving. I had never thought of using those addition trig identities. . I just solved them long way. Your method is faster.

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