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AQA AS Physics Unit 2 (PHYA2) June 9th 2016 Resit paper watch

1. (Original post by mbh16)
i just put the equation, then said that if the frequency was less than the fringe spacing decreases so you would see a small peak either side of the main peak
i said something similar, that you would see more waves between A and B because the width was smaller and cause higher frequency theres more between A and B?
dunno what you mean by frequency less so fridge space is less, do you mean frequency is higher?
2. (Original post by Selborn)
we got given refractive index an you needed to use n=C/Cs I believe
i did that but it then asked for the new wavelength . it gave us another wavelength .
3. (Original post by jamestordoff)
i did that but it then asked for the new wavelength . it gave us another wavelength .
yeah i just used like ratios to find that like for in the core and for in air, is that what you did? can't remember my answer though
4. (Original post by jamestordoff)
i did that but it then asked for the new wavelength . it gave us another wavelength .
It's just: n=lambda/lamda(substance)
5. (Original post by txnilxnur)
yeah i just used like ratios to find that like for in the core and for in air, is that what you did? can't remember my answer though
great , i think the wavelength they gave us was something point something times ten to the minus 9 and my new wavelength was something point something times ten to the minus 7
6. (Original post by jamestordoff)
great , i think the wavelength they gave us was something point something times ten to the minus 9 and my new wavelength was something point something times ten to the minus 7
wasn't it 1300nm which is 1300 x10 9m
7. (Original post by the_chosen_one97)
It's just: n=lambda/lamda(substance)
by n do you mean the refractive index , i dont understand where in the spec it says that sorry i must have it wrong then . do you think my answer will still be right .,
8. Would the final speed of the empty lorry be higher as its driving force will be constant, therefore as m has decreased a would increase. As its the same time period a = v/t would therefore meaning it had a greater final speed?
9. (Original post by GeorgeWhite2)
wasn't it 1300nm which is 1300 x10 9m
i dont know i thought nm meant nano metres and so was x10-9
10. (Original post by jamestordoff)
great , i think the wavelength they gave us was something point something times ten to the minus 9 and my new wavelength was something point something times ten to the minus 7
yeah I'm certain mine to the minus 7 too. can't even remember what the other questions were.. what were the questions after the 6 marker cause I'm sure there were some more on the same question
11. (Original post by jamestordoff)
i dont know i thought nm meant nano metres and so was x10-9
Thats what I meant, i knew what i typed looked wrong for some reason - forgot the minus sign.
12. (Original post by henry.philips)
Would the final speed of the empty lorry be higher as its driving force will be constant, therefore as m has decreased a would increase. As its the same time period a = v/t would therefore meaning it had a greater final speed?
i put that but im not sure if its right . loads of people are saying the terminal velocity is the same as the water lorry
13. (Original post by jamestordoff)
by n do you mean the refractive index , i dont understand where in the spec it says that sorry i must have it wrong then . do you think my answer will still be right .,
Yes, you can use n=c/c(substance) and n=lambda/lambda(substance) - basically ratios. I can't remember what the refractive index was exactly but I'll use 1.42 as an example. The answer was 1300x10^-9 / 1.42 = 9.1x10^-7 or something very similar
14. (Original post by jamestordoff)
i dont know i thought nm meant nano metres and so was x10-9
(Original post by GeorgeWhite2)
wasn't it 1300nm which is 1300 x10 9m
nanometres is x10^-9 !! not 9
15. (Original post by txnilxnur)
yeah I'm certain mine to the minus 7 too. can't even remember what the other questions were.. what were the questions after the 6 marker cause I'm sure there were some more on the same question
im not sure its all a blank to me hahahah
16. (Original post by the_chosen_one97)
Yes, you can use n=c/c(substance) and n=lambda/lambda(substance) - basically ratios. I can't remember what the refractive index was exactly but I'll use 1.42 as an example. The answer was 1300x10^-9 / 1.42 = 9.1x10^-7 or something very similar
i think i got that so everyones a winner winner chicken dinner
17. (Original post by jamestordoff)
i put that but im not sure if its right . loads of people are saying the terminal velocity is the same as the water lorry
I said the speeds at the end were equal but the leaking lorry accelerated faster therefore covering more distance in the same time period as the other lorry.
18. (Original post by jamestordoff)
im not sure its all a blank to me hahahah
same lol
19. (Original post by Selborn)
I said the speeds at the end were equal but the leaking lorry accelerated faster therefore covering more distance in the same time period as the other lorry.
yeah but a fat man in a car cant reach the same speed as a skinny guy in a car if their resultant forces are the same can they ?
20. (Original post by Physicsretake)
anyone want to sign a petition to get the grade boundries lowerd drastically so 50% is an A, seems a reasonable thing to do....
Uhh no..
1. why would the AQA give a **** if 300 students said that it should be lowered? They put the grade boundaries at a level that accurately reflects skill level of the student.
2. The grade boundaries will probably be low anyway as it was slightly harder than previous years.

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