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# Edexcel Unit 4: Physics on the Move 6PH04 (11th June 2015) watch

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1. going to need 101% UMS in unit 5 now
2. Anyone else get a voltage of 1.5v for the first capacitor question?
3. Yeah it was hahah
4. (Original post by LukeBarnett)
Anyone else get a voltage of 1.5v for the first capacitor question?
I got 15V and not 1,5V. Sorry
5. (Original post by LukeBarnett)
Anyone else get a voltage of 1.5v for the first capacitor question?
I got 15V for the emf.
6. (Original post by daniel666545)
hello, your answers seem right, however, question 14 is a bit different. The probe ejects empty fuel tanks by a explosion. therefore, there is energy lost to heat ( from the explosion ) and energy is not conserved.
this is what I said
7. (Original post by LukeBarnett)
Anyone else get a voltage of 1.5v for the first capacitor question?
no
8. (Original post by bbyturtlexox)
no
Damn, must have missed a multiple of 10 out somewhere along the lines in calculations
9. (Original post by bbyturtlexox)
this is what I said
10. (Original post by iceangel8)
I got 15V for the emf.
The Voltage was 15 V and the Energy then was 2.48 x 10^-2 J.
11. (Original post by justthatprick)
I got an unconditional from LSE, I don't even need to apply for student finance got all the money to pay for my 4 year course already under my mattress. £3000? I use £3000 to light up my cigars while I'm waiting on my butler to bring the next round of Jamon Iberico de bellota.

Also, why report my post? I'm expressing my opinion on the exam, the same as you :*
ayyy lmao troll.

I am happy with what I have got, so stfu, stop boasting and stop trolling
12. (Original post by LukeBarnett)
Damn, must have missed a multiple of 10 out somewhere along the lines in calculations
Yeah probably. What energy stored in the capacitor did you get?
13. **** all you ********s saying it was easy go suck ur nans.
14. (Original post by Nimnam7)
**** all you ********s saying it was easy go suck ur nans.
My teacher said she thought it was the hardest paper she had ever seen, HOWEVER i think she was just saying that so we would not be paranoid over the rest of the exam period and the summer
15. (Original post by blueynuey1)
GUYS THERE IS MASSIVE DOUCHE WHO KEEPS DELETING DOC

HERE IS WORK DONE SO FAR:

unidentified questionstuff from MC Questions:
• Force was F/2 of initial value. +2
• The conclusion you can’t make from Alpha Particle Experiment = That Nucleus contains Protons and Neutrons. +2
• High energies required to make particles with large mass
Which question was the one about the difference between a uniform electric field and an electric field due to a point charge?you had to draw a diagram of the electric field between 2 parallel plates and of a point charge. and then compare the electric field strength of them. I.e. Point Charge: E (proportional) 1/r^2. And E = constant for the parallel plates.Diagram: http://www.revisionworld.com/sites/r...------Question 1. Number of neutrons in a Uranium atom (Z = 92, A= 238) +1
Question 2.
Question 3. If a pennis travels at 5 ms what is its momentumQuestion 4. Question 5. Question 6. Question 7.mv2=p2/mQuestion 8. Question 9. Question 10. Question 11. a. Draw the direction of current in the copper rod. Down. +7 b. State the direction of magnetic field that will cause the rod to move to the right.Into the page. +5
Question 12. Particle physics - identify pion minus quark composition
1. anti up, strange? Pion minus have no strange quarks (http://en.wikipedia.org/wiki/Pion)+1 Down anti-up +4
2. 140MeV/c2 → 2.49 * 10^(-28) +8
Question 13. This was about the boy in the merry-go-round thing. Find the minimum time taken for the boy to complete one revolution given that the boy's mass is 20 kg and the size of the frictional force is 0.35*(weight of the boy). The second part was: Explain how the time changes if a child of greater mass sits on the merry-go-round.
1. time = 3.08s +10
2. independent to mass +7
b explanation -> F = μmg = mrω² therefore μg = rω² so ω independent of mass so T independent of mass

Question 14. This was the 6 marks question about the probe in space. Discuss whether conservation of momentum and energy applies and why its speed increased.Space probe momentum question*Answer from previous MS - http://puu.sh/ikFJk/a2e6029c79.png+1 TE = KE + PE. When KE increases, PE decreases. Idk. TE constant. Chemical energy transferred to heat and light?Question 15. θ = 41 +3 T = 0.895632 N, T=0.035? +4 Tension = √[mg^2 + F^2]. Where mg = weight of one of the balls. And F = the electrostatic force between the balls (from coulombs law).Then θ = tan-1(o/a) = tan-1(mg/F) = 41°.

Question 16. A question about capacitors. A circuit diagram of a battery and capacitor connected in series was given. The capacitance was 220 nF and the charge on each plate was 3.3 uC, with one having a plus sign and the other a minus sign. a) Calculate the voltage of the battery and the energy stored by the capacitor.b) Calculate the time taken for the capacitor to discharge 80% of its charge.c) Use and equation to determine whether the time taken for the energy stored in the capacitor is greater than or less than the time taken for the charge on the capacitor to halfd) State two advantages of using a data logger to measure the voltage on the capacitor instead of a voltmeter and a stopwatch.a) V= Q/C = (3.3 x10-6)/(220 x10^-9) = 15v energy=2.475*10^-4 J +4R = 20MΩ?
b) Find the time for capacitor to discharge to 0.2 (0.8 through the capacitor) RC = τ = 20*106 * 220*109 = 4.4s Q0/Q= 5 (is it not 0.7). Sorry, put Q and Q0 the wrong way around. It’s correct now.Therefore t = 4.4 ln(5) ≡ -4.4 ln(0.2) = 7.08 s. +2
d)
• Reduced/ gets rid of human error in measuring time
• Means that many measurements can be taken - as voltage changes very quickly for a discharging capacitor.
+1

c) Because and C is constantHence E = kQ2for E become 1/2 EQ need to become 1/√2 Q 1/√2 ≈ 0.7 (≈0.689)Q reaches 0.7Q0 before reaching 0.5Q0Q reaches 0.7Q0 = Energy reaches halfTEnergy reaches half < TCharge reaches half //Let’s use this as the answer since the English language is confusing?
So the time is less for the energy to decrease by half+2
Question 17. Part 1: State what is meant by Faraday's law.
• Emf induced is directly proportional to the rate of change of flux linkage in a system
• = ᐃΦ/ᐃtI., so EMF is directly proportional to the change in flux linkage and indirectly proportional to change in time.
Part 2: A diagram of a magnet hung vertically (with N at the bottom and S at the top) on a spring with it placed inside a copper ring was given. The question was: The magnet is displaced and then let go. It oscillates. Why does this produce an alternating current in the ring?
• Change in B field
• alternates as magnet oscillates up and down
• Rate of change of flux greatest when speed of magnet greatest
• meaning a maximum current
Part 3: The given value was 0.035 Ts^-1 Which is (n(BA))/Time Therefore A = GIVEN RADIUS^2*PI So EMF = 0.035*pi*radius^2EMF = I(r +R) but as there is no internal resistance, r=0 so EMF = IRTherefore divive the emf/given resistance Gives Currrent = 4.01A +6 I = 4.10 A ?

Question 18. Show that B = 2fme.From formula sheet:r = mV/BQ and v = ωr and ω = 2π/T = 2πf
B = mV/Qr = mω/e = m2πf/el
Question 19.Question: Describe and explain the events shown in Photograph?-Charged particle collision with proton created two particles, one charged and one neutral-Charged particle goes along path of X-Neutral particle travels from X to Y-Neutral particle leaves no track as no charge (only charged particles show in bubble chamber)-Neutral decays into matter/anti matter pair at Y as tracks are equal (radius of curvature) but in opposite directions (momentum conserved) so mass is same for both but opposite charges
I wrote down all the answers i gave for the 10 multiple choice questions:

1. B.
2. D.
3. B.
4. D.
5. A.
6. B.
7. B
8. D.
9. B
10. C.
However, i do not know the questions any more by heart.
16. For roundabout question- it said frictional force was weight of the boy x 0.35. Weight was 20g so 0.02 x 9.81 = weight, x 0.35 = frictional force... right?
17. (Original post by jay_em)
For roundabout question- it said frictional force was weight of the boy x 0.35. Weight was 20g so 0.02 x 9.81 = weight, x 0.35 = frictional force... right?
Seems right. And this force is equal to the equation.
18. (Original post by daniel666545)
I wrote down all the answers i gave for the 10 multiple choice questions:

1. B.
2. D.
3. B.
4. D.
5. A.
6. B.
7. B
8. D.
9. B
10. C.
However, i do not know the questions any more by heart.
19. (Original post by daniel666545)
Seems right. And this force is equal to the equation.
That frictional force was equal to the centripetal force? F=mv^2/r?
20. (Original post by LukeBarnett)
That frictional force was equal to the centripetal force? F=mv^2/r?
That's what I did, yeah

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