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    does anyone have an idea on how the 4 marks on the end question about area will be distributed?
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    Yeah I got that too but I didn't have time to simplify it so my final answer was root 8000 over 2 (I came out of the exam and simplified it and it would've been 20root5) ..though some people said that's wrong because I used the wrong height (for 1/2xbh area of triangle)...which is why I think some people are saying they got 40??
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    (Original post by Madhutty)
    I would disagree strongly, this seemed like a very average paper to me. The only difficult questions were finding k and the final area question.

    Also it's better to assume you have a lower mark than you actually have so you don't get complacent!


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    Yes!The two questions you mentioned were the two I struggled with!
    Yeah, I'll just forget about C1 now.C2 next!
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    What happens if you don't simplify fractions, is that marks lost automatically? For instance, on the graph I put the x axis point of intersection as 6/4, not 3/2
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    (Original post by MacDaddy101)
    does anyone have an idea on how the 4 marks on the end question about area will be distributed?
    I would like to know this too
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    (Original post by Renzhi10122)
    I think the differentiation one was f'(x)=-3x^2+10x-3 and f(x)=-x^3+5x^2-3x+15? Which is f(x)=(5-x)(x^2+3)
    Any idea how many marks this was??
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    FP1 is cancelled tomorrow
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    (Original post by emiilywest)
    What happens if you don't simplify fractions, is that marks lost automatically? For instance, on the graph I put the x axis point of intersection as 6/4, not 3/2
    how did you get 6/4 ? i got it as (2x-3) so it had to be 3/2
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    (Original post by chloe-jessica)
    Ah thank you! Completely forgot about that quadratic one, the answers I got were -8 and 27 though so I'll go with these as being right Can't remember the differentiation question for the life of me, it was something like f(x)=(x^2+7)(8-x) and you had to find f'(x). I'll edit my post now though, thanks again
    How did you do 9 iii?
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    For the 1/x-2 graph transformation, in my head I suddenly decided it was a 1/x^2 graph and put 1/(x-2)^2, is this going to lose me that mark do you think?
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    (Original post by Charlieukharris)
    I would like to know this too
    Answer to last part of question 10: You had to put x=0 into the ?circle?(not sure if it was a circle or a curve- can't remember) equation and then solve to find Q, to give you a set of coordinates. Then put x=0 into the straight line tangent equation to find R(can't remember if it was P or R) to find the final set of coordinates for the triangle. I then drew the graph and plotted the 3 points. It was not a right angled triangle on its own. Therefore I then drew a line from (8,2)-one of the points, to the y-axis, splitting the triangle into 2 right angled triangles. Then I just calculated the area of the two triangles separately and added them together to get 40 Hope this helps
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    someone pls help with how many marks i have lost
    *for the 2nd q i think, i left an answer as 625root5, instead of writing it as 5^k
    *for some line one i think that i wrote 6x+8y-29=0 (think) instead of -8y
    *for the inequality one, i wrote k as k>25/8 with no minus and sign wrong way round
    *and for same question of the graph, for the values of x>0 i wrote answer with signs wrong way round again
    *and lastly area of triangle, i wrote 40 then crossed it out and wrote 50, but how many marks for finding Q and R, and writing that area=1/2basexheight ?

    thanksss
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    (Original post by ella_chloe)
    how did you get 6/4 ? i got it as (2x-3) so it had to be 3/2
    probably just factorised differently, 6/4 is the same as 3/2 but I'm not sure if they'd lose marks for not changing to simplest form?
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    (Original post by eddy29)
    How did you do 9 iii?
    Put your solution for a back into the differential and make this equal to 0. Factorising this gave you, I think, (3x-1)(x+4) = 0 or something similar, so you know the x coordinate of the other TP is going to be 1/3.
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    less than -25/8
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    (Original post by ella_chloe)
    someone pls help with how many marks i have lost
    *for the 2nd q i think, i left an answer as 625root5, instead of writing it as 5^k
    *for some line one i think that i wrote 6x+8y-29=0 (think) instead of -8y
    *for the inequality one, i wrote k as k>25/8 with no minus and sign wrong way round
    *and for same question of the graph, for the values of x>0 i wrote answer with signs wrong way round again
    *and lastly area of triangle, i wrote 40 then crossed it out and wrote 50, but how many marks for finding Q and R, and writing that area=1/2basexheight ?

    thanksss
    1) Possibly 1 out of 2 for the second question.
    2) Provided your method was right for the line question and it was just a stupid mistake copying down, you should only lose the 1 accuracy mark.
    3) Did you find the discriminant of the equation and make it less than 0? This would be worth method marks.
    4) You might get 1 out of 2. If you drew your graph wrong it might be counted as ecf.
    5) Should only be the 1 lost mark for accuracy again.

    Not 100% sure on these but that's what I'd guess at.
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    (Original post by Exephy)
    probably just factorised differently, 6/4 is the same as 3/2 but I'm not sure if they'd lose marks for not changing to simplest form?
    yeahh i know but was just confused, they should still give you the marks yeah
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    (Original post by qwerty1357)
    less than -25/8
    Phew, I got the same
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    (Original post by eajeaj1997)
    Any idea how many marks this was??
    No sorry, but I don't think it's more than 3 for that part
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    (Original post by Madhutty)
    The question about the stretch of -1/x

    The answer is as follows:

    Stretch
    Scale factor 1/3
    In EITHER direction

    THIS GRAPH (http://puu.sh/hLU2t/a0228020ae.png) shows the pre-stretch graph, and the post-stretch graph.
    So you must state it was a stretch in both the x and y directions? Or will you still get the marks if you say x or y?


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