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    can anyone remember the first question??
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    (Original post by bartbarrow)
    C4
    100 UMS - 66
    A* - 61
    A - 55
    B - 49
    C - 43

    C3
    100 - 70 (maybe 69)
    A* - 62
    A - 55
    B - 51
    C - 46
    D - 41
    E - 36
    ok lol, I completely disagree on c3
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    (Original post by -jordan-)
    Part a)

    2tanϴ = 3x

    Differentiating it implicitly

    2sec^2ϴ * (dϴ/dx) = 3

    (dϴ/dx) = 3/(2sec^2ϴ)
    = 3/(2(1+tan^2ϴ))
    = 3/(2+2tan^2ϴ)
    = 6/(4+4tan^2ϴ)

    And from the question tanϴ=3x/2
    Therefore tan^2ϴ = 9x^2/4
    Putting this into (dϴ/dx) gives

    (dϴ/dx) = 6/(4+4(9x^2/4))
    = 6/4+9x^2 as required

    Part b)

    You had to separate the variables. The first integral had to be done using by parts. The second was from part a, 1/6th of tan^-1(3x/2) because it was the integral of 1/4+9x^2. c came out as pi.


    Ah thanks a lot man i reckon i got 1/2 of the first part.
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    (Original post by lgrg)
    anyone remember the answer for the question that was like 'write in the form Ax+ b +c/ (xxxx)
    I got -3x + 2 +9
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    (Original post by spmenz123)
    Can anyone remember how many marks the binomial expansion question was?
    7 marks
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    (Original post by Viableplayground)
    thought the paper was very nice apart from that last question. Please can someone explain question 8
    See the photo attached
    (Original post by spmenz123)
    Yes, my bad
    Np I just got a little scared there lol

    Posted from TSR Mobile
    Attached Images
     
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    (Original post by koolgurl14)
    Sam I remember checking if it was negative twice when I did it as integration by parts , we all got the same C though
    I'm pretty certain since if you Plug in the x and y values It works.
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    (Original post by jtebbbs)
    I put 330 in the exam and this was my working, couldn't remember the decimals after 8 but that's how you do it I think
    thanks
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    Not a bad paper overall i think, they were very picky with how you put your answers. The vectors question (part c) was tricky but possible if you took your time
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    Did anyone get 1/3 for the gradient ?
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    How many marks will I lose because I put -69/2+9/2ln3 and then simplified it to -69+9ln3.

    I'm stupid and don't know log rules.

    also I put 330.04....w/e the decimals were and then rounded to 331 because that was how I interpreted it wanted rounding to. How many marks will I lose for that? Just one I assume, because I wrote the value then rounded it wrong?
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    Any unofficial mark schemes anywhere?
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    (Original post by 000536)
    How many marks will I lose because I put -69/2+9/2ln3 and then simplified it to -69+9ln3.

    I'm stupid and don't know log rules.

    also I put 330.04....w/e the decimals were and then rounded to 331 because that was how I interpreted it wanted rounding to. How many marks will I lose for that? Just one I assume, because I wrote the value then rounded it wrong?
    1 for each probably
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    (Original post by bartbarrow)
    1 for each probably
    Okay, not too bad but fml for making stupid mistakes like that.
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    I managed to store some of my answers in my calculator (Stats mode is great!), besides the "show that" questions, and this is what I had:

    1)A = -1/2, B = 9/2
    -1 + 7x - 22/3 x^2 + O(x^3)
    -1/2 < x < 1/2

    2)x = 0°, 99.6°, 206.4°

    3)A = -3, B = 2, C = 9
    p = -69/2 (lol), q = 9/2

    4) m = 181g, t_1/2 = 330 days

    5) p = 2/15
    r = 1/3, s = 4/15

    6) cos theta = 13/35
    intersection = (2, 0, -1)
    C = (5/2, -5/6, 7/6), D = (3/2, 5/6, 5/6) (or vice versa)

    7) gradient = e^4/2

    8) k = 12, c = -pi (but if you put the +c on the opposite integral, you would have got c = pi assuming that's correct)

    Anyone agree?
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    Damn I forgot it was positive sin3x do you think I'll only lose one mark for that.
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    But using C4 techniques, so it wan't off spec
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    if you clearly stated 330 before you should get the full marks, but if you only stated 331 i think you would loose and answer mark as it said to the nearest day(which would be 330) from what i can remember
    (Original post by 000536)
    How many marks will I lose because I put -69/2+9/2ln3 and then simplified it to -69+9ln3.

    I'm stupid and don't know log rules.

    also I put 330.04....w/e the decimals were and then rounded to 331 because that was how I interpreted it wanted rounding to. How many marks will I lose for that? Just one I assume, because I wrote the value then rounded it wrong?
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    (Original post by 000536)
    How many marks will I lose because I put -69/2+9/2ln3 and then simplified it to -69+9ln3.

    I'm stupid and don't know log rules.

    also I put 330.04....w/e the decimals were and then rounded to 331 because that was how I interpreted it wanted rounding to. How many marks will I lose for that? Just one I assume, because I wrote the value then rounded it wrong?
    I got that answer also, but i think you would lose 1 mark for putting down that final answer because it was "rational number" i think
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    (Original post by joef1337)
    I managed to store some of my answers in my calculator (Stats mode is great!), besides the "show that" questions, and this is what I had:

    1)A = -1/2, B = 9/2
    -1 + 7x - 22/3 x^2 + O(x^3)
    -1/2 < x < 1/2

    2)x = 0°, 99.6°, 206.4°

    3)A = -3, B = 2, C = 9
    p = -69/2 (lol), q = 9/2

    4) m = 181g, t_1/2 = 330 days

    5) p = 2/15
    r = 1/3, s = 4/15

    6) cos theta = 13/35
    intersection = (2, 0, -1)
    C = (5/2, -5/6, 7/6), D = (3/2, 5/6, 5/6) (or vice versa)

    7) gradient = e^4/2

    8) k = 12, c = -pi (but if you put the +c on the opposite integral, you would have got c = pi assuming that's correct)

    Anyone agree?
    I don't remember completely but I recognise those numbers. Except in q2 the range was 0<x<360 so 0 was not a solution
 
 
 
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