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    (Original post by RhyaCeri)
    this was actually a really nice paper! probably easier for me because i was resitting but it was so much better than last years paper
    I preferred last years paper :/
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    (Original post by tadit)
    How many marks was that question?
    3 marks
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    (Original post by JacobC1998)
    The question said that the factor was (x+2) i am certain of it
    (Original post by student0042)
    Actually you may be right because it was p(-2) = 0 there x + 2 =0 and x = -2
    Honestly I can't remember anymore.
    Here we go: Its (x+2) which gives a root of x=-2

    https://www.dropbox.com/s/ziig4709q7...22343.jpg?dl=0
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    (Original post by ItsMJ)
    I can probably post an unofficial mark scheme if someone could remember the questions, because I don't remember them.
    Somebody already made one:

    http://www.thestudentroom.co.uk/show....php?t=3322639
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    There are quite a few questions I've DEFINITELY got wrong, but how many working marks would I get if:

    For Q1Bii) To find A, I attempted a simultaneous equation with the equation given, and the one calculated, but have the wrong answer?

    Q2) I didn't distinctly state that N=7, however I got 7+rt15

    Q4d) To find the smallest length, I used pythagoras with the radius 5rt2 and minused it from another length I had (which is wrong), but would I get any marks for working??

    Q5c) I identified that the values in the complete square form changed, to (x+0.5)^2 + (y+2.5)^2, however I left 'c' the same and didn't minus the 1/4 from 0.5^2, so my quadratic was incorrect. How many working marks, if any?

    Question 6b) I stupidly differentiated 24pi(r)-pi^4/2, instead of 24pi(r)-pi^3/2 (I differentiated with the power 4 instead of 3). I think I did dy/dx and d2y/dx2 correctly, however I differentiated the wrong expression! Would I get any marks carried forward for this, or would I get 0?

    Question 7a) The cubic graph, I wrote down that x=0 and x=3, however the graph that I drew (despite going through 0 and 3) was wrong. Would I get any of the 3 marks?

    Question 8c) Another ridiculous mistake, I couldn't figure out the factors to factorise with (36 and -4), so put b^2-4ac from the previous question into the quadratic formula, however I didn't solve anything as I ran out of time. Would I get a mark for working for doing this?

    If you read all of this post, I thank you enormously!
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    (Original post by snuvisol)
    3 marks
    Well since you drew the curve touching/passing the roots correctly and you drew the curve as a general cubic shape, you may only lose one mark for drawing it the other way round
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    I got 162/5 for the area under the graph
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    I got 162/5 for the area or the shaded region
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    I thought it was a pretty standard paper; only thing i struggled with personally was the translation question; because i was in 2 minds whilst answering that question.

    Apart from that nothing new really came up; they just recycle old questions styles.
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    (Original post by tadit)
    Well since you drew the curve touching/passing the roots correctly and you drew the curve as a general cubic shape, you may only lose one mark for drawing it the other way round
    I hope you are right That would be just 1 mark lost overall, so I can still get 100 UMCS
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    (Original post by brokenlevel23)
    Finished the markscheme. Thanks everyone!
    How do you do 8b? I know that u use discriminant but when i expand the brackets, I don't get the equation
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    i messed up the integration one i worked out the area of the trapezium to be 270/5 but i didn't get the one before right and my final answer was like 124/5 how many marks would i lose?
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    (Original post by JacobC1998)
    I am sure that question 7biv was x=-2
    Im pretty sure part 6aii.) was 2 marks, not 3
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    (Original post by brokenlevel23)
    FINAL MARKSCHEME:

    Question 1
    (a) -3/5 [2]
    (b)(i)
    perp. gradient = 5/3
    y-?=5/3(x-?)
    5x-3y+1=0 [3]
    (b)(ii) A(9,-4) [3]

    Question 2
    7+√15
    n=7 [5]

    Question 3
    (a) y=-10x-4 [4]
    (b)(i) 108/5 (oe, e.g. 21.6) [5]
    (b)(ii). 162/5 (oe, e.g. 32.4) [3]

    Question 4
    (a) (x+1)^2 + (y-3)^2 = 50 [2]
    (b)(i). C(-1,3) [1]
    (b)(ii) 5√2 [2]
    (c)
    k^2-6x-16
    (k-8)(k+2)
    k=8, k=-2 [2]
    (d) min. distance = 7 [2]

    Question 5
    (a) p = 3/2, q = -¼ [3]
    (b)(i) (-3/2, -¼) [2]
    (b)(ii) line of symmetry is x=-3/2 [1]
    (c) y=x^2-x+4 [3]

    Question 6
    **IT WAS AN OPEN TOP CYLINDER DAMNIT**
    (a)(i) h = 24/r -r/2 [3]
    (a)(ii) Sub πr^2 into part (i) to get V = 24πr -π/2 r^3 [3]
    (b)(i) 24π -3π/2 r^2 [2]
    (b)(ii)
    r=4 when dy/dx=0
    r=4 => d^2y/dx^2(=-12π)<0, therefore maximum [4]

    Question 7
    (a) http://i.imgur.com/rVJ169A.png [3]
    (b)(i) R = 36 [2]
    (b)(ii) R= 0 therefore root [2]
    (b)(iii)(x-2)(x^2-5x+10) [2]
    (b)(iv) x=2 [3]

    Question 8
    (a) (Show) x^2 + 3(k-2)x -13-k=0 [1]
    (b) 9k^2-32k-16<0 [3]
    (c) -4/9< k<4 [4]



    im pretty sure 6aii was 2 marks, not 3
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    On the cylinder question who got 4 for the stationary point ?
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    Could someone give me the two equations that were used for 1c, where you had to find coordinates A by doing simultaneous equations please.
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    (Original post by Rachel1315)
    That's what I got, How did you do question 2 the surds one it's really bugging me because I know it was probably so simple!
    You were given two co-ordinates in the form of surds, I've forgotten what they were.

    However, all you needed to do was use the gradient equation (y2-y1/x2-x1) and then rationalize the denominator to end up with like 7+ 15 (or -√15, I've forgotten.)
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    (Original post by starfish5577)
    On the cylinder question who got 4 for the stationary point ?
    I got 4.
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    Guys for the integral one I got 648/30 which is equivalent to 108/5 would I still get the marks .
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    Did you have to put n=7 because for similar questions on other mark-schemes they never stated that?
 
 
 
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