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The Physics PHYA2 thread! 5th June 2013 Watch

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    (Original post by SortYourLife)
    I literally live round the corner from there! (Well like a 20 minute walk, my nanas lives about a 2 minute walk away aha)

    But yeah I'm there a lot aha :') you?


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    HAHA 'nanas' I think you are from an Asian country. Am I right? Preferably from Pakistan? I have been to there a lot of times too My mum likes it soo much and takes me with her and I get bored there. HAHA
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    (Original post by StalkeR47)
    HAHA 'nanas' I think you are from an Asian country. Am I right? Preferably from Pakistan? I have been to there a lot of times too My mum likes it soo much and takes me with her and I get bored there. HAHA
    Nope, English. Sorry aha


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    (Original post by SortYourLife)
    Nope, English. Sorry aha


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    Stop talking about unrelated things. That's what chat is for.

    And does anyone know how to do this question?Name:  ImageUploadedByStudent Room1370201436.090810.jpg
Views: 159
Size:  195.5 KB
    The answers are 0 and 4lambda respectively


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    (Original post by Tuya)
    Stop talking about unrelated things. That's what chat is for.

    And does anyone know how to do this question?Name:  ImageUploadedByStudent Room1370201436.090810.jpg
Views: 159
Size:  195.5 KB
    The answers are 0 and 4lambda respectively


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    read the question. Thats the second order diffraction
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    (Original post by Tuya)
    Stop talking about unrelated things. That's what chat is for.

    And does anyone know how to do this question?Name:  ImageUploadedByStudent Room1370201436.090810.jpg
Views: 159
Size:  195.5 KB
    The answers are 0 and 4lambda respectively


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    Sorry boss.


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    (Original post by Goods)
    read the question. Thats the second order diffraction
    Even so, wouldn't the path length 2 lambda? as it would be lambda from the diffraction grating to the lens and another lambda from the lens to the screen wouldn't it? I'm a bit confused why its four?
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    (Original post by sazzabazza)
    How would one know when to use w=lambdaD/s and when to use dsintheta=nlambda when trying to find wavelengths in a slit diffraction experiment? I'm talking about the six mark prose questions?

    Thanks
    Well the question would tell you whether or not it was single slit or the diffraction grating experiment. Which is what the equations correspond to respectively as you have stated them.
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    Attachment 222498
    Not sure how much help the cue card is but that's how I summarised it for myself.
    The path difference when it is the second order is two, between adjacent waves.
    Because its not the adjacent wave the path difference is four, double.
    In triangle terms because the hypotenuse is 2d rather than just d.
    No sure how well I'm explaining that- shall I draw it?x
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    (Original post by IWantSomeMushu)
    Does anybody know the conversions of 1mm^2 and 1cm^2 to 1m^2?
    1mm^2= 0.01cm^2

    1mm^2=0.000001m^2

    1cm^2=0.0001m^2
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    (Original post by Juliajuliajulia)
    Attachment 222498
    Not sure how much help the cue card is but that's how I summarised it for myself.
    The path difference when it is the second order is two, between adjacent waves.
    Because its not the adjacent wave the path difference is four, double.
    In triangle terms because the hypotenuse is 2d rather than just d.
    No sure how well I'm explaining that- shall I draw it?x
    Yes please
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    Name:  ImageUploadedByStudent Room1370205170.948187.jpg
Views: 150
Size:  156.7 KB
    Sorry look so long got distracted with the joys of my biology exam tomorrow...
    Allow I literally have no artistic talent, hope it makes sense x
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    (Original post by Currentlysmilin)
    Even so, wouldn't the path length 2 lambda? as it would be lambda from the diffraction grating to the lens and another lambda from the lens to the screen wouldn't it? I'm a bit confused why its four?
    The path length between db is 2 lamba therefore the path lenght CE is 2 lamba + 2 lamba = 4 lamba
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    (Original post by Juliajuliajulia)
    Name:  ImageUploadedByStudent Room1370205170.948187.jpg
Views: 150
Size:  156.7 KB
    Sorry look so long got distracted with the joys of my biology exam tomorrow...
    Allow I literally have no artistic talent, hope it makes sense x
    OOOHH! I get it and it feels brilliant! Thank you for your effort!!
    Good luck in your exam!
    Plus your drawings a very clear!
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    (Original post by Goods)
    The path length between db is 2 lamba therefore the path lenght CE is 2 lamba + 2 lamba = 4 lamba
    Thanks
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    (Original post by Currentlysmilin)
    OOOHH! I get it and it feels brilliant! Thank you for your effort!!
    Good luck in your exam!
    Plus your drawings a very clear!
    That's really neat, makes perfect sense now... Thanks


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    (Original post by Tuya)
    Stop talking about unrelated things. That's what chat is for.

    And does anyone know how to do this question?Name:  ImageUploadedByStudent Room1370201436.090810.jpg
Views: 159
Size:  195.5 KB
    The answers are 0 and 4lambda respectively


    Posted from the TSR iPad app
    Which past paper is this question from ?

    Thanks
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    (Original post by posthumus)
    Which past paper is this question from ?

    Thanks
    Yup I second this! This was quite hard!
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    Has anyone got any exam tomorrow? I have ICT
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    (Original post by Currentlysmilin)
    Yup I second this! This was quite hard!
    Yup The question got me really worried... but apparently it's from the old spec
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    (Original post by StalkeR47)
    Has anyone got any exam tomorrow? I have ICT
    I have ICT tomorrow too!
 
 
 
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