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    (Original post by -jordan-)
    The usual policy is that they ignore extra trigonometric values and you get the mark if you've got all the valid ones in that range.
    Oh that's alright then
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    (Original post by pb123)
    i agree it was -5/2
    I concur also
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    Would 66/67 be full ums?


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    (Original post by joef1337)
    I managed to store some of my answers in my calculator (Stats mode is great!), besides the "show that" questions, and this is what I had:

    1)A = -1/2, B = 9/2
    -1 + 7x - 22/3 x^2 + O(x^3)
    -1/2 < x < 1/2

    2)x = 0°, 99.6°, 206.4°

    3)A = -3, B = 2, C = 9
    p = -69/2 (lol), q = 9/2

    4) m = 181g, t_1/2 = 330 days

    5) p = 2/15
    r = 1/3, s = 4/15

    6) cos theta = 13/35
    intersection = (2, 0, -1)
    C = (5/2, -5/6, 7/6), D = (3/2, 5/6, 5/6) (or vice versa)

    7) gradient = e^4/2

    8) k = 12, c = -pi (but if you put the +c on the opposite integral, you would have got c = pi assuming that's correct)

    Anyone agree?
    I got different co-ordinates for C and D in question 6, can't remember exact vales but mine had thirds in, and an integer for the x co-ordinate
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    I got a=-3 b=2 and c=9
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    Welcome Squad
    (Original post by Manliker)
    What did people get for the ax + b + c/something??
    I got A = -3, B = 2 and C = 9
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    (Original post by Yo12345)
    Was the Ax + B + C/? question out of 6?


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    i got -3x + 2 + 9/2x + whatever it was
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    (Original post by Yo12345)
    Would 66/67 be full ums?


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    100 UMS - 66
    A* - 61
    A - 55
    B - 49
    C - 43

    I think my estimate might be a bit low for the 100 UMS mark but 66/67 would probably be 100, if not close to it.
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    (Original post by joef1337)
    I managed to store some of my answers in my calculator (Stats mode is great!), besides the "show that" questions, and this is what I had:

    1)A = -1/2, B = 9/2
    -1 + 7x - 22/3 x^2 + O(x^3)
    -1/2 < x < 1/2

    2)x = 0°, 99.6°, 206.4°

    3)A = -3, B = 2, C = 9
    p = -69/2 (lol), q = 9/2

    4) m = 181g, t_1/2 = 330 days

    5) p = 2/15
    r = 1/3, s = 4/15

    6) cos theta = 13/35
    intersection = (2, 0, -1)
    C = (5/2, -5/6, 7/6), D = (3/2, 5/6, 5/6) (or vice versa)

    7) gradient = e^4/2

    8) k = 12, c = -pi (but if you put the +c on the opposite integral, you would have got c = pi assuming that's correct)

    Anyone agree?
    I believe the consensus was that k =6 , not 12
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    (Original post by jthill98)
    C/D for core 3
    B for core 4

    cheers; what u thinking number-wise?
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    Would I get 7/7 for follow on marks for 8b) even though I put 1/2tan^-1(3x/2), because I integrated correctly and got c=pi?


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    How many marks was the decay question worth?


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    Didn't get the vectors question. Other than that I think it was just arithmetic errors or silly things, but I don't think I've improved on last year's grade anyway so it doesn't matter.
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    I got k = 4 for 8 part a. Anyone else get that?
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    (Original post by snimkar)
    I got k = 4 for 8 part a. Anyone else get that?
    It was 6
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    Would I get any marks for 6c) by finding the length of CD?


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    do people remember what sinA, sinB, cosA and cosB were?
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    (Original post by Jm098)
    I got landa as 1 and u as a 1/2
    i got that too =D and 100% sure its right cus i even performed a check
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    I find it difficult
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    (Original post by hi-zen-berg)
    cheers; what u thinking number-wise?
    To be perfectly honest my friend im an A grade maths student so only pay attention to the A boundary, i reckon for c3 an A will be 56 or 57. For core 4 i reckon 57 or 58
 
 
 
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