Here are my answers (I know some of them are wrong!!)

__Paper 1__

1. Y=-4/3 +8

2. b) 7, 6 and 8

3. 37.68cm3 (Total nonsense I know!!!!)

4. a) (x-2) (x+3)

b) 3x3 + 17x2 + 7x - 2

5. -9

6. Can't remember but think I said something like 4cm!!

7. p(-18)

8a) -11

b) Can't find the roots of a minus number

9. 45 degrees

10. a) -5

b) 8,0

c) -20

__Paper 2__

1. £155,000

2. Pasta - 150 degrees Baked potato 200 degrees Salad - 10 degrees

3. £8

4. a) 49

b) 3.96

5. Y = -12.32 and X = -18.8

6. 3s/2

7. L=p/2 - B

8. 6 square root 2

9. 1342.56 cm2

10. b) 2

11. 25.3cm

12. 126.48m

13. 3.45m

14. a) 8.69

b) 48 degrees

@minsyb

Paper 2

Q3. I got £11

Q4. (a) I got 7

Some others I can't remember.

@Lscott22

That is the same as i got

Q14b) i got 48 degrees and 228 degrees because it was tan and you used x and 180+x

@Danny1994

I got thoose answers as well, but I got 228 degrees and I did not put it down because that would mean the building was hanging/bending over the surveyor?

Solutions:

1) 0.9575 * 0.9575 * 0.9575 * 176500 = £155000

2)

Pasta - 150 deg

Potato - 200 deg

Salad - 10 deg

3) p = 2 + 1.5m = 2 + 1.5*6 = £11

4) a) i) 7

ii) 3.958

b) SD is lower so less spread with the new coach. Mean is higher so better score.

8)

2x - 5y = 24

7x + 8y = 33

14x - 35y = 168

14x + 16y = 66

14x - 14x - 35y - 16y =168 - 66

-51y = 102

y = -2

2x - 5y = 24

2x + 10 = 24

2x = 14

x = 7

So x=7 and y =-2

6)

(s^2)*3t / t*2s

= 3s / 2

7)

P = 2(L+B)

P/2 = L+B

L = P/2 - B

8) sqrt(63) + sqrt(28) - sqrt(7) = 5 root 7 - root 7 = 4 root 7

9) Front and back:

Area = pi*r^2 = pi*14^2 = 615.75 for whole area.

65 deg. 65 / 360 = 18.06% of the area.

So front is 0.1806 * 615.75 = 111.18 cm^2 * 2 (for back) 222.36 cm^2

Sides:

Recentangle sides 14 and 40 so for two = 14 * 40 * 2 = 1120 cm^2

Answer = 1120 + 222.36 = 1342.36 cm^2

10)

a) A = (x+3)(x+7) = x^2 +3x +7x +21 = x^2 + 10x + 21

b) x^2 + 10x + 21 = 45

x^2 + 10x - 24 = 0

(x-2)(x+12) = 0

x-2 = 0 -> x = 2

x+12 = 0 -> x=-12

x can't be -12 or sides would have a negative length, so x=2

11) A of top = pi*r^2 = 128.7 cm^2

V = AL

L = V/A = 3260 / 128.7 = 25.3 cm

12) Angle SRQ = 180 - 90 - 42 = 48 deg

Angle PRS = 63 deg

So Angle PRQ = 111 deg

Side RQ = (350 / sin111)*sin27 = 170 m

Side SQ = (170/sin90)*sin48 = 126m

126m

13) Heigh below =

1.95^2 - 1.25^2 = 2.24

sqrt(2.24) = 1.5

1.5 + 1.95 = 3.45 m

14) a)15*tan25 + 1.7 = 6.99 + 1.7 = 8.7m

b) tanx = (h - 1.7)/15 = (18.4 - 1.7)/15 = 16.7/15 = 1.11

x = arctan(1.11) = 48 deg

also does it matter if I get say a C in paper 2 and an A in paper 1 as long as both marks out of 80 add up to 60% then I have achieved a B? and could I get into higher with it even though I got a C in paper 2, if I do fail surely I can appeal as well

@ CJN

thanks for helping but for 9 it actually is A of S/A of S..well I think lol cause it actually mentions a sector and a radius and there is an angle in the centre of it, and I actually made a mistake I have 26 guaranteed marks so I need 4...im hoping I get about 2 for Q9 2 for Q14 and maybe one for Q4(b) but even if I get a C my paper one was so good I think I might get an overall B...i'm like literally praying haha

I could scan and upload paper 1, but my answers are scrawled all over it :/