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    (Original post by Jono404)
    Yeah I see where I went wrong now, needed parentheses then expansion. How many marks was that worth? Hopefully I'll get one of them for the -0.5....
    The first translation question was worth 2 marks where you had to describe the translation and the second, 4.
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    I think that translation was such an awful one to ask, I've never seen anything like it and it even fooled me at first. I think I'm the only one in my college who managed to get it so hopefully the marks schemes will be lenient for those questions!

    Question 8eii was quite difficult too, 20 minutes passed before i realised one needed to look at part (ei) :P:
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    (Original post by chronicl3)
    :yes:

    Did you get " translation (3/4 0) for the question before that
    Yes I did chronicle, it's nice to find someone who agrees with me haha

    y = 2^(4x-4) - 0.5
    y = 0 when there's an x-intercept, so 2^(4x-4) = 0.5
    Thus, (4x-4)log2 = log0.5
    Thus, 4x-4 = -1
    Thus, x = 3/4 so the x-intercept is (3/4 , 0)

    Apropos the first translation:
    2^(4x-3) ==== 2^4(x-3/4) ergo it's a translation of 3/4 units, parallel to the x-axis.
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    (Original post by chronicl3)
    I got x= 0.75.

    Cuz after the translation the equation would become 2^4(x-1)-0.5 that is 2^4x-4 - 0.5
    I agree with that I think
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    (Original post by Ollie901)
    I agree with that I think
    this is correct and i got it wrong. What did you guys get on the cosine rule and the area of the triangle?
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    I think the ares was 14.3?
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    (Original post by rob...)
    I think that translation was such an awful one to ask, I've never seen anything like it and it even fooled me at first. I think I'm the only one in my college who managed to get it so hopefully the marks schemes will be lenient for those questions!

    Question 8eii was quite difficult too, 20 minutes passed before i realised one needed to look at part (ei) :P:
    Which translation one?
    2^4x ---> 2^4x+3?

    That might have not been it exactly.

    I put stretch SF 1/8 for one of them D:
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    (Original post by rob...)
    The translation WAS 2^4(X-1) - 0.5! = 2^(4x-4) -0.5. x was 0.75 i'm certain.

    I had to spend 5 mins explaining this to my maths teacher haha. Also for the 2^4x translates to 2^(4x-3) is a translation of 0.75 units parallel to x-axis. NOT +3 UNITS!!!
    are you sure it's 0.75 and not (3 0) ???
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    (Original post by memomemootoo)
    are you sure it's 0.75 and not (3 0) ???
    3/4 yeah

    If you translate by (3 0) you get: 4(x-3) = 4x-12
    If you translate by (3/4 0) you get: 4(x-0.75) = 4x-3
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    (Original post by memomemootoo)
    are you sure it's 0.75 and not (3 0) ???
    Yeah, if you replace x with x-3 the equation would become 2^4(x-3) ---> 2^4x-12
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    Read this and see if you agree:

    y = 2^(4x-4) - 0.5
    y = 0 when there's an x-intercept, so 2^(4x-4) = 0.5
    Thus, (4x-4)log2 = log0.5
    Thus, 4x-4 = -1
    Thus, x = 3/4 so the x-intercept is (3/4 , 0)

    Apropos the first translation:
    2^(4x-3) ==== 2^4(x-3/4) ergo it's a translation of 3/4 units, parallel to the x-axis.
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    i can't believe that was a 3 mark question! it was horrible! and half the paper was on sequences...FML
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    (Original post by rob...)
    I think the ares was 14.3?
    Yeah, you did 180-150-11.5=18.5 for the third angle, then 1/2absinC, least I think that was it, remember getting 14 something
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    ok thanks people... oh crap:bawling:
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    (Original post by Jono404)
    Yeah, you did 180-150-11.5=18.5 for the third angle, then 1/2absinC, least I think that was it, remember getting 14 something
    Exactly the same its right don't worry...well that's 3 marks so far
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    (Original post by Jono404)
    Yeah, you did 180-150-11.5=18.5 for the third angle, then 1/2absinC, least I think that was it, remember getting 14 something
    yes I did exactly that... You actually stole my post . Was going to write exactly the same thing. Can't remember the answer though
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    The only Qs that threw me off was the integrating one, transformation and last one. I think I did okay on all other questions.
    Integrating was tricky. Had to do it twice.

    I think this paper was one of the harder ones =|
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    Yeh i did! i used 18.5 for the angle though which could have reduced accuracy and made my 3rd sig figs wrong! I need to start using the ANSWER button on my calculators!
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    rob, remember what the actual question was?
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    do the grade boundaries change every year or not?
 
 
 
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