Tougher mathematics test for trainee teachers Watch

MathMan
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#41
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#41
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My reasoning is as follows; 11,11,11,a,20,b,c,d,e,32,f in ascending order in order to keep 11 as the modal value im going to make the team as you as possible with the exception of F, so 11,11,11,12,20,21,21,22,22,32,f.

As the sum of the ages = 242, 242-(11+11+11+12+20+21+21+22+22+32)= f(max)=59
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Mr M
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#42
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#42
BabyMaths! I saw that. Tut tut. Your Head will expect your resignation on Monday morning.
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Mr M
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#43
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#43
(Original post by MathMan)
...
We don't allow 11 year olds to play in this league.
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BabyMaths
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#44
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#44
(Original post by Mr M)
BabyMaths! I saw that. Tut tut. Your Head will expect your resignation on Monday morning.
Nobody knows who I am, or do they?



Caught out, momentarily, by the modal condition.

I'm always in a rush to post and read carefully later. I've learnt my lesson.

Getting a very basic question wrong doesn't bode well for my MSc does it?



When are you going to post this at the other place?
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Mr M
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#45
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#45
Regretting positive repping you now Benjy.
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MathMan
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#46
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#46
Awwww that was my mistake, misread the question
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Noble.
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#47
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#47
(Original post by BabyMaths)


Caught out by the modal condition.

Doesn't bode well for my MSc.

Don't worry, I thought 62-21 = 40, who said mathematicians had to be good with numbers?
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Mr M
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#48
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#48
I'm off to strike fear in the hearts of the trainees over in Education and Teaching. Will report back later.
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the bear
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#49
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#49
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the sent off was 32, the oldest was 43
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danny111
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#50
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#50
(Original post by Mr M)
I'm off to strike fear in the hearts of the trainees over in Education and Teaching. Will report back later.
That's evil!
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Juncture
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#51
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For those interested in how I worked it out please see inside the spoiler

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a. We know that the mean age for the 11 players is 22, so the total age of those players is 22x11 = 242.
When we only have the 10 players the mean age goes down to 21, so the total age of these players is 21x10 = 210

Then just subtract 210 from 242 to get the players age of 32

b. We know these facts: There are 11 players, the modal age is 17 and there are 3 people of this age and this is the youngest age in the team, the median age is 20, and we have one player who is 32 (from the previous question). If we line up our players in age order we can fill in what we know:

1. 17
2. 17
3. 17
4.
5.
6. 20
7.
8.
9.
10. 32 (32 goes here because we want the highest age possible so want it to be higher than 32 and we want the other players to be as young as possible).
11. y

Then go through adding in the youngest ages possible (without using more than 2 of the same age) to get: 17, 17, 17, 18, 18, 20, 20, 21, 21, 32 and y

We know the total age is 242 so just take these ages away to be left with the answer of 41
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Mr M
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#52
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#52
(Original post by BabyMaths)
When are you going to post this at the other place?
Good idea. Hadn't though of it.
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Mr M
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#53
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#53
(Original post by the bear)
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the sent off was 32, the oldest was 43
Second is wrong bear.
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Genesis2703
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#54
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I got

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32 for the 1st one and 41 for the second. The 1st part was extremely straight forward, the 2nd part I had to assume the minimum case of 17,17,17,18,18,20,20,21,21,32,X. Then found X


That question wasn't really bad, just a bit tedious
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Noble.
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#55
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(Original post by Mr M)
I'm off to strike fear in the hearts of the trainees over in Education and Teaching. Will report back later.
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danny111
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#56
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#56
(Original post by Noble.)
ahahahahahahaha
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the bear
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#57
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#57
I ermm meant
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42
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Mr M
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#58
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#58
(Original post by the bear)
I ermm meant
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42
That may be the answer to life, the universe and everything but it isn't the answer to part b.
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Atheism
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#59
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#59
@Thebear, you're close to what the answer would be if you didn't include the person from the answer in question A. Have you included that person?
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Noble.
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#60
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#60
(Original post by Atheism)
@Thebear, you're close to what the answer would be if you didn't include the person from the answer in question A. Have you included that person?
If he didn't include the person from a) the difference would be much greater.
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