Tougher mathematics test for trainee teachers Watch
As the sum of the ages = 242, 242-(11+11+11+12+20+21+21+22+22+32)= f(max)=59
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BabyMaths! I saw that. Tut tut. Your Head will expect your resignation on Monday morning.
Caught out, momentarily, by the modal condition.
I'm always in a rush to post and read carefully later. I've learnt my lesson.
Getting a very basic question wrong doesn't bode well for my MSc does it?
When are you going to post this at the other place?
a. We know that the mean age for the 11 players is 22, so the total age of those players is 22x11 = 242.
When we only have the 10 players the mean age goes down to 21, so the total age of these players is 21x10 = 210
Then just subtract 210 from 242 to get the players age of 32
b. We know these facts: There are 11 players, the modal age is 17 and there are 3 people of this age and this is the youngest age in the team, the median age is 20, and we have one player who is 32 (from the previous question). If we line up our players in age order we can fill in what we know:
10. 32 (32 goes here because we want the highest age possible so want it to be higher than 32 and we want the other players to be as young as possible).
Then go through adding in the youngest ages possible (without using more than 2 of the same age) to get: 17, 17, 17, 18, 18, 20, 20, 21, 21, 32 and y
We know the total age is 242 so just take these ages away to be left with the answer of 41
That question wasn't really bad, just a bit tedious