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    (Original post by Dan_JR_12)
    It could have 2 tangents, depending on the value of k, because it was a reciprocal graph. It had to different curves
    Ah yes! May not be as wrong as I thought then Hopefully I got one of them right.
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    (Original post by rach100)
    yhh same, but i ended up with surds for most of them :/
    Same - really annoying but I'm sure we did it the right way


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    Yeah I got that for the 125 root 5 question
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    (Original post by jo7777)
    I used the quadratic formula three times I think
    For the 125 root 5 question did you get 5^7/2?
    Spot on


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    What did anyone get for question 9? and for question 10 what was people intersecting circles?
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    what did you guys get for the minimum value of y?
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    Can I have a prediction of the grade boundaries for an A btw ?


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    (Original post by Sun_Bear)
    what did you guys get for the minimum value of y?
    -7


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    question nine anyone?
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    (Original post by hayjohn30)
    What did anyone get for question 9? and for question 10 what was people intersecting circles?
    Which one was question 9?
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    Someone create an unofficial mark scheme to with predicted grade boundaries?
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    (Original post by Dan_JR_12)
    Which one was question 9?
    The divisible by 3? I ended up from the sum as 3x^2+2
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    What did people get for the coefficient of x^3 in the binomial expansion question?
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    I got that but did you divide it by 3 as means of explaining you couldn't fully divide it by 3 ?


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    I reckon it will be about 55-58 for an A i thought the paper was quite easy apart from the last question
    Q 12 is where most candidates will loose loads of marks
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    I think I got everything right apart from retardedly writing 8a^8 instead of 8a^9...

    last question was k=0 or 4, by discriminant = 0

    distance between chord and centre was root10

    on one of them the y intercepts (I think) were 2+root11 and 2-root11

    cant remember much else
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    (Original post by Dan_JR_12)
    What did people get for the coefficient of x^3 in the binomial expansion question?
    -2560 but i think I've put positive 2560


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    I got k as 0 and 12. The tried verifying the values k by subbing it back in the quadratic. Was 9 the proof if so I got 3n for the first one and said that 3 can be taken out. And the 9 part 2 I got 3n^2+2 and said 3 couldn't be removed. Not sure about part 2 though. I got (2,-7) as min point
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    (Original post by krishkmistry)
    I got that but did you divide it by 3 as means of explaining you couldn't fully divide it by 3 ?


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    Yeh eventually and for the coefficient i got it wrong but it was 10 x 4 x -64x^3
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    Much nicer than the January paper.

    For the f(x-2) root question, did everyone get x=0, x=(7/2) and one other which I've forgot (-1?)
 
 
 
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