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    (Original post by emfp21)
    My teacher said half a sub division, another one said a whole sub division :/
    Anyone???

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    Did they say why because it doesn't say anything in the source that would suggest an uncertainty that large?
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    (Original post by emfp21)
    My teacher said half a sub division, another one said a whole sub division :/
    Anyone???

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    To be honest, I'm not really sure how you could get such an uncertainty unless there were issues when reading the measurements (vision problems) but that isn't really relevant. I'd also think that the uncertainty would be the thickness of the trace because ultimately that value will effect your readings. I'm not entirely sure though, I could be wrong.
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    (Original post by Mutleybm1996)
    Do you have the links?


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    Sorry I was on mobile before so I couldn't put the links in

    https://www.youtube.com/user/diggitydev

    and

    https://www.youtube.com/user/DrPhysicsA

    http://www.examsolutions.net/
    ( super helpful for the mechanics side of things calculations and stuff)

    hope this helps it has been a lifesaver for me
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    We just had some questions, one was estimate the uncertainty in time/voltage measurements, hence estimate uncertainty in the frequency calculations

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    (Original post by alicerose2)
    hope this helps it has been a lifesaver for me
    did you make many notes?, I make them but dont understand them :L

    videos are the way forward
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    Guys, click on the link below and scroll to the bottom, there are questions and answers for predicted section C questions
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    (Original post by shloke123)
    Guys, click on the link below and scroll to the bottom, there are questions and answers for predicted section C questions
    Where is the link? You tease
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    Any last advice?


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    By the way, does the answer always have to be the exact numerical answer given in the mark scheme?
    Can your answer be very close but only different as you used different significant figures?
    I'm doing the June 2009 paper, question 9.a) iv) and I cannot get the answer that they want. They want 0.054 W and I'm not getting answers that round to this exact number.

    http://www.ocr.org.uk/Images/59857-q...a-handling.pdf
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    Does anyone know how to do this?

    1. L= 110.0 ±0.1 cm, T=2.10±0.5 sec (where the uncertainty is due to the reaction time)

      Based on these measurements, what is the value of g and what is the maximum value the of the uncertainty in g?
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    Does anyone else think that the number of significant figures required by the mark scheme is quite inconsistent? It ranges from 2 s.f. to even 4 s.f. Does the number of s.f. depend on context or is there a set number we should round to?
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    (Original post by Mutleybm1996)
    Any last advice?


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    just try not to cry
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    (Original post by LimbuRonit)
    Does anyone know how to do this?

    1. L= 110.0 ±0.1 cm, T=2.10±0.5 sec (where the uncertainty is due to the reaction time)

      Based on these measurements, what is the value of g and what is the maximum value the of the uncertainty in g?
    Rearrange the equation given in the stimulus to get g=(4pi^2L)/T. Plug in L and T to get g. The max uncertainty will be when the largest L by the smallest T so plug in 110.1 for L and 1.6 for T. The difference between them is the uncertainty.

    *edit: should be divided by T^2 in equation and L is in cm so remember to divide by 100

    does that help?
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    (Original post by theoaze)
    Does anyone else think that the number of significant figures required by the mark scheme is quite inconsistent? It ranges from 2 s.f. to even 4 s.f. Does the number of s.f. depend on context or is there a set number we should round to?
    It depends on the context to a certain extent but as a general rule I'd say 2sf is most commonly I'm the ms. However, it does say that any sensible number of sf is acceptable which depends on the question
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    Does anyone have any useful material for section c? I'm really worried about this section...
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    Predictions on content?


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    (Original post by Carla Huynh)
    Rearrange the equation given in the stimulus to get g=(4pi^2L)/T. Plug in L and T to get g. The max uncertainty will be when the largest L by the smallest T so plug in 110.1 for L and 1.6 for T. The difference between them is the uncertainty.

    *edit: should be divided by T^2 in equation and L is in cm so remember to divide by 100

    does that help?
    I thought the formula for is ....g=4pi^2m (m=gradient)
    ???
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    (Original post by LimbuRonit)
    I thought the formula for is ....g=4pi^2m (m=gradient)
    ???
    4pi^2 / m


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    (Original post by bonzo123)
    did you make many notes?, I make them but dont understand them :L

    videos are the way forward
    I made notes in class but i haven't even looked at them they are so shocking! do you have the revision guide? That is pretty handy at explaining things too as long as you don't mind the shock of HELL WE HAVE NOT COVERED THIS IN CLASS I AM BUMMED. ( I am getting this a lot and end up frantically goggling)
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    (Original post by alicerose2)
    I made notes in class but i haven't even looked at them they are so shocking! do you have the revision guide? That is pretty handy at explaining things too as long as you don't mind the shock of HELL WE HAVE NOT COVERED THIS IN CLASS I AM BUMMED. ( I am getting this a lot and end up frantically goggling)
    You'll be ok! How did you find unit 1?

    Physics teachers are generally pretty rubbish at explaining things, Biology and Chemistry all the way


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