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Can any of you TSRians solve this puzzle? Watch

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    I've solved it but I can't be asked to type it

    But loooooooool the second spoiler tho Hahahaha TheOtherSide. I love it
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    (Original post by ForestShadow)
    Careful madhatter...pumpkin zombies will be to getcha......



    what the pumpkin :eek3:

    EDIT: omg the dolphins are gone :cry: :cry2:
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    (Original post by ZuluK)
    I've solved it but I can't be asked to type it

    But loooooooool the second spoiler tho Hahahaha TheOtherSide. I love it
    Congrats! :woo:
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    I think I just got my hopes up :getmecoat:
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    (Original post by TheOtherSide.)
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    I basically just posted this because it mentions 'the other side' :getmecoat:
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    And it should be easy for you guys to solve.
    Agreed this very easy
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    (Original post by TaintedLight)
    Agreed this very easy
    Not sure if you're being sarcastic or not :lol:
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    (Original post by TheOtherSide.)
    Not sure if you're being sarcastic or not :lol:


    I'm just surprised even after 3 pages no one have convincingly answered this25ty234y3qewaZXA;L
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    (Original post by TaintedLight)


    I'm just surprised even after 3 pages no one have convincingly answered this
    They were too busy finding faults with the plot :dontknow:
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    I'm looking at you, ForestShadow :rofl:
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    (Original post by TheOtherSide.)
    But as soon as the zombie rows, back, there'll be more zombies than humans on the more populated side of the river.
    Not if it doesn't get out of the boat. Or does that count as being on the side?

    I don't think it's possible otherwise.
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    (Original post by morgan8002)
    Not if it doesn't get out of the boat. Or does that count as being on the side?

    I don't think it's possible otherwise.
    It is definitely possible otherwise, but yeah, I get your point.

    I think it does count, though, because as soon as the boat gets back to the side, there are basically enough zombies to outnumber the humans.

    If you don't want to try other solutions, we can leave it at that. :lol:
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    (Original post by morgan8002)
    Not if it doesn't get out of the boat. Or does that count as being on the side?

    I don't think it's possible otherwise.
    :hat2:

    3 humans (A,B,C) and 3 zombies (X,Y,Z)

    Ride #1: A and X ferries across, drops X and returns back
    Ride #2: Y and Z ferries across, drops Z and returns back

    Ride #3: A and B ferries across, drops B, picks Z and returns back

    Ride #4: A and C ferries across, departs the boat, lets X return the boat back.

    As it stands A, B and C has gone to the other side. ()
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    (Original post by TaintedLight)
    :hat2:

    3 humans (A,B,C) and 3 zombies (X,Y,Z)

    Ride #1: A and X ferries across, drops X and returns back
    Ride #2: Y and Z ferries across, drops Z and returns back

    Ride #3: A and B ferries across, drops B, picks Z and returns back

    Ride #4: A and C ferries across, departs the boat, lets X return the boat back.

    As it stands A, B and C has gone to the other side. ()
    After ride 1 there is one zombie on the far side and no humans.
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    (Original post by morgan8002)
    After ride 1 there is one zombie on the far side and no humans.
    That's allowed - you just can't have more zombies than humans on any side.
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    (Original post by morgan8002)
    After ride 1 there is one zombie on the far side and no humans.
    Actually, the alternative is for the human to stay and that means on the other side, the zombies will outnumber the other 1 or 2 human(s)

    (Original post by TheOtherSide.)
    That's allowed - you just can't have more zombies than humans on any side.
    question clearly.... doesn't ...say that though
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    (Original post by TheOtherSide.)
    That's allowed - you just can't have more zombies than humans on any side.
    Oh, ok.
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    (Original post by TaintedLight)
    wtf. Brb


    Did no one else read all of the rules carefully?
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    (Original post by TaintedLight)
    Actually, the alternative is for the human to stay and that means on the other side, the zombies will outnumber the other 1 or 2 human(s)
    I know. It's not possible unless you're allowed to leave zombies on their own.
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    (Original post by TaintedLight)
    question clearly.... doesn't ...say that though
    If having the same number of humans and zombies on each side was a rule, I'm pretty sure they'd say that.
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    (Original post by bluemadhatter)
    You pick the human that is the strongest swimmer to swim across the river and the 2 other humans use the boat. Who gives a pumpkin about the zombies? :lol:
    Because zombies deserve to live too?
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    (Original post by ForgetMe)
    Because zombies deserve to live too?
    they're parasites
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    (Original post by TaintedLight)
    :hat2:

    3 humans (A,B,C) and 3 zombies (X,Y,Z)

    Ride #1: A and X ferries across, drops X and returns back
    Ride #2: Y and Z ferries across, drops Z and returns back

    Ride #3: A and B ferries across, drops B, picks Z and returns back

    Ride #4: A and C ferries across, departs the boat, lets X return the boat back.

    As it stands A, B and C has gone to the other side. ()
    This is the second fastest solution. You should realise this because your ride 2 does nothing functional with Y but moves Z, and your ride 3 does nothing functional with A, moves B and restores the original state of Z. This is, in essence, identical to just changing B once.

    Fastest solution is
    Ride 1 - 2 zombies cross, 1 zombie returns
    Ride 2 - 1 human, 1 zombie cross, 1 zombie returns
    Ride 3 - last 2 humans cross
 
 
 
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