_Xenon_
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#41
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#41
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Size:  318.2 KB Hi how do I do part b, thanks.
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Zacken
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#42
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#42
(Original post by _Xenon_)
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Size:  318.2 KB Hi how do I do part b, thanks.
If his height at age 20 is x then his height at age 12 is \frac{85}{100} \times x = \cdots
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_Xenon_
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#43
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#43
(Original post by Zacken)
If his height at age 12 is x then his height at age 12 is \frac{85}{100} \times x = \cdots
What's x?
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Zacken
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#44
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#44
(Original post by _Xenon_)
What's x?
His height at age 20.
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_Xenon_
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#45
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#45
(Original post by Zacken)
His height at age 20.
Is it a hard question? We can't times by x when we don't know what it is!
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Sir Cumference
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#46
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(Original post by _Xenon_)
Is it a hard question? We can't times by x when we don't know what it is!
It's quite a standard reverse percentages question.

Have you studied that topic? How do you usually do a question like this?
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_Xenon_
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#47
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(Original post by notnek)
It's quite a standard reverse percentages question.

Have you studied that topic? How do you usually do a question like this?
Not learnt reverse percentages but thanks!!
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(Original post by _Xenon_)
Not learnt reverse percentages but thanks!!
Then you should probably learn the topic before trying questions.

Zacken has given you a way to do it using algebra. If you want to do it a different way then one of us can give you another method.
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#49
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#49
(Original post by _Xenon_)
Is it a hard question? We can't times by x when we don't know what it is!
I'm asking you to setup an equation involving x and then solve for x.
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_Xenon_
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#50
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#50
(Original post by notnek)
Then you should probably learn the topic before trying questions.

Zacken has given you a way to do it using algebra. If you want to do it a different way then one of us can give you another method.
(Original post by Zacken)
I'm asking you to setup an equation involving x and then solve for x.
153/85 * 100 ? Will that be correct?

And yeah it is in a past paper I'm reviewing to fill in the gaps.
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Zacken
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(Original post by _Xenon_)
153/85 * 100 ? Will that be correct?
Yes.
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_Xenon_
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#52
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(Original post by Zacken)
Yes.
OK thanks!!!
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_Xenon_
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#53
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(Original post by Zacken)
Yes.
Algebra is better imo, will try that!!
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Zacken
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#54
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#54
(Original post by _Xenon_)
Algebra is better imo, will try that!!
That is the algebraic method?
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_Xenon_
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#55
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(Original post by Zacken)
That is the algebraic method?
Nope.
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Zacken
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#56
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(Original post by _Xenon_)
Nope.
Okay.
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_Xenon_
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#57
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(Original post by Zacken)
That is the algebraic method?
Like this

153 = 85/100 * x
15300 = 85x
15300/85 = x
120 = x
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Zacken
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#58
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(Original post by _Xenon_)
Like this

153 = 85/100 * x
15300 = 85x
15300/85 = x
120 = x
15300/85 is not 120.
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_Xenon_
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#59
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#59
(Original post by Zacken)
15300/85 is not 120.
I made a mistake 😱
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Zacken
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#60
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#60
(Original post by _Xenon_)
I made a mistake 😱
Just an arithmetical one.
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