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Size:  318.2 KB Hi how do I do part b, thanks.
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    (Original post by _Xenon_)
    Name:  image.jpeg
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Size:  318.2 KB Hi how do I do part b, thanks.
    If his height at age 20 is x then his height at age 12 is \frac{85}{100} \times x = \cdots
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    (Original post by Zacken)
    If his height at age 12 is x then his height at age 12 is \frac{85}{100} \times x = \cdots
    What's x?
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    (Original post by _Xenon_)
    What's x?
    His height at age 20.
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    (Original post by Zacken)
    His height at age 20.
    Is it a hard question? We can't times by x when we don't know what it is!
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    (Original post by _Xenon_)
    Is it a hard question? We can't times by x when we don't know what it is!
    It's quite a standard reverse percentages question.

    Have you studied that topic? How do you usually do a question like this?
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    (Original post by notnek)
    It's quite a standard reverse percentages question.

    Have you studied that topic? How do you usually do a question like this?
    Not learnt reverse percentages but thanks!!
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    (Original post by _Xenon_)
    Not learnt reverse percentages but thanks!!
    Then you should probably learn the topic before trying questions.

    Zacken has given you a way to do it using algebra. If you want to do it a different way then one of us can give you another method.
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    (Original post by _Xenon_)
    Is it a hard question? We can't times by x when we don't know what it is!
    I'm asking you to setup an equation involving x and then solve for x.
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    (Original post by notnek)
    Then you should probably learn the topic before trying questions.

    Zacken has given you a way to do it using algebra. If you want to do it a different way then one of us can give you another method.
    (Original post by Zacken)
    I'm asking you to setup an equation involving x and then solve for x.
    153/85 * 100 ? Will that be correct?

    And yeah it is in a past paper I'm reviewing to fill in the gaps.
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    (Original post by _Xenon_)
    153/85 * 100 ? Will that be correct?
    Yes.
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    (Original post by Zacken)
    Yes.
    OK thanks!!!
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    (Original post by Zacken)
    Yes.
    Algebra is better imo, will try that!!
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    (Original post by _Xenon_)
    Algebra is better imo, will try that!!
    That is the algebraic method?
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    (Original post by Zacken)
    That is the algebraic method?
    Nope.
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    (Original post by _Xenon_)
    Nope.
    Okay.
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    (Original post by Zacken)
    That is the algebraic method?
    Like this

    153 = 85/100 * x
    15300 = 85x
    15300/85 = x
    120 = x
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    (Original post by _Xenon_)
    Like this

    153 = 85/100 * x
    15300 = 85x
    15300/85 = x
    120 = x
    15300/85 is not 120.
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    (Original post by Zacken)
    15300/85 is not 120.
    I made a mistake 😱
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    (Original post by _Xenon_)
    I made a mistake 😱
    Just an arithmetical one.
 
 
 
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