Hey there! Sign in to join this conversationNew here? Join for free

How did you find the Edexcel FP1? Watch

  • View Poll Results: How was the FP1 for you?
    very hard
    148
    23.95%
    hard
    186
    30.10%
    ok
    167
    27.02%
    easy
    70
    11.33%
    very easy
    47
    7.61%

    Offline

    4
    ReputationRep:
    (Original post by 13 1 20 8 42)
    I am intrigued to see this paper now..
    It wasn't anything strange - I think finding the midpoint of a line threw people off and some weird awkward wording that's all.
    Offline

    2
    ReputationRep:
    Interested in seeing the paper too - I'd be happy to try and provide a correction
    Offline

    3
    ReputationRep:
    (Original post by oShahpo)
    I got -2.03 for the angle.
    Not negative as P was in top left quadrant.
    Offline

    19
    ReputationRep:
    (Original post by JamieOH)
    Not negative as P was in top left quadrant.
    Oh yea you're right, I took the angle I got away from pi. There was another negative angle though, right?
    Offline

    2
    ReputationRep:
    (Original post by oShahpo)
    14/5 root2 or something similar.
    15root2/4
    Offline

    4
    ReputationRep:
    Havent seen the paper yet, though the initial reaction doesn't help my nerves for FP2 and FP3 :laugh:
    Offline

    2
    ReputationRep:
    (Original post by JamieOH)
    Perpendicular I put? If R was 5? Maybe it wasnt
    (Original post by oShahpo)
    I didn't say the gradient was the same, I proved it they were parallel however using the ideas of vectors, that is that OA = 2 * PR, would I lose a mark for that?
    The two lines were parallel from what I got, both had a gradient of -2.
    JamieOH I don't think they were perpendicular as they weren't at right angles

    oShahpo I don't know, I might have lost a mark for not mentioning the length/vectors or you might have lost a mark for not mentioning the gradient.... who knows
    Offline

    19
    ReputationRep:
    (Original post by themechguy)
    The two lines were parallel from what I got, both had a gradient of -2.
    JamieOH I don't think they were perpendicular as they weren't at right angles

    oShahpo I don't know, I might have lost a mark for not mentioning the length/vectors or you might have lost a mark for not mentioning the gradient.... who knows
    I did mention they have the same length, arghh I would be angry if I lost a mark for not mentioning the gradient.
    Offline

    2
    ReputationRep:
    That paper was horrible! I'd been working so hard to get an A (I much prefer the applied stuff) and was managing to do it ok. I couldn't get the answer to the parabola part 1, I got the y(p+q) =2x (or something like that) but not the last bit.
    Also I only got the 1st proof by subtracting k+1 not adding it.

    WHAT HAPPENED??????
    Offline

    2
    ReputationRep:
    (Original post by oShahpo)
    I did mention they have the same length, arghh I would be angry if I lost a mark for not mentioning the gradient.
    I think it was like 1 mark, so I literally just stated parallel, it was fairly obvious from the diagram. Not sure they asked for a formal proof.
    Offline

    19
    ReputationRep:
    (Original post by edothero)
    Havent seen the paper yet, though the initial reaction doesn't help my nerves for FP2 and FP3 :laugh:
    Wasn't really hard at all, nothing mentally challenging. Some questions might have been poorly worded and some questions were lengthy, but that's all.
    Offline

    19
    ReputationRep:
    (Original post by Armpits)
    I think it was like 1 mark, so I literally just stated parallel, it was fairly obvious from the diagram. Not sure they asked for a formal proof.
    It was definitely 2 marks.
    Offline

    2
    ReputationRep:
    (Original post by themechguy)
    For the relationship between the two chords I said they were parallel as the gradient was the same.
    I wrote that the length of one was double the other
    Offline

    2
    ReputationRep:
    (Original post by themechguy)
    For the relationship between the two chords I said they were parallel as the gradient was the same.
    haha yeah, I only realised that the imaginary part = 0 in a real number with about 5 minutes to go, i think i had 20 seconds left when i got onto part e, how many marks was that question? 1 or 2?
    Offline

    1
    ReputationRep:
    (Original post by oShahpo)
    I got -2.03 for the angle.
    I don't remember entirely but I think x was negative and y was positive, giving +2.03.
    Offline

    19
    ReputationRep:
    (Original post by Unravelling)
    I don't remember entirely but I think x was negative and y was positive, giving +2.03.
    Yea it definitely is +2.03, I took the angle I got away from pi. There must have been another negative angle though, right?
    Offline

    3
    ReputationRep:
    (Original post by oShahpo)
    I didn't say the gradient was the same, I proved it they were parallel however using the ideas of vectors, that is that OA = 2 * PR, would I lose a mark for that?
    I anticipate:

    B1 parallel
    B1 gradient -2/same length shown or stated

    I said parallel, gradient -2, both making an angle of 26 or so degrees with the horizontal


    Posted from TSR Mobile
    Offline

    19
    ReputationRep:
    (Original post by Armpits)
    15root2/4
    Yea, I have the memory of a gerbil.
    Offline

    3
    ReputationRep:
    Wonder how I got they were perpendiuclar... Was it QR and OP right? I had R as 5?
    Offline

    1
    ReputationRep:
    It was 2.03 because the complex number was -1+2i , therefore you do pi - tan-1(2/1) = 2.03....

    You might have put -1 into the tan part which could screw things up, but because the argument was clearly less than or equal to pi and greater than 0, you know it must be a positive answer for the argument. Either way, if you put -2.03 I'm sure that's only 1 mark deducted as you performed the calculations correctly
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    What's your favourite Christmas sweets?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.