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    (Original post by tavtavtav)
    Isnt it least similar?
    It's the person who's most different cake is the least different
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    Ken should have baked no cakes and got 0 marks for baking and decorating, then difference would have been 0 and he would have won the ridiculous special prize
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    (Original post by Original.Name)
    Ken should have baked no cakes and got 0 marks for baking and decorating, then difference would have been 0 and he would have won the ridiculous special prize
    I am guessing he had to submit a cake, but why not just urinate on it or something. Ensures a double 0
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    (Original post by CuriosityKTMC)
    I am guessing he had to submit a cake, but why not just urinate on it or something. Ensures a double 0
    Good plan, unless they were "modern art" fans in which case they may have given him extra decorating points.....
    Or if Bear Grylls was judging that's extra taste points...
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    Does ecf apply to 4iv?
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    Also, what sort of lazy calendar maker can only be bothered to get 6 pictures?
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    (Original post by xsanda)
    Xsanda’s solutions:

    1) Matching
    i) JF=3-ND=4
    1:MA
    2:-
    3:JF
    4:ND
    5:JA
    6:MJ
    ii) SO=5-JA=2
    1:MA 2:JA 3:JF 4:ND 5: SO 6:MJ
    iii) 3=JF,4=ND,5=SO always
    1:MJ 2:MA 3:JF 4:ND 5: SO 6:JA

    2) Flow
    i) FT = 2, DT = 4, cut = 9
    iia) SCBFT +2 (given)
    b) SCFBAEDT +1
    iii) 8, with cut {SABCF}{DET} of value 8

    3) Hungarian
    i) Add dummy column X with 100 in each
    Reduce rows -86, -91, -88, -98
    Reduce cols -0,-2,-0,-2
    ii) AS, BT, CL, no match for D, £271 cost
    iii) CS, BT; AL costs £83

    4) Rock paper scissors
    i) scissors with paper: gain of 1, loss of 2: 1 + (-2) ≠ 0
    ii) playsafe: scissors
    iii) scissors 2-2p-4q, paper 3p+2q-2, rock 2q-p
    iv) p=0.5, q=0.25, rock = 0.25

    5) critical path analysis
    i) F and H also critical
    ii) A: -, B: -, C: -, D: A, E: BD, F: BCD, G: E, H: EF, I: GH, J: H
    iii) 60 mins, critical ABDEHJ
    iv) allocation for 3 people
    v) allocation for 2 people
    vi) A is critical, but so is B, which happens at the same time, so must reduce both to gain 5 minutes. 200+400=£600. Best is H and J: £500+£500 = £1000

    6i) (0;0)-(1;1)-(2;1)-(3;0)-(4;0): weight 7
    ii) 1 point
    iii) (0;0)-(1;0) 1
    (0;0)-(1;1) 2
    (1;0)-(2;0) 1
    (1;0)-(2;1) 1
    (1;1)-(2;0) 2
    (1;1)-(2;1) 1
    (2;0)-(3;0) 0
    (2;0)-(3;1) 0
    (2;1)-(3;0) 2
    (2;1)-(3;1) 0
    (3;0)-(4;0) 1
    (3;1)-(4;0) 2
    iv) (0;0)-(1;0)-(2;0)-(3;0)-(4;0): 1 point per round maximum
    How many marks was each question worth, do you know?
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    I don't get how we could have augmented the flow when all the pipes out of the source was full?... or am I mistaken?
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    (Original post by smm90)
    I don't get how we could have augmented the flow when all the pipes out of the source was full?... or am I mistaken?
    One can augment"backwards" if you get what I mean, so in effect reducing the flow in one area
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    (Original post by Carter1)
    I was convinced for most of the paper, that there was a mistake on the flow question, as all the arcs were saturated. You had to reroute a flow of 1, along another route, allowing for an additional flow of 1. You could find a cut of 8 (to prove this was maximal), by highlighting your saturated arcs, and finding the cut which went through only saturated arcs (I forget exactly what it was). It was not a nice question. And that dynamic programming..... Well at least they told me what absolute value means ... :rolleyes:

    For the first part of the critical path question, if we assume C was critical, does that mean the 2 to follow C were also critical? I wasn't too confident about that one.
    Yep, F and H were critical
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    (Original post by bassala)
    Yep, F and H were critical
    That is great. When I saw 3 unknowns in the game theory question, I was honestly expecting to be asked to form a simplex tableau...
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    (Original post by Carter1)
    That is great. When I saw 3 unknowns in the game theory question, I was honestly expecting to be asked to form a simplex tableau...
    Yeah it was a bit weird, I was under the impression that we deal with zero sum games only so was slightly confused but thank goodness it was not Simplex haha
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    (Original post by xsanda)
    Xsanda’s solutions:

    1) Matching
    i) JF=3-ND=4
    1:MA
    2:-
    3:JF
    4:ND
    5:JA
    6:MJ
    ii) SO=5-JA=2
    1:MA 2:JA 3:JF 4:ND 5: SO 6:MJ
    iii) 3=JF,4=ND,5=SO always
    1:MJ 2:MA 3:JF 4:ND 5: SO 6:JA

    2) Flow
    i) FT = 2, DT = 4, cut = 9
    iia) SCBFT +2 (given)
    b) SCFBAEDT +1
    iii) 8, with cut {SABCF}{DET} of value 8

    3) Hungarian
    i) Add dummy column X with 100 in each
    Reduce rows -86, -91, -88, -98
    Reduce cols -0,-2,-0,-2
    ii) AS, BT, CL, no match for D, £271 cost
    iii) CS, BT; AL costs £83

    4) Rock paper scissors
    i) scissors with paper: gain of 1, loss of 2: 1 + (-2) ≠ 0
    ii) playsafe: scissors
    iii) scissors 2-2p-4q, paper 3p+2q-2, rock 2q-p
    iv) p=0.5, q=0.25, rock = 0.25

    5) critical path analysis
    i) F and H also critical
    ii) A: -, B: -, C: -, D: A, E: BD, F: BCD, G: E, H: EF, I: GH, J: H
    iii) 60 mins, critical ABDEHJ
    iv) allocation for 3 people
    v) allocation for 2 people
    vi) A is critical, but so is B, which happens at the same time, so must reduce both to gain 5 minutes. 200+400=£600. Best is H and J: £500+£500 = £1000

    6i) (0;0)-(1;1)-(2;1)-(3;0)-(4;0): weight 7
    ii) 1 point
    iii) (0;0)-(1;0) 1
    (0;0)-(1;1) 2
    (1;0)-(2;0) 1
    (1;0)-(2;1) 1
    (1;1)-(2;0) 2
    (1;1)-(2;1) 1
    (2;0)-(3;0) 0
    (2;0)-(3;1) 0
    (2;1)-(3;0) 2
    (2;1)-(3;1) 0
    (3;0)-(4;0) 1
    (3;1)-(4;0) 2
    iv) (0;0)-(1;0)-(2;0)-(3;0)-(4;0): 1 point per round maximum
    how many marks lost for being an idiot and not making the negative values positive for absolute but getting the correct route (and maximin?)
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    soz for spam - how many marks lost for being an idiot and not making the negative values positive for absolute but getting the correct route (and maximin?)??? all the rest of the paper was good :/
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    (Original post by duncanjgraham)
    soz for spam - how many marks lost for being an idiot and not making the negative values positive for absolute but getting the correct route (and maximin?)??? all the rest of the paper was good :/
    I am not an examiner, although I would think you would get the majority of mark if your tabulation is correct (based on your values ) and you got the correct solution + route.
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    (Original post by Carter1)
    I am not an examiner, although I would think you would get the majority of mark if your tabulation is correct (based on your values ) and you got the correct solution + route.
    at first i thought negative arc weights was a no no but realised for the MAX(x,y) it's going to always make a positive value so the table wouldn't mess up completely.

    Hopefully it is what you say .. fingers crossed because i loved this paper except I'd never heard of absolute before , and they even fcking explained it and I ignored it
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    for the last question I only put the route but not the minimax value, is that ok?
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    (Original post by duncanjgraham)
    at first i thought negative arc weights was a no no but realised for the MAX(x,y) it's going to always make a positive value so the table wouldn't mess up completely.

    Hopefully it is what you say .. fingers crossed because i loved this paper except I'd never heard of absolute before , and they even fcking explained it and I ignored it
    aha I was not looking forward to that question, I was expecting another bird sanctuary or dog houses.... But yeh I know how you feel, I had C2 before that exam and started to get lazy in D2
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    (Original post by Carter1)
    That is great. When I saw 3 unknowns in the game theory question, I was honestly expecting to be asked to form a simplex tableau...
    when i saw that my heart literally stopped i hate hate hate simplex tableau
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    (Original post by btsx)
    for the last question I only put the route but not the minimax value, is that ok?
    Yeah it only asked for route.
 
 
 
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