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    (Original post by Miracle-)
    Yes same I got 36/73 thats 0.493.

    Why would you divide by 2l for the amplitude?
    think he means for working out elastic energy cos you do conservation of energy to get the amplitude.
    I did so wrong, and didn't get the centre of the oscillation right either. Assumed it was just where the thing was at equilibrium and started from.
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    grade boundary estimates?
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    (Original post by XY123)
    I got 8.77
    same. :cool:
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    (Original post by XY123)
    grade boundary estimates?
    I'd Imagine it'll be around 66 for 100 UMS, 62 for 90 and 55 for an A.
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    (Original post by Miracle-)
    Yes same I got 36/73 thats 0.493.

    Why would you divide by 2l for the amplitude?
    To find max extension so I could find amplitude, with epe=gpe


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    Well it's a good thing I don't require further maths for my uni offers.
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    (Original post by Miracle-)
    I got R=73/50W, what did you get for coefficient of friction? I got like 0.49 not sure if thats right.

    Last one I has some problems with too, I got 0.7m below O for centre of motion.

    Yeah I got both of those, what did you get for U< for the vertical circle?
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    (Original post by JoeyTr)
    Yeah I got both of those, what did you get for U< for the vertical circle?
    I got U<Root(5ag)
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    (Original post by JoeyTr)
    Yeah I got both of those, what did you get for U< for the vertical circle?
    U<root(5ag)
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    (Original post by Nathanburns01)
    I got U<Root(5ag)
    Same here, top notch!
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    Was the maximum height 5/3 a?
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    (Original post by hallo.C)
    Was the maximum height 5/3 a?
    Thats what i got
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    (Original post by XY123)
    I got 8.77
    Same here! Love it
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    (Original post by JoeyTr)
    Same here! Love it
    Yes lads


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    What was A and w for the last one?
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    (Original post by JoeyTr)
    Yeah I got both of those, what did you get for U< for the vertical circle?
    I'm fairly sure the question asked for a range of values of U where the string would go slack. If that is the case, then U > root(2ag), as the string must reach at least horizontal in order to go slack.

    I wrote root(2ag) < U < root(5ag)
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    (Original post by dsk1898)
    I'm fairly sure the question asked for a range of values of U where the string would go slack. If that is the case, then U > root(2ag), as the string must reach at least horizontal in order to go slack.

    I wrote root(2ag) < U < root(5ag)
    Strong point. I hope you're wrong but I have a feeling you're not. Hopefully 1 mark lost if so.
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    (Original post by dsk1898)
    I'm fairly sure the question asked for a range of values of U where the string would go slack. If that is the case, then U > root(2ag), as the string must reach at least horizontal in order to go slack.

    I wrote root(2ag) < U < root(5ag)
    Yeah sounds right to be honest, didn't think about that.

    I reckon around 60 marks for 90 UMS tbh hardest one I've done
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    What did people get for the speeds of the collisions?
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    (Original post by hallo.C)
    What did people get for the speeds of the collisions?
    Think I got B as 2.25 and A as -1.25. So e>5/9. And because their components parallel to the wall was the same they could collide again.
 
 
 
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