You are Here: Home >< Maths

# OCR M3 (non MEI) Wednesday 8th June watch

1. (Original post by Miracle-)
Yes same I got 36/73 thats 0.493.

Why would you divide by 2l for the amplitude?
think he means for working out elastic energy cos you do conservation of energy to get the amplitude.
I did so wrong, and didn't get the centre of the oscillation right either. Assumed it was just where the thing was at equilibrium and started from.
3. (Original post by XY123)
I got 8.77
same.
4. (Original post by XY123)
I'd Imagine it'll be around 66 for 100 UMS, 62 for 90 and 55 for an A.
5. (Original post by Miracle-)
Yes same I got 36/73 thats 0.493.

Why would you divide by 2l for the amplitude?
To find max extension so I could find amplitude, with epe=gpe

Posted from TSR Mobile
6. Well it's a good thing I don't require further maths for my uni offers.
7. (Original post by Miracle-)
I got R=73/50W, what did you get for coefficient of friction? I got like 0.49 not sure if thats right.

Last one I has some problems with too, I got 0.7m below O for centre of motion.

Yeah I got both of those, what did you get for U< for the vertical circle?
8. (Original post by JoeyTr)
Yeah I got both of those, what did you get for U< for the vertical circle?
I got U<Root(5ag)
9. (Original post by JoeyTr)
Yeah I got both of those, what did you get for U< for the vertical circle?
U<root(5ag)
10. (Original post by Nathanburns01)
I got U<Root(5ag)
Same here, top notch!
11. Was the maximum height 5/3 a?
12. (Original post by hallo.C)
Was the maximum height 5/3 a?
Thats what i got
13. (Original post by XY123)
I got 8.77
Same here! Love it
14. (Original post by JoeyTr)
Same here! Love it

Posted from TSR Mobile
15. What was A and w for the last one?
16. (Original post by JoeyTr)
Yeah I got both of those, what did you get for U< for the vertical circle?
I'm fairly sure the question asked for a range of values of U where the string would go slack. If that is the case, then U > root(2ag), as the string must reach at least horizontal in order to go slack.

I wrote root(2ag) < U < root(5ag)
17. (Original post by dsk1898)
I'm fairly sure the question asked for a range of values of U where the string would go slack. If that is the case, then U > root(2ag), as the string must reach at least horizontal in order to go slack.

I wrote root(2ag) < U < root(5ag)
Strong point. I hope you're wrong but I have a feeling you're not. Hopefully 1 mark lost if so.
18. (Original post by dsk1898)
I'm fairly sure the question asked for a range of values of U where the string would go slack. If that is the case, then U > root(2ag), as the string must reach at least horizontal in order to go slack.

I wrote root(2ag) < U < root(5ag)
Yeah sounds right to be honest, didn't think about that.

I reckon around 60 marks for 90 UMS tbh hardest one I've done
19. What did people get for the speeds of the collisions?
20. (Original post by hallo.C)
What did people get for the speeds of the collisions?
Think I got B as 2.25 and A as -1.25. So e>5/9. And because their components parallel to the wall was the same they could collide again.

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: June 27, 2016
Today on TSR

### Summer Bucket List is Back!

Start yours and you could win £150!

### GCSE Physics Equations sheet!

Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE