what was the question for the first trig question part a
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EDEXCEL CORE 2 MAY 2016  Unoffical Markscheme W/ Explained Answers watch

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 25052016 20:16

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 25052016 20:19
(Original post by Morg698)
Could you explain further how by letting 2^x =y that 2^2x+5 gives 32y^2
Say 2^x = y,
2^2x=y^2
And 2^5=32
Therefore 2^2x+5= 32y^2 
examhater44
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 25052016 20:21
Last years grade boundary was 59/75 for the A. I think it will be around 5556 this year tho

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 25052016 20:27
Question 8: Oh logs.
 I messed up  I got b = 5/3  a hahahah! The correct answer is:
a5/9
I think this question was to "express b in terms of a"
Not quite sure what your answer meant? 
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 45
 25052016 20:32
(Original post by casperyc)
Question 8: Oh logs.
 I messed up  I got b = 5/3  a hahahah! The correct answer is:
a5/9
I think this question was to "express b in terms of a"
Not quite sure what your answer meant? 
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 46
 25052016 20:36
(Original post by alevez2ez)
I messed up with that too, the subject of the formula. That was more of a test on the wording then actual .. answer. Btw.. I think your answer was wrong anyway.
I think I got (9a a number)/3 
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 25052016 20:41
(Original post by casperyc)
I did not give an answer in the reply. That was OP's answer. I was just asking if I remember correctly, that question should not have anything to do with "a= number" or "b= number". Should be something like "b= something with a".
I think I got (9a a number)/3 
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 25052016 20:43
(Original post by casperyc)
I did not give an answer in the reply. That was OP's answer. I was just asking if I remember correctly, that question should not have anything to do with "a= number" or "b= number". Should be something like "b= something with a".
I think I got (9a a number)/3
Cool! Well done!
I just want to get the paper and check my trig results. I think I got something different than the answers there. 
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 25052016 21:05
Thanks for the answers by the way, was looking for a while.
I wondered, how many marks would you lose for? :
In the factor theorem question, not splitting up the correct quadratic factor into two liner factors, I didn't think it factorised during the exam :/
Differentiating one or two of the terms in the differentiation question incorrectly, but still using the right method to find to find the min value of x and the perimeter I think it was.
Using the wrong range for the second trig question, I used the range in the first question :/ But doing the rest right.
Also was anyone confused about it saying graphical methods are not acceptable? Surely that didn't mean you couldn't have found the solutions using the trig graphs? 
TrueDAN
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 25052016 21:05
(Original post by casperyc)
Question 8: Oh logs.
 I messed up  I got b = 5/3  a hahahah! The correct answer is:
a5/9
I think this question was to "express b in terms of a"
Not quite sure what your answer meant?
Being blunt, my answer for that question was just completely wrong  I messed up on it! Guess we all do something like that each now and then xD 
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 25052016 21:12
(Original post by TrueDAN)
Being blunt, my answer for that question was just completely wrong  I messed up on it! Guess we all do something like that each now and then xD 
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 25052016 22:18
 Hey can anybody go through the trig identities question, it was 12cos(thetaPI/5) = 0 then ii) was 4cos^2x + 7sinx2=0 i think for 0<=x<=360

pantherxxxx
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 25052016 22:31
I will be getting 100 UMS ty edexcel for a piss exam i look foward to my future 3 figure UMS scores in S1 C3 and C4

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 26052016 00:24
(Original post by TrueDAN)
Hey all, sorry for the time delay in this one!! Best of wishes to Arsey too
I've not seen an official thread for this, although some great progress into formulating a markscheme has begun (who I will credit).
I think that the paper was deceiving in that it was actually more demanding than you'd think, but it was certainly better than C1
Question 1:
 Show that A is 64
(Use the sum formula and it's straight forward enough)
 Sum to infinity was 256
64/0.25 = 256
 Difference between 9th and 10th: 1.602 (3dp was requested)
Be careful to do ar^8 instead of ar^9 and likewise goes for ar^9 instead of ar^10.
Question 2:
a) Complete the trapezium rule table  straight forward substitution for 1 mark.
b) 20.75 square units.
1/2 ( 7.5 + 2(17) was the calculation
c) 5.75 units I believe  I got this one wrong (
Question 3:
a) Distance between points P and Q = Root34
P was (7,8) and Q was (10,13) = 3^2 + 5^2 = 34 then root the answer. It wanted its exact value.
b) (X  7) ^2 + (Y8)^2 = 34
c) 3x + 5y  95 = 0
You had to find gradient of PQ then 1/m it as it is perpendicular to get 3/5 as the gradient. It passed through Q therefore you yy1= m(Xx1)
Question 4: Nice, standard question.
a) Substute in 3/2 into F(X) and you got a remainder of 5  just a calculator job.
b) Substite X=2 into F(X) and there is 0 remainder thus a root.
c) X = 2, 2/3 or 1/2 leaving F(X) = (X+2)(3X+2)(2X1)
Question 5: Binomial which got challenging in some areas.
a) I believe it was 16288x + 1944x^2
b) A = 16 you had to to do this (1+kx)(16288x+1944x^2) and the only single number with no X coefficient was 16 X 1 therefore 16.
c and d)
You had 288 + 16k = 232 Now add 288 to both sides leaving
16k = 52 therefore
K = 7/2
Substitute this value of k into the expansion and you get 936 ( I did the correct method andgot an answer in 900s but can't remember if this was what I 100% got so I may have made a stupid mistake).
B = 936
You had to remember you have the X^2 term and kx^2 term.
Question 6:
I thought the first question was nasty for 3 marks  maybe I just over complicated it. I got 8Pi/ 15 and 7pi/15 however my second answer was wrong. I believe that the agreed answers are:
8Pi/15 and 2pi/15  I was so close (
b) I liked this one : 194.5 and 345.5 I got. You formulate a quadratic and X=2 or 1/4 . You had to disregard the 2 value as it is larger than one leaving sin^1 of 1/4 which was 14.5. Then use cast and make sure to account for it being negative.
Question 7:
a) Standard integration
b) 24.3 square units  you had to find the X bound and I believe it was 9.
Question 8: Oh logs.
 I messed up  I got b = 5/3  a hahahah! The correct answer is:
a5/9
(Thanks to Mills.O)
B) 2.19 luckily I got this. Very sneaky one. 2^2x+5  7(2^y) =0
Let y = 2^x and you get 32y^27y =0
Divide by y to get 32y = 7
Therefore y=7/32
2^x = 7/32 and take logs to get the answer.
Question 9: A really discriminating question  tough.
a) The included angle is 120 degrees, from angles in an equilateral triangle are 60 degrees, then to find the included angle do 180  60 = 120 degrees. I did it in degrees, you may have converted to radians, either way you should be left with 120/360 X PI X x^2 Or use 1/2r^2 X 120 (in radians)
= PiX^2/3
b) Demanding proof  only 3 marks to. I got it in the end, cannot remember it fully though. Area of rectangle was 2xy. Area of triangle was 1/2absinC = 1/2x^2 X sin 60. Area of sector was previous answer. Add them up to equal 1000 (given in the question and then rearrange for y)
c) Even if you didn't get the previous proof, you could have attempted this. You had to find the arc length as well. You ended up with the arc length + 3x + 2y. Substitute the value of y in and do some manipulation.
d) Differentiate to equal zero and attempt to solve. X = 16.6 and P = 120.
e) Differntiate twice and state how it must be larger than zero. Even if your X value is wrong, which I believe mine was, you can still get an error carried forward and pick up these last two marks.
Hope this helps!
HUGE CREDIT TO  X_IDE_sidf
Insane memory from him, as well as marks and answer help. Thanks!
Also credit to Cookie_raider01 for clarifying the marks for each question! See the comments for it
Thanks to TripleSeven for clarity in P and Q coordinates!
Best of luck all  I think I've got between 59 and 70 so that's what I mean by deceiving  I think the grade boundaries will be 5763 for an A. Sorry to speculate but a top 50 boundary for the A is more than likely.
Any corrections, thoughts or misunderstandings please say!! 
AstarAstarA
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 26052016 03:13
Sorry everyone, but the OFFICIAL edexcel mark scheme has been leaked https://drive.google.com/file/d/0B0o...ew?usp=sharing

nerdydicaprio
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 26052016 10:16
Do you still have the official markscheme they have taken it of

Darkseid1234
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 26052016 10:34
(Original post by TrueDAN)
Hey all, sorry for the time delay in this one!! Best of wishes to Arsey too
I've not seen an official thread for this, although some great progress into formulating a markscheme has begun (who I will credit).
I think that the paper was deceiving in that it was actually more demanding than you'd think, but it was certainly better than C1
Question 1:
 Show that A is 64
(Use the sum formula and it's straight forward enough)
 Sum to infinity was 256
64/0.25 = 256
 Difference between 9th and 10th: 1.602 (3dp was requested)
Be careful to do ar^8 instead of ar^9 and likewise goes for ar^9 instead of ar^10.
Question 2:
a) Complete the trapezium rule table  straight forward substitution for 1 mark.
b) 20.75 square units.
1/2 ( 7.5 + 2(17) was the calculation
c) 5.75 units I believe  I got this one wrong (
Question 3:
a) Distance between points P and Q = Root34
P was (7,8) and Q was (10,13) = 3^2 + 5^2 = 34 then root the answer. It wanted its exact value.
b) (X  7) ^2 + (Y8)^2 = 34
c) 3x + 5y  95 = 0
You had to find gradient of PQ then 1/m it as it is perpendicular to get 3/5 as the gradient. It passed through Q therefore you yy1= m(Xx1)
Question 4: Nice, standard question.
a) Substute in 3/2 into F(X) and you got a remainder of 5  just a calculator job.
b) Substite X=2 into F(X) and there is 0 remainder thus a root.
c) X = 2, 2/3 or 1/2 leaving F(X) = (X+2)(3X+2)(2X1)
Question 5: Binomial which got challenging in some areas.
a) I believe it was 16288x + 1944x^2
b) A = 16 you had to to do this (1+kx)(16288x+1944x^2) and the only single number with no X coefficient was 16 X 1 therefore 16.
c and d)
You had 288 + 16k = 232 Now add 288 to both sides leaving
16k = 52 therefore
K = 7/2
Substitute this value of k into the expansion and you get 936 ( I did the correct method andgot an answer in 900s but can't remember if this was what I 100% got so I may have made a stupid mistake).
B = 936
You had to remember you have the X^2 term and kx^2 term.
Question 6:
I thought the first question was nasty for 3 marks  maybe I just over complicated it. I got 8Pi/ 15 and 7pi/15 however my second answer was wrong. I believe that the agreed answers are:
8Pi/15 and 2pi/15  I was so close (
b) I liked this one : 194.5 and 345.5 I got. You formulate a quadratic and X=2 or 1/4 . You had to disregard the 2 value as it is larger than one leaving sin^1 of 1/4 which was 14.5. Then use cast and make sure to account for it being negative.
Question 7:
a) Standard integration
b) 24.3 square units  you had to find the X bound and I believe it was 9.
Question 8: Oh logs.
 I messed up  I got b = 5/3  a hahahah! The correct answer is:
a5/9
(Thanks to Mills.O)
B) 2.19 luckily I got this. Very sneaky one. 2^2x+5  7(2^y) =0
Let y = 2^x and you get 32y^27y =0
Divide by y to get 32y = 7
Therefore y=7/32
2^x = 7/32 and take logs to get the answer.
Question 9: A really discriminating question  tough.
a) The included angle is 120 degrees, from angles in an equilateral triangle are 60 degrees, then to find the included angle do 180  60 = 120 degrees. I did it in degrees, you may have converted to radians, either way you should be left with 120/360 X PI X x^2 Or use 1/2r^2 X 120 (in radians)
= PiX^2/3
b) Demanding proof  only 3 marks to. I got it in the end, cannot remember it fully though. Area of rectangle was 2xy. Area of triangle was 1/2absinC = 1/2x^2 X sin 60. Area of sector was previous answer. Add them up to equal 1000 (given in the question and then rearrange for y)
c) Even if you didn't get the previous proof, you could have attempted this. You had to find the arc length as well. You ended up with the arc length + 3x + 2y. Substitute the value of y in and do some manipulation.
d) Differentiate to equal zero and attempt to solve. X = 16.6 and P = 120.
e) Differntiate twice and state how it must be larger than zero. Even if your X value is wrong, which I believe mine was, you can still get an error carried forward and pick up these last two marks.
Hope this helps!
HUGE CREDIT TO  X_IDE_sidf
Insane memory from him, as well as marks and answer help. Thanks!
Also credit to Cookie_raider01 for clarifying the marks for each question! See the comments for it
Thanks to TripleSeven for clarity in P and Q coordinates!
Best of luck all  I think I've got between 59 and 70 so that's what I mean by deceiving  I think the grade boundaries will be 5763 for an A. Sorry to speculate but a top 50 boundary for the A is more than likely.
Any corrections, thoughts or misunderstandings please say!! 
Darkseid1234
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 26052016 10:38
(Original post by tifflcy)
heres the working for question 10, realised that i forgot to find p when i got 2 mins left so rushed it and got it wrong
P=120.2
d2p/dx2 = 2000^3, x = 16.6, d2p/dx2 > 0 hence minimum 
jimtaylor24
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 26052016 10:48
(Original post by cookie_raider01)
1.
A) 2 marks
B) 2 marks
C) 3 marks
2.
A) 1 mark
B) 3 marks
C) 2 marks
3.
A) 2 marks
B) 2 marks
C) 4 marks
4.
A) 2 marks
B) 2 marks
C) 4 marks
5.
A) 4 marks
B) 1
C) 2
D) 2
6.
A) 3
B) 6
7.
A) 3
B) 3
8.
A) 3
B)4
9.
A) 2
B) 3
C) 3
D) 5
E)2
if anyone can explain what I'll need it's much appreciated, I don't understand the whole marks to UMS thing so 
cookie_raider01
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 26052016 12:02
(Original post by jimtaylor24)
if I got two U's on C1 and D1 I reckon maybe a high U on C1 (like 35 marks) and completely messed up C2 (about 20 marks) then can I still get a grade overall if I smash D1?
if anyone can explain what I'll need it's much appreciated, I don't understand the whole marks to UMS thing so
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