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# Mr M's OCR (not OCR MEI) Core 2 Answers May 2016 watch

1. (Original post by ComputeiT)
For the last question 9 iii I left my two answers as (1/3)pi/a and (4/3)pi/a - will I still get the full 4 marks?
I expect so.
2. If i did the last question not in terms of A but rather just 4Pi/5 and Pi/5, how many marks would i lose?
3. (Original post by Ozil5)
Do you know what the question was for 4ii? Thanks
Solve
4. (Original post by Mr M)
Mr M's OCR (not OCR MEI) Core 2 Answers May 2016

1. (i) 10 cm (2 marks)

(ii) 5.04 cm (2 marks)

2. (i) (2 marks)

(ii) (3 marks)

3. (i) (4 marks)

(ii) (2 marks)

4. (i) (2 marks)

(ii) (4 marks)

5. (a) (3 marks)

(b) (i) (4 marks)

(ii) 4 (1 mark)

6. (i) (3 marks)

(ii) (2 marks)

(iii) (6 marks)

7. (i) Quotient and remainder 0 (3 marks)

(ii) or or (3 marks)

(iii) Show (2 marks)

(iv) (4 marks)

8. (i) Translation by 2 units in the positive x direction (2 marks)

(ii) Stretch parallel to the y axis scale factor (2 marks)

(iii) Sketch showing as the only point of intersection (2 marks)

(iv) (3 marks)

(v) 9.60 (3 marks)

9. (i) (1 mark)

(ii) and (3 marks)

(iii) and (4 marks)

Sorry guys I made a mess of 9(ii) at the start - I didn't notice k had to be positive. It's right now.
Thank sir. For 5ib I wrote the correct answer down in the exam booklet however for some stupid reason I made it equal 0 and tried to solve for a. How many marks would that be? And for 6iii. I worked it out and got 37.2 but rounded down to 37. What will I get?
5. (Original post by Mr M)
They might ignore subsequent working.
So might i lose marks
6. (Original post by Mr M)
Solve
For the last part of the last queston, why when subbing 4pi/5a into the equation do the values not equate - the cos part is negative
7. (Original post by czj1997)
6iii)
I did the sum of Un and the sum to infinity to Wmn.. and I ended up with 3n^2+17n-1200>0 or 3n^2+17n-1200<0 (i forgotten)... getting n=17.4
Did I do the entire question wrong or do I get any method marks?
N needs to be an integer so you round up and your quadratic is wrong.

You should have obtained .

You would get 3 marks I expect.
8. (Original post by Gogregg)
Wasnt the question to find the minimum points on the graph, not the x-intersects?
(Sorry for double posting and sorry if I'm wrong )
It wasn't either of those. I've corrected my solution.
9. (Original post by Ozil5)
Can someone please explain how to do 4ii, I know ive made a mistake somewhere but im not sure where

or but the second solution has to be rejected as it does not satisfy the original equation.
10. (Original post by Jamesk123)
I thought q 8 iii and 9 iii were 3 marks each?
No.
11. (Original post by Mr M)
N needs to be an integer so you round up and your quadratic is wrong.

You should have obtained .

You would get 3 marks I expect.
I had that answer but wrote 17 instead of -17 when using the quadratic formula so i had 38 as negative and 43 as positive so i wrote N=43 how many marks would I lose?
12. (Original post by ellaatherz)
For 7iv I integrated between -1 and 1 instead of -1 and 3 do you think I'll get any marks?
Yes 2 marks.
13. (Original post by Mr M)

or but the second solution has to be rejected as it does not satisfy the original equation.
Would I lose a mark for including -3?
14. (Original post by M99)
I'm almost certainly wrong, but how comee this doesn't work:

Sin(api/5) =sin(a*2pi/5)

Thus (double angle theorem)

Sin (api/5) =2*sin(api/5)*cos(api/5)

Thus 0.5 = cos(api/5)

Thus pi/3 = api/5

Thus 5/3 = a (which is smaller than 5 so is surely the first solution if it is right?
Interesting method. I did it wrong first time. It's corrected now. I didn't notice that k had to be positive.
15. (Original post by swagmister)
Would I lose a mark for including -3?
Yes.
16. (Original post by AlfieH)
Question 9ii - the question said that k must be a positive constant and 0 isn't a positive constant?
Yes I fixed it some time ago.
17. If it did for the period question
0 is greater than or equal to ax is less than or equal to 2api is this wrong
18. Do you lose marks if you forget to put cm?
19. (Original post by Mr M)
Yes I fixed it some time ago.
And I posted some time ago!
20. (Original post by Bobrey)
How come when you substitute in 4pie/3a into sin(ax) = root(3)cos(ax) they are not equal - it gives -ve value on the cos side.
They are equal. Both sides are negative.

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