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AQA AS FP1 Further Pure 1 15th June 2016 [Exam Discussion Thread] Watch

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    (Original post by An1998)
    I got tanx=-1/root3, but i maybe wrong :/
    I think I got tan pi/3 = 3^0.5
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    Hi guys did anyone get -7/4<k<1/4 for the value of k for the parabola question? Please say someone did!
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    Nah I got -1/2<k<2 I think


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    (Original post by Olsmarto)
    Nah I got -1/2<k<2 I think


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    I got this aswell
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    I'm a little sweat and do all the past papers and I feel this years papers have been worse than the past papers I've done😶 hopefully the grade boundaries and 100ums will be a lot lower? Anyone agree?


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    Has anyone got an unofficial mark scheme for this ?
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    (Original post by Physics Optimist;[url="tel:65801937")
    65801937[/url]]Thanks - this was the only one where I think I made a mistake. I got q as -7, -1 and 5. I didn't like 3 values and my Casio didn't agree with me I think I have one sign error so a probable 1/5 marks?
    How did you get that?! I got -1 and couldn't work out the others which meant I completely screwed up that question ended up spending like 25 minutes on it too
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    (Original post by Olsmarto;[url="tel:65805605")
    65805605[/url]]I'm a little sweat and do all the past papers and I feel this years papers have been worse than the past papers I've done😶 hopefully the grade boundaries and 100ums will be a lot lower? Anyone agree?


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    Other than the complex number question, I didn't do the questions any more difficult, though there were some 5/6 markers which would usually be split into smaller questions
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    (Original post by Olsmarto)
    I'm a little sweat and do all the past papers and I feel this years papers have been worse than the past papers I've done😶 hopefully the grade boundaries and 100ums will be a lot lower? Anyone agree?


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    Probably ~58 for an A. The paper was good except the higher mark ones which were much harder than usual, especially complex numbers question.
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    (Original post by LaurenLovesMaths)
    How did you get that?! I got -1 and couldn't work out the others which meant I completely screwed up that question ended up spending like 25 minutes on it too
    I subbed p+qi and p-2i into the equation, hence getting 4 simultaneous equations in p and q (2real and 2 imag). Two of them gave -1 for q but the others are prob incorrect. Never mind 😄
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    (Original post by bheaton)
    Loved the matrix question anyone remember what they got for the last part of the question???
    2root3 and 2
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    Did anyone get (\frac{\sqrt 3}{2},2) for the 6 mark matrices question?

    We had to find the coordinates of the point which is mapped onto (0,-4), after being transformed by \mathbf{A^2} and then reflected in the line x - \sqrt{3}y = 0. So, using the information from earlier question parts, this is how I arrived at my answer (sorry about the LaTex):

     \begin{bmatrix} \frac{1}{2} & -\frac{\sqrt 3}{2} \\[6pt] - \frac{\sqrt 3}{2} & -\frac{1}{2} \end{bmatrix} \cdot \begin{bmatrix} 4 & 0 \\[6pt] 0 & 1 \end{bmatrix} \cdot \begin{bmatrix} x \\[6pt] y \end{bmatrix} = \begin{bmatrix} 0 \\[6pt] -4 \end{bmatrix} \: \therefore \: \begin{bmatrix} 2 & -\frac{\sqrt 3}{2} \\[8pt] - 2 \sqrt 3 & -\frac{1}{2} \end{bmatrix} \cdot \begin{bmatrix} x \\[6pt] y \end{bmatrix} = \begin{bmatrix} 0 \\[6pt] -4 \end{bmatrix}

    If we multiply the two matrices together, and compare both sides, we get 2x - \frac{\sqrt 3}{2}y = 0 and - 2 \sqrt 3x - \frac{1}{2}y = -4.

    By solving these equations simultaneously, we can then show that x = \frac{\sqrt 3}{2} and y = 2.
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    (Original post by sam_97)
    Did anyone get (\frac{\sqrt 3}{2},2) for the 6 mark matrices question?

    We had to find the coordinates which were mapped onto (0,-4) after being transformed by \mathbf{A^2} then reflected in the line x - \sqrt{3}y = 0. So, using the information from earlier question parts, this is how I arrived at my answer (sorry about the LaTex):

     \begin{bmatrix} \frac{1}{2} & -\frac{\sqrt 3}{2} \\[6pt] - \frac{\sqrt 3}{2} & -\frac{1}{2} \end{bmatrix} . \begin{bmatrix} 4 & 0 \\[6pt] 0 & 1 \end{bmatrix} . \begin{bmatrix} x \\[6pt] y \end{bmatrix} = \begin{bmatrix} 0 \\[6pt] -4 \end{bmatrix} \:\:\Rightarrow \:\: \begin{bmatrix} 2 & -\frac{\sqrt 3}{2} \\[8pt] - 2 \sqrt 3 & -\frac{1}{2} \end{bmatrix} .  \begin{bmatrix} x \\[6pt] y \end{bmatrix} = \begin{bmatrix} 0 \\[6pt] -4 \end{bmatrix}

    If the multiply the new matrices together, then 2x - \frac{\sqrt 3}{2}y = 0 and - 2 \sqrt 3x - \frac{1}{2}y = -4.

    By solving these two equations simultaneously, we get x = \frac{\sqrt 3}{2} and y = 2.

    Hope someone recognises this!
    Yay, I got this too!!!
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    (Original post by ollycostello)
    2root3 and 2
    YESSS!!! I got that
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    (Original post by Roxanne18)
    Yay, I got this too!!!
    Great! Hopefully it's correct
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    Is anyone else taking MS2B on Tuesday ?
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    (Original post by bheaton)
    Is anyone else taking MS2B on Tuesday ?
    I am. Here's the link to the MS2B exam thread http://www.thestudentroom.co.uk/show....php?t=4121015
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    (Original post by Physics Optimist;[url="tel:65808229")
    65808229[/url]]I subbed p+qi and p-2i into the equation, hence getting 4 simultaneous equations in p and q (2real and 2 imag). Two of them gave -1 for q but the others are prob incorrect. Never mind 😄
    That's what I did but I just got -1, and then through doing something weird I got -8i?! I don't know hahaha
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    Uggggh for the final matrices question, somehow managed to f*ck up my simultaneous equations!?! Got so close... such a dumbass :L
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    [QUOTE=LaurenLovesMaths;65812917]That's what I did but I just got -1, and then through doing something weird I got -8i?! I don't know hahaha.

    I'm hoping for 2 out of 5.
 
 
 
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