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    (Original post by abc:))
    Lol I'm being destroyed :laugh: I really need this explaining to me
    Easy target and I'm bored tbh


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    (Original post by drandy76)
    Technically speaking it is getting smaller if we're only concerned with the magnitudes


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    But we're not
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    (Original post by Student403)
    But we're not
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    I think what's happened is the divide sign on your calculator has been rubbed out a bit and now looks like a minus sign.
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    (Original post by tanyapotter)
    I think what's happened is the divide sign on your calculator has been rubbed out a bit and now looks like a minus sign.
    -4-(-4)=0
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    (Original post by Kvothe the arcane)
    -4-(-4)=0
    He still could have typed -4-4 into his calculator.
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    (Original post by NoahMal)
    -4/-4 Firstly two negatives cancel out hence its 4/4 which is 1 therefore by mathematical induction it does not equal -8....
    This is correct. I agree wholeheartedly.
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    I'm gonna start off by assuming that \frac{x}{x} = k where k is some constant.

    \iff x=kx \iff \left ( k-1 \right )x = 0 and so we now know that x = 0.

    From our original equation we have \frac{0}{0}= k and we know that anything divided by 0 is infinity, and so \iff \pm \infty = k.

    We reject the positive solution because x = -4 in our original example and so it must be negative infinity: k = - \infty.

    Infinity is just an 8 rotated 90 or 270 degrees, so k = -8 and it follows that \frac{x}{x} = -8, hence -4 divided by -4 is indeed -8.
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    (Original post by Ayman!)
    I'm gonna start off by assuming that \frac{x}{x} = k where k is some constant.

    \iff x=kx \iff \left ( k-1 \right )x = 0 and so we now know that x = 0.

    From our original equation we have \frac{0}{0}= k and we know that anything divided by 0 is infinity, and so \iff \pm \infty = k.

    We reject the positive solution because x = -4 in our original example and so it must be negative infinity: k = - \infty.

    Infinity is just an 8 rotated 90 or 270 degrees, so k = -8 and it follows that \frac{x}{x} = -8, hence -4 divided by -4 is indeed -8.
    Today is a good day in maths history
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    (Original post by Ayman!)
    I'm gonna start off by assuming that \frac{x}{x} = k where k is some constant.

    \iff x=kx \iff \left ( k-1 \right )x = 0 and so we now know that x = 0.

    From our original equation we have \frac{0}{0}= k and we know that anything divided by 0 is infinity, and so \iff \pm \infty = k.

    We reject the positive solution because x = -4 in our original example and so it must be negative infinity: k = - \infty.

    Infinity is just an 8 rotated 90 or 270 degrees, so k = -8 and it follows that \frac{x}{x} = -8, hence -4 divided by -4 is indeed -8.
    nah you forgot you have to rotate the k by 90 or 270 degrees as well
 
 
 
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