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I teach Cheeeeese Special Relativity!!! watch

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    (Original post by CheeseIsVeg)
    :hide:
    :fuhrer:
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    (Original post by Kyx)
    :fuhrer:
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    (Original post by CheeseIsVeg)
    :bhangra:
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    CheeseIsVeg


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    want the answer, or you gonna do it?
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    (Original post by Kyx)
    CheeseIsVeg


    want the answer, or you gonna do it?
    I will do it wait pls
    :puppyeyes:
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    (Original post by CheeseIsVeg)
    I will do it wait pls
    :puppyeyes:
    OK. hurry plez
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    (Original post by Kyx)
    OK. hurry plez
    Ok so I am ill and tired and certain this is wrong but I got
    t^2= 1/(c^2-v^2)
    Where c = 3 x 10^8 ms^-2
    .....
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    (Original post by CheeseIsVeg)
    Ok so I am ill and tired and certain this is wrong but I got
    t^2= 1/(c^2-v^2)
    Where c = 3 x 10^8 ms^-2
    .....
    nearly there.
    And now you square root both sides to get...
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    (Original post by Kyx)
    nearly there.
    And now you square root both sides to get...
    t = +- 1/(3x10^8)-v
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    (Original post by CheeseIsVeg)
    t = +- 1/(3x10^8)-v
    You get t = (sqrt)[1/(c2-v2)]

    The amount of time according to the person on the train is simply 1/c, let's use capital T for this

    So, the amount of time dilation (gamma) is equal to t/T which is...
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    (Original post by Kyx)
    You get t = (sqrt)[1/(c2-v2)]

    The amount of time according to the person on the train is simply 1/c, let's use capital T for this

    So, the amount of time dilation (gamma) is equal to t/T which is...
    Oh lol i forgot to square root the bottom hehe i promise you i did on paper over here
    Ermmm
    C/root(c^2-v^2)
    Or something
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    (Original post by CheeseIsVeg)
    Oh lol i forgot to square root the bottom hehe i promise you i did on paper over here
    Ermmm
    C/root(c^2-v^2)
    Or something
    Yes, but there's one more step.

    The final answer is Gamma = 1/(sqrt)[1-(c2/v2)]
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    Cool to think that if you're travelling at say 80% of c that you age slower than your fellow earthlings. Still amazes me to this day that if you go on a superfast space journey then come back, you could be younger than say, your own grandchildren.
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    (Original post by Kyx)
    Yes, but there's one more step.

    The final answer is Gamma = 1/(sqrt)[1-(c2/v2)]


    (Original post by cbreef)
    Cool to think that if you're travelling at say 80% of c that you age slower than your fellow earthlings. Still amazes me to this day that if you go on a superfast space journey then come back, you could be younger than say, your own grandchildren.
    Physicccsss
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    (Original post by CheeseIsVeg)



    Physicccsss
    Physyx
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    (Original post by Kyx)
    Physyx
    :mmm:
 
 
 
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