Edexcel GCSE Mathematics A Higher Paper 2016 Unofficial Markscheme

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    (Original post by #1Mathlete)
    Small packs (x) have 5 envelopes
    Large packs (y) have 20 envelopes
    Give a formula for total (T) number of envelopes

    T=5x+20y
    Can't believe that was worth 3 marks...
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    What do you guys predict the grade boundaries will be like


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    (Original post by mrpaper)
    It didn't ask for the midpoint. (1, 2.5) was the midpoint.
    Ahhhh crap
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    [QUOTE=gcseexamz;65196911]Coordinates were (1, 2.5), (5, 7)

    How can the midpoint be totally negative if the two points were positive(on the upper part of the graph??
    Surely the midpoint would be somewhere near the coordinates right?
    I put the midpoint was ( 3, 4.75)[/QU

    they gave the midpoint we had to work out Q or something i swear ?
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    (Original post by AGcseStudent2016)
    3b)teacher asks students to do a questionnaire, why might the sample be bad?

    A: biased, due to same age range??- not 100%
    Yes that sounds correct. You could've said because of the sample being in the same school, it could have had influence on the decision making etc...
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    For the 36% answer question, what were the 3 marks for?
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    [QUOTE=carolinrev;65197101]
    (Original post by gcseexamz)
    Coordinates were (1, 2.5), (5, 7)

    How can the midpoint be totally negative if the two points were positive(on the upper part of the graph??
    Surely the midpoint would be somewhere near the coordinates right?
    I put the midpoint was ( 3, 4.75)[/QU

    they gave the midpoint we had to work out Q or something i swear ?
    Aghh crap
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    This is all incorrect do NOT TRUST THIS PAGE WARNINGGGGG
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    (Original post by 34908seikj)
    7*10^8
    The question was (5 X 10^6) / (3.5 X 10^-3)
    So I did:
    5 X 3.5 = 17.5
    6 - -3 = 9 = 10^9
    17.5 X 10^9 = 1.75 X 10^10

    No?
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    (Original post by mayjunemayhem)
    What do you guys predict the grade boundaries will be like


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    difficult to say considering the fact that only 1 paper has been sat. however, if paper 2 is similar then 160-165 for A*


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    Please can someone put a link to the best mark scheme bc there's too many
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    [QUOTE=gcseexamz;65197123]
    (Original post by carolinrev)
    Aghh crap
    dont stress u still have another paper
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    what was question 5 again
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    (Original post by angelax)
    The question was (5 X 10^6) / (3.5 X 10^-3)
    So I did:
    5 X 3.5 = 17.5
    6 - -3 = 9 = 10^9
    17.5 X 10^9 = 1.75 X 10^10

    No?
    Incorrect

    its 3.5x10^-3 / 5x10^6
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    For the -0.4 and 4.4 question wouldn't it be the opposite, 0.4 and -4.4?
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    (Original post by angelax)
    The question was (5 X 10^6) / (3.5 X 10^-3)
    So I did:
    5 X 3.5 = 17.5
    6 - -3 = 9 = 10^9
    17.5 X 10^9 = 1.75 X 10^10

    No?
    no
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    does anyone know what answer the for probality tree was
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    (Original post by vrajpatel)
    Q1 750cm^3
    Q2 too vague and no timeframe
    The class is a small sample/biased
    Q3 p^7
    g^2
    k^6
    10-5m
    n(n-7)
    45
    90
    No not enough varnish cos she needs 50cm^2 but has 37.5cm^2
    60
    T=5x+20y
    (-3,-2)
    11 females
    100-25pi
    36%
    I compared median, IQR and range
    150
    7x10^8
    X<7
    7/5
    2 4/5 in mixed fraction form
    4/5
    x=-0.4 and 4.4
    X=-1.1 and 5.1
    X=-1.7 and 4.7
    Angle MST 69
    Probability is 0.04
    X=2&6
    a+b
    -a+3b
    3/4(a+b) for vector
    Point s is on both lines and it is point where they intersect
    100,25,4
    Final questions is (3-root6)/12
    I factorised the letter one (t=5x+20y) will i still get the mark if thats right??
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    (Original post by ewales)
    That was a tricky one, everyone at school seems to have different answers:
    Mine being (2 - root 6)/12.
    I got that too but I didn't think it was right. I could be wrong though...
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    (Original post by jamesM22)
    For the 36% answer question, what were the 3 marks for?
    I literally just wrote 30x1.2=36%


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