Turn on thread page Beta
    Offline

    21
    Prove that x+Square root(1-x) <= 5/4
    Offline

    22
    ReputationRep:
    (Original post by Mystery.)
    yes that's the type I meant. Like this question :https://www.imperial.ac.uk/media/imp...tions-2010.pdf
    Q3 I
    No, that's really not what I'm talking about, this is what algebraic geometry is: https://www.dpmms.cam.ac.uk/study/II...5-2016/HW1.pdf

    (Original post by RuairiMorrissey)
    I don't fully understand how you got that last term?
    Do you mean how I got u\int_{-1}^1 3x^2 \, \mathrm{d}x = 2u? If so: what's the value of \int_{-1}^1 3x^2 \, \mathrm{d}x.
    Offline

    3
    ReputationRep:
    (Original post by GrungeGirl)
    Can someone please explain to how to do this? It is from 2011, Q3.
    Attachment 589816
    Put the RHS under a common denominator i.e. 3b^2 -1 .
    Offline

    21
    Also How would you sketch the below? I did algebraic division and got 1-2/x^2-5x+6 and drew a parabola but when I put it into wolfram alpha it looks different

    ((x-1)(x-4))/((x-2)(x-3))

    (Original post by Zacken)
    No, that's really not what I'm talking about, this is what algebraic geometry is: https://www.dpmms.cam.ac.uk/study/II...5-2016/HW1.pdf

    ohh looks like fun.
    Offline

    21
    nevermind i got it
    Offline

    14
    ReputationRep:
    Edit: Also this;
    Spoiler:
    Show
    Name:  img052.jpg
Views: 131
Size:  283.1 KB


    Is this question correct, the mark scheme shows a different answer
    Spoiler:
    Show
    Name:  img051.jpg
Views: 114
Size:  433.0 KB
    Offline

    21
    I think I am being really stupid here but I tried to do a graph because the standard way doesn't work
    Attached Images
     
    Offline

    7
    ReputationRep:
    Could anyone explain q3 2013 pls. I dont understand the last two bits at all.
    https://www.maths.ox.ac.uk/system/fi...nts/test13.pdf
    Offline

    21
    stuck on part ii
    Attached Images
     
    Offline

    2
    ReputationRep:
    (Original post by Mystery.)
    stuck on part ii
    Lad are these MAT questions? where are you finding them?
    Offline

    21
    (Original post by joodaa)
    Lad are these MAT questions? where are you finding them?
    yeah man like 2000s
    Offline

    7
    ReputationRep:
    (Original post by Mystery.)
    stuck on part ii
    a^3x + a^-3x is a sum of cubes so equals (a^x + a^-x)(a^2x -1 + a^-2x)

    a^2x + a^-2x = 4y^2-2 which is just squaring a^x + a^-x = 2y

    so equals 2z=(2y)(4y^2-3) then just expand
    Offline

    7
    ReputationRep:
    (Original post by 11234)
    Could anyone explain q3 2013 pls. I dont understand the last two bits at all.
    https://www.maths.ox.ac.uk/system/fi...nts/test13.pdf
    pls help im so confused with this one
    Offline

    21
    (Original post by 11234)
    a^3x + a^-3x is a sum of cubes so equals (a^x + a^-x)(a^2x -1 + a^-2x)

    a^2x + a^-2x = 4y^2-2 which is just squaring a^x + a^-x = 2y

    so equals 2z=(2y)(4y^2-3) then just expand
    Thanks!
    What's the way to spot a sum of cubes ?
    Offline

    7
    ReputationRep:
    (Original post by Mystery.)
    Thanks!
    What's the way to spot a sum of cubes ?
    i just learnt the identities so x^3 + y^3 = (x+y)(x^2-xy+y^2)

    x^3-y^3= (x-y)(x^2 + xy + y^2)
    Offline

    7
    ReputationRep:
    (Original post by Mystery.)
    yeah man like 2000s
    i found that the old ones are much easier than the new ones
    Offline

    21
    (Original post by 11234)
    i found that the old ones are much easier than the new ones
    yeah they are.
    Offline

    21
    (Original post by 11234)
    pls help im so confused with this one
    if you look at part iii, the f(k)...=-f(2-k)... so it has been reflected in the x-axis
    then it also changes from (1+t) to (1-t) essentially this is a reflection the line x=1 because for example if you sub t=0 you get the same function so that is the axis of symmetry
    when you reflect or move a graph the area stays the same
    Offline

    2
    ReputationRep:
    I got it, I think anyway. Could you take a look at what I did please? Name:  1477511830443.jpg
Views: 121
Size:  38.3 KB
    Name:  1477511870316.jpg
Views: 73
Size:  35.1 KB

    Posted from TSR Mobile
    Offline

    14
    ReputationRep:
    (Original post by KloppOClock)
    Edit: Also this;
    Spoiler:
    Show
    Name:  img052.jpg
Views: 131
Size:  283.1 KB

    Is this question correct, the mark scheme shows a different answer
    Spoiler:
    Show
    Name:  img051.jpg
Views: 114
Size:  433.0 KB
    ..
 
 
 
Turn on thread page Beta
Updated: October 30, 2017
Poll
“Yanny” or “Laurel”

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.