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The Super Juicy CURRENT YEAR 11 (2012-13) THREAD Mark VI watch

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    (Original post by UncreativeJ)
    Haha...yeah! (But it was only humorous in Bengali )

    sooyt dek-ya fagol oy-gisla (Sylheti Bengali: "sweet saw crazy became")

    I see how it is...I'm from Beanibazar in that case
    Hahaha bengali is the funniest language ever. You can speak bengali but must provide translation below.

    Hahaha love your translation. I should do it like that now.

    Beanibazaar haha


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    (Original post by Jina)
    Are you saying i (personally) am incapable of beating the Chinese? -_- Fishy can fight for us but he doesn't like being bengali.


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    No, I'm saying that you couldn't beat the joint forces of budey and aurororororae!
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    Cya
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    (Original post by justinawe)
    Fine then

    \mathrm{Consider \ vertical \ motion}:

    s = ut + \frac{1}{2} at^2

    0 = 30t \sin 45^{\circ} + \frac{1}{2} (-9.81)(t^2)

    15t\sqrt{2} - 4.905t^2 = 0

    t(15\sqrt{2} -  4.905t) = 0

    t = 0, \ \dfrac{1000\sqrt{2}}{327}

    \mathrm{Reject} \ t=0 \ \mathrm{as \ looking \ for \ final \ time}.

    \mathrm{Consider \ horizontal \ motion}:

    s = ut + \frac{1}{2} at^2

    s = ( 30\cos 45^{\circ} ) \left(\dfrac{1000\sqrt{2}}{327} \right) + \frac{1}{2}(0) \left( \dfrac{1000\sqrt{2}}{327} \right)

    s = 91.7 \ \mathrm{m \ \ \ \ \ }  (\mathrm{3 \ s.f.})


    \mathrm{For \ max \ height}:

    \mathrm{Max \ s \ at} \ v=0;

    v^2 = u^2 + 2as

    0 = (30 \sin 45^{\circ})^2 + 2(-9.81)(s)

    s = 22.9 \ \mathrm{m \ \ \ \ \ }  (\mathrm{3 \ s.f.})


    :mmm:
    :rofl: people don't be scared, once you know the theory it's all good :yy:
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    (Original post by Vionar)
    No, I'm saying that you couldn't beat the joint forces of budey and aurororororae!
    Ahh such faith! Haha im sure I could... With fishy in the background.


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    (Original post by L'Evil Fish)
    :rofl: people don't be scared, once you know the theory it's all good :yy:
    LMAO. Was just about to say that's the reason behind nightmares.


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    (Original post by Jina)
    LMAO. Was just about to say that's the reason behind nightmares.


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    Haha, it's not bad at all
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    (Original post by L'Evil Fish)
    Haha, it's not bad at all
    You're just subbing in values and calculating stuff really :dontknow:
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    (Original post by Jina)
    Ahh such faith! Haha im sure I could... With fishy in the background.

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    Only with fishy, without him budey and aurororororae would win!
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    (Original post by justinawe)
    You're just subbing in values and calculating stuff really :dontknow:
    But they see suvat and think it's complex with the trig and quad and rejection of values!:dontknow:

    They'll see next year :mmm: you should show them something beautiful... :moon:
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    (Original post by Jina)
    Hahaha bengali is the funniest language ever. You can speak bengali but must provide translation below.

    Hahaha love your translation. I should do it like that now.

    Beanibazaar haha


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    Eela afne khoriyo (Translation: "This way you (respectable you) do")


    HEY! BEANIBAZAR IS COOL, MAN! xP

    I just google mapped it and Bishwanat is about 1 hour 30 mins from Beanibazar! That's close
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    (Original post by L'Evil Fish)
    But they see suvat and think it's complex with the trig and quad and rejection of values!:dontknow:

    They'll see next year :mmm: you should show them something beautiful... :moon:
    Something beautiful? I'm sure many here would love to see puke fly 92 metres across the room :mmm:

    Did you know the fact that 45 degrees is the optimal angle for max horizontal distance, or did you just make it up as part of the question?
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    Hello all

    I'm Gary and I'm currently in year 11, oh gosh, it's positively frightening that I've chosen all my AS subjects and will be going to 6th form in September :eek: I hope to study English Literature and Viking studies at university

    How is everyone? How have all your exams gone?
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    (Original post by justinawe)
    Something beautiful? I'm sure many here would love to see puke fly 92 metres across the room :mmm:

    Did you know the fact that 45 degrees is the optimal angle for max horizontal distance, or did you just make it up as part of the question?
    Something that'll scare them, perhaps a proof of reductions formula

    Yeah, I did. I was gonna say the angle of inclination allows for the optimum horizontal distance to be reached. But 45 degrees was so much easier :lol:
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    (Original post by L'Evil Fish)
    Something that'll scare them, perhaps a proof of reductions formula

    Yeah, I did. I was gonna say the angle of inclination allows for the optimum horizontal distance to be reached. But 45 degrees was so much easier :lol:
    I remember writing out a calculus proof that 45 degrees gave the furthest horizontal distance in class out of boredom :mmm:
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    (Original post by justinawe)
    Fine then

    Spoiler:
    Show
    \mathrm{Consider \ vertical \ motion}:

    s = ut + \frac{1}{2} at^2

    0 = 30t \sin 45^{\circ} + \frac{1}{2} (-9.81)(t^2)

    15t\sqrt{2} - 4.905t^2 = 0

    t(15\sqrt{2} -  4.905t) = 0

    t = 0, \ \dfrac{1000\sqrt{2}}{327}

    \mathrm{Reject} \ t=0 \ \mathrm{as \ looking \ for \ final \ time}.

    \mathrm{Consider \ horizontal \ motion}:

    s = ut + \frac{1}{2} at^2

    s = ( 30\cos 45^{\circ} ) \left(\dfrac{1000\sqrt{2}}{327} \right) + \frac{1}{2}(0) \left( \dfrac{1000\sqrt{2}}{327} \right)

    s = 91.7 \ \mathrm{m \ \ \ \ \ }  (\mathrm{3 \ s.f.})


    \mathrm{For \ max \ height}:

    \mathrm{Max \ s \ at} \ v=0;

    v^2 = u^2 + 2as

    0 = (30 \sin 45^{\circ})^2 + 2(-9.81)(s)

    s = 22.9 \ \mathrm{m \ \ \ \ \ }  (\mathrm{3 \ s.f.})



    :mmm:
    Eek! :eek: Oh my, what language is this? :cry2:

    (Original post by L'Evil Fish)
    Something that'll scare them, perhaps a proof of reductions formula

    Yeah, I did. I was gonna say the angle of inclination allows for the optimum horizontal distance to be reached. But 45 degrees was so much easier :lol:
    What's a reduction formula?
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    (Original post by justinawe)
    I remember writing out a calculus proof that 45 degrees gave the furthest horizontal distance in class out of boredom :mmm:
    :eek: how do you prove things like that?
    (Original post by Felix Felicis)
    Eek! :eek: Oh my, what language is this? :cry2:


    What's a reduction formula?
    :lol: very funny Felix.
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    Who watches anime?
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    (Original post by Felix Felicis)
    Hello all

    I'm Gary and I'm currently in year 11, oh gosh, it's positively frightening that I've chosen all my AS subjects and will be going to 6th form in September :eek: I hope to study English Literature and Viking studies at university

    How is everyone? How have all your exams gone?
    Very funny Felix. :unimpressed:


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    (Original post by Felix Felicis)
    Hello all

    I'm Gary and I'm currently in year 11, oh gosh, it's positively frightening that I've chosen all my AS subjects and will be going to 6th form in September :eek: I hope to study English Literature and Viking studies at university

    How is everyone? How have all your exams gone?
    Hey there Gary! I'm Ash. I overslept on the day where everyone was choosing their AS levels, and all the good courses - Physics, Chemistry, Biology were already fully booked by the time I got there! :eek: There was just one course left - Mathematics. They told me it would be a terrible idea to take it, I shouldn't touch the course with a barge pole! Far too unpredictable. They told me to come back next year. I really want to start my AS-levels this year, though What should I do?

    Spoiler:
    Show
    See what I did there?
 
 
 
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