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    (Original post by andersson)
    On a more serious note I'll try to remember all my calculation answers, can you guys tell me if you got the same/different? Thanks

    Current in length of wire test thing at 1.0m : 0.15 amps
    Next part about drawing a thinner wire result it on the graph: basically twice the gradient

    Skydiver: 56m/s speed, then 180m that he fell

    Speed of light in water: approximately 225 million m/s

    Resistors in parallel: 1/12th of an ohm

    Filling in logic circuit: ALL 0s

    Transformer: 46 turns on the primary coil, 1 turn on the secondary coil

    Section D

    I said Steve was wrong because I worked out the breaking distance increased by approximately 30% which is not double 34%

    I got about 30,000km before the tread wore down too much


    Tell me what you got guys
    Speed of light in water would be 2.25 x 10^8

    Transformer: Isn't it 230 turns on the coil and 5 on the secondary?
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    I got all 0s for the logic gates

    Did we have to use standard form notation for the speed of light in water?
    And what was the answer to the next part- glass?
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    (Original post by andersson)
    I did Vp/Vs = Np/Ns, and 230/5 was 46 over 1... Not sure if that was right

    yeah that makes sense hopefully you gain credit for using either calculation :L
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    (Original post by andersson)
    On a more serious note I'll try to remember all my calculation answers, can you guys tell me if you got the same/different? Thanks

    Current in length of wire test thing at 1.0m : 0.15 amps
    Next part about drawing a thinner wire result it on the graph: basically twice the gradient

    Skydiver: 56m/s speed, then 180m that he fell

    Speed of light in water: approximately 225 million m/s

    Resistors in parallel: 1/12th of an ohm

    Filling in logic circuit: ALL 0s

    Transformer: 46 turns on the primary coil, 1 turn on the secondary coil

    Section D

    I said Steve was wrong because I worked out the breaking distance increased by approximately 30% which is not double 34%

    I got about 30,000km before the tread wore down too much


    Tell me what you got guys
    Haha my teacher couldn't believe they put a cross word on there
    but anyways, yep I got 0.15, and then I drew my line extended to the end of the graph, is this ok or should I have stopped when their line stopped?
    I got 56m/s but somehow 36m lol! yep same for light, btw did you put arsenic glass as the part B answer? I got 12/13, and then 4 1/3 for my resistor answers however my logic circuit was 0010?
    yep Steve was wrong as it would've been 10metres too high if you doubled the previous percentage and yeah same, then for part B, I wrote its still dangerous lol!! Oh also what did everyone write for the small electrical components disadvantage? I put may get lost and expensive, is that ok?
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    For logic gates i got 0,0,0,0....was i wrong? :/


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    (Original post by IHTWFR)
    Speed of light in water would be 2.25 x 10^8

    Transformer: Isn't it 230 turns on the coil and 5 on the secondary?
    I used the formula VpIp=VsIs
    to work out the current in the secondary transformer, because they didn't give us the number of turns in the coil of wire but I could be wrong though :dontknow:
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    (Original post by BP_Tranquility)
    I got all 0s for the logic gates

    Did we have to use standard form notation for the speed of light in water?
    And what was the answer to the next part- glass?

    Yep


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    (Original post by NatashaG)
    yeah that makes sense hopefully you gain credit for using either calculation :L
    There was nothing to do with the number of turns on the coil...so that equation wouldn't work? It has to be VpIp= VsIs


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    (Original post by benwalters1996)
    For logic gates i got 0,0,0,0....was i wrong? :/


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    I got that too and so did a lot of my friends, i think its right
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    (Original post by dazzer19)
    W to the T to the F!

    the last 6 marker I was just sitting there like :O
    What was it on again?


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    (Original post by IHTWFR)
    Speed of light in water would be 2.25 x 10^8

    Transformer: Isn't it 230 turns on the coil and 5 on the secondary?
    No...that would be too hard-if you look back at old spec past papers they literally tell you the number of turns on each coil

    Therefore you needed to use VpIp = VsIs and i worked out Is, which is a high current which reduces the voltage induced across the secondary coil to 5v


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    (Original post by Jed_Singh)
    Aha, I'm sure you did great overall though, it is only a 2 mark question after all
    Thank you, I'm sure you did too!

    (Original post by IHTWFR)
    Speed of light in water would be 2.25 x 10^8

    Transformer: Isn't it 230 turns on the coil and 5 on the secondary?
    Yes, and that's the right ratio so yes,

    (Original post by BP_Tranquility)
    I got all 0s for the logic gates

    Did we have to use standard form notation for the speed of light in water?
    And what was the answer to the next part- glass?
    They asked for the answer in m/s and they didn't say whether to do it in standard form or not, so either way will get credit, but the answer was like 225 million.

    (Original post by NatashaG)
    yeah that makes sense hopefully you gain credit for using either calculation :L
    You should.

    (Original post by Zippyzazu)
    Haha my teacher couldn't believe they put a cross word on there
    but anyways, yep I got 0.15, and then I drew my line extended to the end of the graph, is this ok or should I have stopped when their line stopped?
    I got 56m/s but somehow 36m lol! yep same for light, btw did you put arsenic glass as the part B answer? I got 12/13, and then 4 1/3 for my resistor answers however my logic circuit was 0010?
    yep Steve was wrong as it would've been 10metres too high if you doubled the previous percentage and yeah same, then for part B, I wrote its still dangerous lol!! Oh also what did everyone write for the small electrical components disadvantage? I put may get lost and expensive, is that ok?
    Drawing it to the end of the graph is fine, it's what I did. It's probably what you're supposed to do too. I put the glass with trisulphate or trisulphide. The logic circuit was all 0s. It asked how it would be bad for the manufacturers, so I don't think getting lost would count. I put expensive and complex.

    (Original post by benwalters1996)
    For logic gates i got 0,0,0,0....was i wrong? :/


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    No, I think that was right.
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    What did everyone put for the bridge question? Route wise...


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    How is everyone managing to remember all the calculations they did..
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    What did everyone put for the bridge question? Route wise...


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    (Original post by Rubicon1)
    How is everyone managing to remember all the calculations they did..
    I can't :L


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    (Original post by benwalters1996)
    What did everyone put for the bridge question? Route wise...


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    I said it went through the diode in-between two of the top points then through the resistor. When it alternated to the other charge I said it went through the diode in-between the two of the bottom points then through the resistor.

    What did you put?
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    (Original post by benwalters1996)
    What was it on again?


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    Her mobile phone and transforming and loads of other shiz
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    (Original post by dazzer19)
    Her mobile phone and transforming and loads of other shiz
    That was the easiest one :/


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    (Original post by benwalters1996)
    What did everyone put for the bridge question? Route wise...


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    For the first one, I used the letters to indicate the journey of the current- I also stated it was a positive half cycle.

    For the second one, I did the same thing (in the opposite direction) but then mentioned it was during the negative half cycle.

    I didn't like the wording of the question so I'm not too sure if I did it correctly or not :rolleyes:
 
 
 
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