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    (Original post by Tajwar786)
    please someone help I am struggling to get head around the "log rules"

    It says log x-log y = log(x/y)

    then in the equation 2^x=10
    why x= (log 10 / log 2) NOT SAME AS x= Log 8???
    Log10 MINUS log2 would be equal to log5 as 5 is 10 divided by 2.

    But log10 DIVIDED by log2 is not equal to log8 or log5.

    The formula says that logx - logy = log(x/y) but that does NOT mean that logx/logy is log(x-y). It doesnt work that way around

    I really hope this has made sense and helped you for tomorrow. If any of it doesn't, just let me know best of luck for the exam
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    Does anyone have the 2015 c2 paper? would be much appreciated if you could link it
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    (Original post by ionic285)
    So exams tomorrow, How's everyones revision going?
    Anyone find any difficult questions/papers they want to share?
    Dont get divergence and convergence. Did jan 13 paper yesterday and said the sequence which approaches 0 is converge.
    While approaching infinity is diverge. I thought this was other way around?

    In a paper i did earlier, june 11, it had a sequence tend to 0, but it said it was diverging?
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    (Original post by Caedite eos)
    Does anyone have the 2015 c2 paper? would be much appreciated if you could link it
    Previous page, link called woodhouse or something like that
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    (Original post by zirak46)
    Dont get divergence and convergence. Did jan 13 paper yesterday and said the sequence which approaches 0 is converge.
    While approaching infinity is diverge. I thought this was other way around?

    In a paper i did earlier, june 11, it had a sequence tend to 0, but it said it was diverging?
    Ok thanks I'll do the paper now, I'll let you know if I figure it out.
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    (Original post by ionic285)
    So exams tomorrow, How's everyones revision going?
    Anyone find any difficult questions/papers they want to share?
    I dont get question 3.

    Ive got answer but i dont get how to the get the exact value.

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    (Original post by ionic285)
    So exams tomorrow, How's everyones revision going?
    Anyone find any difficult questions/papers they want to share?

    Few more questions i dont get..
    ques 2 part ii
    ques 12 part i A
    ques 10
    ques 11 part ii

    Would appreciate help
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    (Original post by zirak46)
    I dont get question 3.

    Ive got answer but i dont get how to the get the exact value.

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    Wouldn't you just use pythagoras to find the adjacent value, what answer does it give in the mark scheme?
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    (Original post by ionic285)
    Wouldn't you just use pythagoras to find the adjacent value, what answer does it give in the mark scheme?
    You smart.. you very smart

    Ahh didnt understand the ms, just did what you said and i got it right, thanks pal

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    Can someone explain part ii?
    Ive got two angles: 7/6pi and 11/6pi, but dont get what other mark is for? It mentions plus and minus pi/6.

    But i only got minus pi/6. Pretty confused

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    Hey guys, I really need help with this question:

    "Show that N satisfies the inequality

    N > (log10200007 - log107) / (log102)

    Hence find the least possible value of N"

    This is on the June 2010 paper, Q.12 (ii) (B.)

    Please help ASAP! I don't know how to do this, or even the method of how I would go about other questions like this!

    Thanks

    EDIT: Here's the link to the paper: http://www.mei.org.uk/files/papers/c210ju_ireg-2.pdf
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    7(2^n-1)>2000000
    2^n-1>2000000/7
    2^n>2000000/7+7/7
    2^n>2000007/7
    nlog2>log2000007-log7
    n>(log2000007-log7)/log2

    Tada!!
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    (Original post by zirak46)
    Can someone explain part ii?
    Ive got two angles: 7/6pi and 11/6pi, but dont get what other mark is for? It mentions plus and minus pi/6.

    But i only got minus pi/6. Pretty confused

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    The answers should be just 7/6pi and 11/6pi, can you tell me what paper it is so I can look at the mark scheme
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    (Original post by zirak46)
    Can someone explain part ii?
    Ive got two angles: 7/6pi and 11/6pi, but dont get what other mark is for? It mentions plus and minus pi/6.

    But i only got minus pi/6. Pretty confused

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    I just did this question. For me, to work out 7/6pi I did 2pi - 11/6pi to work out the distance between the 2 points, and got 1/6pi (which I then added to pi). It could be that but I'm not really sure, just guessing.
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    (Original post by ionic285)
    The answers should be just 7/6pi and 11/6pi, can you tell me what paper it is so I can look at the mark scheme
    June 13, ive got the 2 answers, i just dont get what the first mark is. It says plus/minus pi/6 but i only got minus pi over 6
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    Name:  ImageUploadedByStudent Room1465328681.961247.jpg
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Size:  125.9 KB Any one can help me with part c?


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    (Original post by zirak46)
    Few more questions i dont get..
    ques 2 part ii
    ques 12 part i A
    ques 10
    ques 11 part ii

    Would appreciate help
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    Part 10 i is -sin(angle) because you are adding 180 to the graph, which makes it negative.)
    T2 = Sin(angle) ,,,since your adding 360 the graph does not change.
    Draw the sin graph this really helps.
    Hope this was clear
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    (Original post by ShadowHz)
    Name:  ImageUploadedByStudent Room1465328681.961247.jpg
Views: 231
Size:  125.9 KB Any one can help me with part c?
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    Use pythag to find the y-displacement: a^2 = c^2 - b^2 = (13/2)^2 - 6^2 = 6.25
    so a = 2.5

    y coordinates of A and B are -1 -2.5 = -3.5 then just use circle equation to find the corresponding x coordinates
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    Ahhhhhhh!! My own fault for no revision over the holiday.... But I'm just gonna have to wing it tomorrow! Let's hope it's a nice paper, like the other two were!
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    (Original post by Skipper12345)
    Ahhhhhhh!! My own fault for no revision over the holiday.... But I'm just gonna have to wing it tomorrow! Let's hope it's a nice paper, like the other two were!
    But S1 was dreadful in my opinion..
 
 
 
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